Displaying 20 results from an estimated 7000 matches similar to: "error fitting coxph model"
2011 Apr 27
0
treatment of factors and errors in ridge() function with coxph
I am trying to fit a large Cox model with many predictors. Because
there are many predictors, I would like to use the ridge() function to
get penalized ml estimates for all coefficients. The problems are that:
1. When I include a factor (like race) in the ridge() function, dummy
variables are not created. The resulting model has a single
coefficient for the race variable, and I have
2011 Apr 21
1
passing a vector of variable names to the ... pairlist function argument
Hi,
I have a character vector that contains the names of several objects
that I would like to pass to a function (specifically, the ridge
function in the survival package, but cbind is a similar example).
I've been struggling with how to do this so that the object values get
interpreted by the function, rather than the object names.
For example,
x1 <- 1:4
x2 <- 2:5
x3 <-
2006 Dec 29
2
Survfit with a coxph object
I am fitting a coxph model on a large dataset (approx 100,000 patients), and
then trying to estimate the survival curves for several new patients based
on the coxph object using survfit. When I run coxph I get the coxph object
back fairly quickly however when I try to run survfit it does not come
back. I am wondering if their is a more efficient way to get predicted
survival curves from a coxph
2008 Jul 01
2
"Invalid object" error in boxplot
Hi,
I'm trying to make a boxplot with the data at the end of the message, and when I
try to execute the command
>boxplot(Diatoms) (or for any other field instead of "Diatoms")
I get the following error message:
Error in oldClass(stats) <- cl : adding class "factor" to an invalid object
Any advice would be much appreciated.
Thanks a lot,
Miriam
Date
2011 Oct 01
4
Is the output of survfit.coxph survival or baseline survival?
Dear all,
I am confused with the output of survfit.coxph.
Someone said that the survival given by summary(survfit.coxph) is the
baseline survival S_0, but some said that is the survival S=S_0^exp{beta*x}.
Which one is correct?
By the way, if I use "newdata=" in the survfit, does that mean the survival
is estimated by the value of covariates in the new data frame?
Thank you very much!
2009 Jul 13
0
adjusting survival using coxph
I have what I *think* should be a simple problem in R, and hope
someone might be able to help me.
I'm working with cancer survival data, and would like to calculate
adjusted survival figures based on the age of the patient and the
tumour classification. A friendly statistician told me I should use
Cox proportional hazards to do this, and I've made some progress with
using the
2012 Nov 27
4
Fitting and plotting a coxph with survfit, package(surv)
Hi Dear R-users
I have a database with 18000 observations and 20 variables. I am running
cox regression on five variables and trying to use survfit to plot the
survival based on a specific variable without success.
Lets say I have the following coxph:
>library(survival)
>fit <- coxph(Surv(futime, fustat) ~ age + rx, data = ovarian)
>fit
what I am trying to do is plot a survival
2009 Feb 25
3
survival::predict.coxph
Hi,
if I got it right then the survival-time we expect for a subject is the
integral over the specific survival-function of the subject from 0 to t_max.
If I have a trained cox-model and want to make a prediction of the
survival-time for a new subject I could use
survfit(coxmodel, newdata=newSubject) to estimate a new
survival-function which I have to integrate thereafter.
Actually I thought
2005 Jan 13
2
coxph() and intervening events
Hello!
I am using the coxph() function for counting process data. I want to
include an intervening event as one of my covariates. In order to do this
I have split the relevant observations in my data at the time of
intervention. But I have not found any way to "inform" coxph() of the id
of these observations. The result of this is that coxph() interprets the
split data as
2002 Jul 18
1
survfit on coxph object with weights
Hi,
I am working on a study where we need to predict individual survival
curves from a cox-model fit with sampling weights. In both R and Splus
the survfit.coxph code starts with
if(!is.null((object$call)$weights))
stop("Survfit cannot (yet) compute the result for a weighted model")
My question is does anyone have code to get the expected survival curve,
or even just the base
2011 Sep 23
1
p values in coxph()
Hi,
I'm interested in building a Cox PH model for survival modeling, using 2
covariates (x1 and x2). x1 represents a 'baseline' covariate, whereas x2
represents a 'new' covariate, and my goal is to figure out where x2 adds
significant predictive information over x1.
Ideally, I could get a p-value for doing this. Originally, I thought of
doing some kind of likelihood ratio
2006 Aug 21
1
interpreting coxph results
I am having trouble understanding results I'm getting back from coxph
doing a recurrent event analysis. I've included the model below and
the summary. In some cases, with minor variations, the Robust
variance and Wald tests are significant, but the individual
covariates may or may not be significant. My main question is: If
Wald and robust tests both take into account the
2009 Aug 19
2
Problem with predict.coxph
We occasionally utilize the coxph function in the survival library to fit multinomial logit models. (The breslow method produces the same likelihood function as the multinomial logit). We then utilize the predict function to create summary results for various combinations of covariates. For example:
2010 Nov 11
2
predict.coxph and predict.survreg
Dear all,
I'm struggling with predicting "expected time until death" for a coxph and
survreg model.
I have two datasets. Dataset 1 includes a certain number of people for which
I know a vector of covariates (age, gender, etc.) and their event times
(i.e., I know whether they have died and when if death occurred prior to the
end of the observation period). Dataset 2 includes another
2009 Jan 07
0
Frailty by strata interactions in coxph (or coxme)?
Hello,
I was hoping that someone could answer a few questions for me (the background is given below):
1) Can the coxph accept an interaction between a covariate and a frailty term
2) If so, is it possible to
a) test the model in which the covariate and the frailty appear as main terms using the penalized likelihood (for gaussian/t frailties)
b)augment model 1) by stratifying on the variable that
2010 Oct 27
2
coxph linear.predictors
I would like to be able to construct hazard rates (or unconditional death prob) for many subjects from a given survfit.
This will involve adjusting the ( n.event/n.risk)
with (coxph object )$linear.predictors
I must be having another silly day as I cannot reproduce the linear predictor:
fit <- coxph(Surv(futime, fustat) ~ age, data = ovarian)
fit$linear.predictors[1]
[1] 2.612756
2008 Oct 03
1
formula form of coxph
Dear R user,
I got a question when using the coxph function. I have 5 covariates x1, x2,
x3, x4, x5 and I want to write a function so that when given an indicator,
e.g., c(1,3,5), I can fit the model as
model=coxph(Surv(time, status)~x1+x3+x5). Any idea to play around the form
of formula?
Thank you very much!
Xing Yuan
University of Pittsburgh
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2006 Jul 11
1
Coxph
Dear all,
My question is:
In the Surv object you have two arguments, "time" and "event". I have
two events, namely withdrawn and success.
I use no event or status argument in "Surv" because all my objects "die"
in my data set.
Does coxph function calculate the coefficients correctly when you put no
"event" argument into the Surv object?
2003 Aug 04
1
coxph and frailty
Hi:
I have a few clarification questions about the elements returned by
the coxph function used in conjuction with a frailty term.
I create the following group variable:
group <- NULL
group[id<50] <- 1
group[id>=50 & id<100] <- 2
group[id>=100 & id<150] <- 3
group[id>=150 & id<200] <- 4
group[id>=200 & id<250] <- 5
group[id>=250
2012 Sep 03
2
Coxph not converging with continuous variable
The coxph function in R is not working for me when I use a continuous predictor in the model. Specifically, it fails to converge, even when bumping up the number of max iterations or setting reasonable initial values. The estimated Hazard ratio from the model is incorrect (verified by an AFT model). I've isolated it to the "x1" variable in the example below, which is log-normally