Displaying 20 results from an estimated 170 matches similar to: "correlation matrix between data from different files"
2013 Feb 17
1
RELENG_8: amdtemp module and newer CPUs not working. MFC?
Hello,
I'm running FreeBSD 8.3-stable on a machine with an AMD A8-5600K cpu.
tingo at kg-quiet$ uname -a
FreeBSD kg-quiet.kg4.no 8.3-STABLE FreeBSD 8.3-STABLE #2: Fri Jan 4 19:18:15 CET 2013
root at kg-quiet.kg4.no:/usr/obj/usr/src/sys/GENERIC amd64
tingo at kg-quiet$ dmesg | grep CPU | head -1
CPU: AMD A8-5600K APU with Radeon(tm) HD Graphics (3618.02-MHz K8-class CPU)
2006 Mar 08
1
RES: survival
Dear Thomas,
The head of my dataset
> head(wsuv)
parcel sp time censo treatment
species
1 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
2 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
3 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1 1
4 S8 Poecilanthe effusa ( Hub. ) Ducke. 1 1 1
2010 Jun 15
6
working with zoo time index ??
Hello
Where could I find examples on how to work with the time index in a
timeseries or zoo series?
Let say I've got this series
DATA
1990-01-01 10:00:00 0.900
1990-01-01 10:01:00 0.910
1990-01-01 10:03:00 0.905
1990-01-01 10:04:00 0.905
1990-01-01 10:05:00 0.890
.......................
2000-12-31 20:00:00 0.992
How do I make simple calculations such as ... ?
Calculate the
2006 Jul 06
1
PLS method
dear all,
I am a new comer to R and statistic. Now I have a little confuse about the
package pls.
I have to use 5 components to form a model. There are strong relationship
between some of the components, which leads to the changes of the sign of
each coeficeince, of course this is unwanted when using the normal
regression way. So I choose the way of PLS, which is good at solve this kind
of
2009 Jan 30
3
Matlab inv() and R solve() differences
I submit the following matrix to both MATLAB and R
x= 0.133 0.254 -0.214 0.116
0.254 0.623 -0.674 0.139
-0.214 -0.674 0.910 0.011
0.116 0.139 0.011 0.180
MATLAB's inv(x) provides the following
137.21 -50.68 -4.70 -46.42
-120.71 27.28 -8.94 62.19
-58.15 6.93 -7.89 36.94
8.35 11.17 10.42 -14.82
R's solve(x) provides:
261.94 116.22 150.92 -267.78
116.22 344.30 286.68
2012 Sep 06
2
merge a list of data frames
I have a list of data frames:
> str(data)
List of 4
$ :'data.frame': 700773 obs. of 3 variables:
..$ V1: chr [1:700773] "200130446465779" "200070050127778" "200030633708779" "200010587002779" ...
..$ V2: int [1:700773] 0 0 0 0 0 0 0 0 0 0 ...
..$ V3: num [1:700773] 1 1 1 1 1 ...
$ :'data.frame': 700773 obs. of 3 variables:
..$
2018 May 31
2
mysterious rounding digits output
Well pointed out, Jim!
It is infortunate that the documentation for options(digits=...)
does not mention that these are *significant digits* and not
*decimal places* (which is what Joshua seems to want):
"?digits?: controls the number of digits to print when
printing numeric values."
On the face of it, printing the value "0,517" of 'ccc' looks
like printing 4
2005 Feb 04
2
no. at risk in survfit()
Hi,
when I generated a survfit() object, I can get number
of patients at risk at various time points by using
summary():
fit<-survfit(Surv(time,status)~class,data=mtdata)
summary(fit)
class=1
time n.risk n.event survival std.err lower 95% CI
upper 95% CI
9.9 78 1 0.987 0.0127 0.963 1
41.5 77 1 0.974 0.0179 0.940 1
54.0 76
2012 Oct 28
5
Re-sizing qcow2 images
Hello All,
I am using Centos 6.3 with libvirt 0.910 and qemu-kvm 0.12
I had to resize a qcow2 disk, and came across several issues;
I used this command to resize the image:
sudo -i /usr/bin/qemu-img /var/lib/libvirt/images/mydisk.img resize
+100G . The disk is attached using virtio.
I then tried to use parted from within the guest to resize the partition.
The first problem was that the
2018 May 31
0
mysterious rounding digits output
>>>>> Ted Harding
>>>>> on Thu, 31 May 2018 07:10:32 +0100 writes:
> Well pointed out, Jim!
> It is infortunate that the documentation for options(digits=...)
> does not mention that these are *significant digits*
> and not *decimal places* (which is what Joshua seems to want):
Since R 3.4.0 the help on ?options *does* say
2018 May 31
0
mysterious rounding digits output
Hi Joshua,
Because there are no values in column ddd less than 1.
itemInfo[3,"ddd"]<-0.3645372
itemInfo
aaa bbb ccc ddd eee
skill 1.396 6.225 0.517 5.775 2.497
predict 1.326 5.230 0.462 5.116 -2.673
waiting 1.117 4.948 NA 0.365 NA
complex 1.237 4.170 0.220 4.713 5.642
novelty 1.054 4.005 0.442 4.260 2.076
creative 1.031 3.561 0.362 3.689
2008 Sep 05
1
Plot by column
Dear list,
I have the following matrix. How can I make the following plot?
1. The x-axis has index 1:7, and the first column is plotted against index 1, second against 2, and so on.
2. I want the points from the left upper conner including the antidiagonal to be plotted with col=2, and the rest with col=3
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,] 0.589 0.857 0.923 0.944 0.954 0.963
2010 Sep 15
1
optim with BFGS--what may lead to this, a strange thing happened
Dear R Users
on a self-written function for calculating maximum likelihood probability (plz
check function code at the bottom of this message), one value, wden, suddenly
jump to zero. detail info as following:
w[11]=2.14
lnw =2.37 2.90 3.76 ...
regw =1.96 1.77 1.82 ....
wden=0.182 0.178 0.179...
w[11]=2.14
lnw=2.37 2.90 3.76 ...
regw =1.96 1.77 1.82 ....
wden=0.182
2018 May 31
3
mysterious rounding digits output
R version 3.5.0 (2018-04-23) -- "Joy in Playing"
Platform: x86_64-pc-linux-gnu (64-bit)
options(digits=3)
itemInfo <- structure(list("aaa" = c(1.39633732316667, 1.32598263816667, 1.11658324066667, 1.23651072616667, 1.05368679983333, 1.03100737383333, 0.9630728395, 0.7483865045, 0.620086646166667, 0.5411017985, 0.496397607833333, 0.459528044666667, 0.427877047833333,
2008 Apr 11
1
Vegan dataframe not acting nicely
This is what my data looks like
DOC TOC TKN
RM119mFeb-06 1 2 3
RM61mFeb-06 2 4 6
I have this both in a .csv and .txt I have read this in with
read.csv("chemodr.csv", header=T)
and this is what I get
X dAmon DN.N Nitrite.N DOC OP P TKN TOC
1 RM215mFeb-06 0.000 0.1300 0.0000 2.5
2008 Mar 06
2
How to hold a value(Mean sq) with a string
Hi all:
Can someone advice me on how to hold the residuals
Mean sq value on a string
so it can be used in other calculations.
I was trying something like this:
Msquare<-dfr$Mean sq but fails..Thanks
dfr <- read.table(textConnection("percentQ
Efficiency
1.565 0.0125
1.94 0.0213
0.876 0.003736
1.027 0.006
1.536 0.0148
1.536 0.0162
2.607 0.02
1.456 0.0157
2.16 0.0103
2008 Feb 28
0
problem with the ltm package - 3PL model
Hi Xavier,
the reason you observe this feature is that in the 'constraint'
argument you should specify the values under the additive
parameterization, i.e., when in the second column of the matrix
supplied in 'constraint' you specify 2, then you need to provide the
easiness parameters (not the difficulty parameters) in the third
column. Check the Details section of ?tpm() and
2011 Nov 22
5
x, y for point of intersection
Hi everyone,
?
I am trying to get a point of intersection between a
polyline and a straight line ?.. and get the x and y coordinates of this point.
For exemplification consider this:
?
?
set.seed(123)
?
k1 <-rnorm(100, mean=1.77, sd=3.33)
?k1 <- sort(k1)
q1 <- rnorm(100, mean=2.37, sd=0.74)
q1 <- sort(q1, decreasing = TRUE)
plot(k1, q1, xlim <- c((min(k1)-5),
2007 Feb 25
2
RFA
Dear Sir in the following example,is the vector lmom a l-moment ratios
vector? What is meant by size = northCascades[,1]? And what are the values
in c(0.0104,0.0399,0.0405)?
Please help me I am unable to understand these from help manual.
Best Regards
AMINA
data(northCascades)
lmom <- c(1, 0.1103, 0.0279, 0.1366)
kappaParam <- kappalmom(lmom)
heterogeneity(500, 19, size =
2010 Jul 23
1
Survival analysis MLE gives NA or enormous standard errors
Hi,
I am trying to fit the following model:
sr.reg.s4.nore <- survreg(Surv(age_sym4,sym4), as.factor(lifedxm),
data=bip.surv)
Where age_sym4 is the age that a subject develops clinical thought
problems; sym4 is whether they develop clinical thoughts problems (0 or
1); and lifedxm is mother's diagnosis: BIPOLAR, MAJOR DEPRESSION, or
CONTROL.
I am interested in whether or not