Displaying 20 results from an estimated 500 matches similar to: "statistical contrasts on 3-way interaction"
2012 Jan 13
1
plotting regression line in with lattice
#Dear All, 
#I'm having a bit of a trouble here, please help me...
#I have this data
set.seed(4)
mydata <- data.frame(var = rnorm(100),
                     temp = rnorm(100),
                     subj = as.factor(rep(c(1:10),5)),
                     trt = rep(c("A","B"), 50))
#and this model that fits them
lm  <- lm(var ~ temp * subj, data = mydata)
#i want to
2007 Sep 15
1
Cannot get contrasts to work with aov.
I have been trying for hours now to perform an orthogonal contrast through an
ANOVA in R.   
I have done a two-factor factorial experiment, each factor having three
levels.  I converted this dataset to a dataframe with one factor with nine
treatments, as I couldn't work out what else to do.   
I have set up a matrix with the eight orthogonal contrasts that I wish to
perform, but despite
2007 Mar 14
1
How to transform matrices to ANOVA input datasets?
Hello, R experts,
I have a list called dataHP which has 30 elements (m1, m2, ..., m30).  
Each element is a 7x6 matrix holding yield data from two factors  
experimental design, with treatment in column, position in row. For  
instance, the element 20 is:
dataHP[[20]]
           col1     col2     col3      trt1     trt2    trt3
  [1,]     22.0     20.3     29.7      63.3     78.5    76.4
  [2,]   
2004 Aug 02
4
Standard errors from glm
Kia ora list members:
I'm having a little difficulty getting the correct standard errors from a glm.object (R 1.9.0 under Windows XP 5.1).  predict() will gives standard errors of the predicted values, but I am wanting the standard errors of the mean.
To clarify:
Assume I have a 4x3x2 factorial with 2 complete replications (i.e. 48 observations, I've appended a dummy set of data at the
2010 Aug 31
4
pasting together 2 character arrays
If possible I would like to combine two different character arrays in combinations
Array1 <- c("height","weight","age","sex")
Array2 <- c("trt0","trt1","trt2")
I would like to combine these two character vectors to end up with such ...
Array3
"height.trt0.trt1"
"height.trt0.trt2"
2005 Nov 03
4
nlme questions
Dear R users;
Ive got two questions concerning nlme library 3.1-65 (running on R 2.2.0 /
Win XP Pro). The first one is related to augPred function. Ive been working
with a nonlinear mixed model with no problems so far. However, when the
parameters of the model are specified in terms of some other covariates,
say treatment (i.e. phi1~trt1+trt2, etc) the augPred function give me the
following
2004 Jan 21
0
intervals in lme() and ill-defined models
There has been some recent discussion on this list about the value of using
intervals with lme() to check for whether a model is ill-defined. My
question is, what else can drive very large confidence intervals for the
variance components (or cause the error message "Error in
intervals.lme(Object) : Cannot get confidence intervals on var-cov
components: Non-positive definite approximate
2010 Oct 20
2
create a list fails
I can not understand why this fails
>
> faicoutput2 <- list(stuff21 = as.numeric(faicout$coefficients[2]),
+                      stuff31=as.numeric(faicout$coefficients[3]),
+                      stuff41=as.numeric(faicout$coefficients[4]),
+                      stuff32=(stuff21-stuff31),
+                      stuff42=(stuff21-stuff41),
+                     
2016 Jul 08
0
Help with nouveau driver
Thanks for the help so far, I have already solved the main problem,
but sadly it seems I can't find out the last step. I hope you can help
me there...
Here ist the important part: It is trying to load some nvidia module,
although i have already done apt-get purge nvidia*
[     4.636] (II) LoadModule: "glx"
[     4.638] (II) Loading /usr/lib/xorg/modules/extensions/libglx.so
[    
2012 Sep 07
2
metafor package: study level variation
Hello.  A quick question about incorporating variation due to study in the metafor package.  I'm working with a particular data set for meta-analysis where some studies have multiple measurements.  Others do not.  So, let's say the effect I'm looking at is response to two different kinds of drug treatment - let's call their effect sizes T1 and T2.  Some studies have multiple
2016 Jul 08
1
Help with nouveau driver
Thanks for the help so far, I have already solved the main problem,
but sadly it seems I can't find out the last step. I hope you can help
me there...
Here ist the important part: It is trying to load some nvidia module,
although i have already done apt-get purge nvidia*
[     4.636] (II) LoadModule: "glx"
[     4.638] (II) Loading /usr/lib/xorg/modules/extensions/libglx.so
[    
2009 Apr 01
1
Fwd: 'for Loop'
Hello,
 
A nice guy call Jun Shen was helping me out with this, but I require a bit more help. Below is my data set or list called 'test'. I'm trying to calculate the %RSD for each pair of index and keep it in cronological order if you can imagine a 3rd column with 'date' beside index.
 
    Result Index
1   0.2901    17
2   0.2928    17
3   0.2913    18
4   0.2893    18
5  
2006 Aug 29
0
how to contrast with factorial experiment
Hello, R experts,
If I understand Ted's anwser correctly, then I can not contrast the  
mean yields between sections 1-8 and 9-11 under "Trt" but I can  
contrast mean yields for sections 1-3 and 6-11 because there exists  
significant interaction between two factors  (Trt:section4,  
Trt:section5). Could I use the commands below to test
the difference between sections 1-3 and 6-11 ?
2008 Oct 15
2
Network meta-analysis, varConstPower in nlme
Dear Thomas Lumley, and R-help list members,
I have read your article "Network meta-analysis for indirect treatment
comparisons" (Statist Med, 2002) with great interest. I found it very
helpful that you included the R code to replicate your analysis;
however, I have had a problem replicating your example and wondered if
you are able to give me a hint. When I use the code from the
2006 Aug 24
1
how to constrast with factorial experiment
Hello, R users,
I have two factors (treat, section) anova design experiment where  
there are 3 replicates. The objective of the experiment is to test if  
there is significant difference of yield between top (section 9 to 11)  
and bottom (section 9 to 11) of the fruit tree under treatment. I  
found that there are interaction between two factors. I wonder if I  
can contrast means from levels of
2005 Dec 08
1
Operations on a list
Hello, Everyone,
I am sorry that my message got truncated.
I resend it again as below:
Hello, R Users,
I have a list (say listexp) of 10,000 elements, each of which consists of a
matrix (5X6). It likes:
$"a"
    trt1rep1    trt1rep2    trt2rep1    trt2rep2    ctlrep1    ctlrep2
[1,]   50        54         98         89            40         45
[2,]   60        65         76         79  
2009 Apr 29
3
2 way ANOVA with possible pseudoreplication
Hi,
I have an experiment with 2 independant factors which I have been trying to
analyse in R. The problem is that there are several data points recorded on
the same animal. However, no combination of treatments  is repeated on the
same animal. All possible combinations of treatments are done in a random
order with as many points as possible being done on 1 animal before moving
onto the next.
The
2005 Nov 02
0
Bugs/issues with model.tables() (PR#8275)
Based on what follows, the most favourable construction is that
the documentation, by failing to say that the function should be
used only for completely balanced designs, is deficient.  Even
for such designs, there is a bug that needs correction. The
discussion is lengthy because I think it important to document,
at least wrt effects and means, exactly what model.tables()
does.
My preference is
2005 Aug 18
1
R equivalent to `estimate' in SAS proc mixed
Example: I have the following model
    > model <- lmer(response ~ time * trt * bio + (time|id), data = dat)
    where time = time of observation
           trt = treatment group (0-no treatment / 1-treated)
           bio = biological factor (0-absent / 1-present)
and I would like to obtain an estimate (with standard error) of the change
in response over time for individuals in the
2004 Sep 03
0
ML vs. REML with gls()
Hello listmembers,
I've been thinking of using gls in the nlme package to test for serial 
correlation in my data set. I've simulated a sample data set and have 
found a large discrepancy in the results I get when using the default 
method REML vs. ML.
The data set involves a response that is measured twice a day (once for 
each level of a treatment factor). In my simulated data set, I