similar to: Problem building up ggplot graph in a loop.

Hi, I had a piece of code which looped over a decimal vector like this: for( i in where ){ thisdata <- subset(herde, herde$mlr >= i) # do stuff with thisdata.. } 'where' is a vector like seq(-1, 1, by=0.1) My problem was: 'nrow(thisdata)' in loop repetition 0.4 was different if 'where' was seq(-1, 1, by=0.1) than when 'where' was seq(-0.8, 1,

Hi, I was using Gviz package to create a boxplot. I understand that Gviz uses "panel.bwplot" to create the boxplot. Is there any way that I can remove the dashed line surrounding each pair of boxplots? Here is some sample code: ############# library(Gviz) thisdata <- matrix(sample(1:100,60),nrow=10,ncol=6) positions <- sample(1:100,6) limit1 <- min(positions)-1 limit2

Dear R-users, i encountered some problems when trying to adjust the line width of the axes and stripes in a plot created with ggplot2. I use the "barley" dataset of the lattice package to illustrate my problem: library(ggplot2) library(lattice) barley[["SD"]] <- 5 limits <- aes(ymax=barley$yield + barley$SD,ymin=barley$yield - barley$SD) p1 <-

The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g. datanames <- paste0("aa_", 2000:2007) datalist <- lapply(datanames, get) names(datalist) <- datanames col1 <- lapply(datalist, "[[", 1) colnum <- lapply(col1, as.numeric) (The 2nd

Hi! Thanks for the replies! I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix

Um, if you insist on doing it that way, at least use assign(varname, as.vector(get(varname))) -pd > On 4 Dec 2017, at 22:46 , Love Bohman <love.bohman at sociology.su.se> wrote: > > Hi! > Thanks for the replies! > I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The

:-) I don't insist on anything, I'm just struggling to learn a new language and partly a new way of thinking, and I really appreciate the corrections. I hope I someday will be able to handle lists in R as easy as I handle loops in Stata... Thanks again! Love -----Ursprungligt meddelande----- Fr?n: peter dalgaard [mailto:pdalgd at gmail.com] Skickat: den 4 december 2017 23:09 Till:

Hi again! I know you don't find loops evil (well, at least not diabolic :-) ). (After many hours googling I have realized that thinking about loops rather than lists is a newbie thing we Stata-users do, I just jokingly pointed it out). Anyway, I'm really happy that you try to teach me some R-manners. Since I still get questions about what the h**k I mean by my strange question, I sort it

By the way, R 'vectors' are not the equivalents of mathematical 'vectors'. In R, a vector is something that can have arbitrary length and which has no 'attributes', other than perhaps element names. Vectors can be numeric, character, complex, lists, etc. Functions, names, and NULL are not vectors. In my opinion, the typical data scientist will rarely find the R vector

Loops are not evil, and no-one in this thread said they are. But I believe your failure to provide a reproducible example is creating confusion, since you may be using words that mean one thing to you and something else to the readers here. ################################ # A reproducible example includes a tiny set of sample data # Since we cannot reproducibly refer to filenames (your

Hello. First, I'm thankful about your wonderful project. However, I have serious worries about the reliability of R. I found the next bug which I consider important because in my job everytime We work with datanames like next. Please see below: b=data.frame(matrix(1:9,ncol=3)) names(b)=c("q99","r88","s77") >b q99 r88 s77 1 1 4 7 2 2 5 8 3

Hi R-users! Being new to R, and a fairly advanced Stata-user, I guess part of my problem is that my mindset (and probably my language as well) is wrong. Anyway, I have what I guess is a rather simple problem, that I now without success spent days trying to solve. I have a bunch of datasets imported from Stata that is labelled aa_2000 aa_2001 aa_2002, etc. Each dataset is imported as a matrix, and

for the moment, I'm using: .onAttach <- function(libname, pkgname) { .bbg.db.conn <<- dbConnect(dbDriver("PostgreSQL"), user="blah","blah") } .onUnload <- function(libpath) { dbDisconnect(.bbg.db.conn) } which results in a hidden global variable in the global environment. I would prefer to make the assignment only in the package namespace.

Hello, I want to arrage the label according to my preference eg.. (va, vp, a, b, c) but don't know how to supress default ordering. Any suggestions? Please try the code below: n <- c("va", "vp", "a", "b", "c") p <- c(2, 2,1, 3,5) pm<- c(3,4,2,5,4) pn <- c(1,1,1,2,3) x<-data.frame(cbind(n,p,pm,pn)) library(ggplot2) qplot(x=n,

Hi, I've got a csv file with scores like this: 40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,32,38,40,20,40,26,40,30,40,5,5,13,12,40,40,3,33,29,23,2,24,9,15,4,21,16,5,26,8,8,18 40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,40,32,40,40,30,40,40,37,34,40,36,13,40,13,40,5,40,8,29,5,15,34,5,22,14,20

Dear helpers I want to use rpart several times in a loop to build a classification tree. My problem is that rpart needs a formula as argument and for that the variables need to have names and this doesn't happen in my case. Every iteration in the loop has a different dataset with several variables (ex. 38 or more) and so I can't type the names by hand every time. Is there any function

Hello, I'd like to sitch to a monochrome/bw color-palette for the filling of geom_bar-bars (produced via "qplot" as in the example below). Hours of googling didn't yield anything useful, so I thought, I'd just ask ... Thanks, Joh library(ggplot2) qplot(factor(cyl), data=mtcars, geom="bar", fill=factor(cyl))

Hi, i do have a dataframe representing data from a repeated experiment. PID is a subject identifier, Time are timepoints in an experiment which was repeated twice. For each subject and all three timepoints there are 2 sets of four values. df <- data.frame(PID = c(rep("A", 12), rep("B", 12), rep("C", 12)), Time = rep(c(0, 0, 0, 0, 30, 30, 30,

Dear useRs, I'm struggling with the new version of ggplot2. In the previous version I did something like this. But now this yield an error (object "fill" not found). library(ggplot2) dummy <- data.frame(x = rep(1:10, 4), group = gl(4, 10)) dummy$y <- dummy$x * rnorm(4)[dummy$group] + 5 * rnorm(4)[dummy$group] dummy$min <- dummy$y - 5 dummy$max <- dummy$y + 5 ggplot(data

Hi all, Is it possible to change the filling of the squares used to represent the colour legend in a bar plot with ggplot? in this example, fillings are raven black, I'd like them white. ggplot(diamonds, aes(clarity, colour = cut)) + geom_bar() Regards -- ------------- Benoit Boulinguiez Ph.D student Ecole de Chimie de Rennes (ENSCR) Bureau 1.20 Equipe CIP UMR CNRS 6226 "Sciences