Displaying 20 results from an estimated 3000 matches similar to: "function similar to ddply? + calculations based on previous row"
2012 Feb 20
1
apply with as function ifelse with 2 logical conditions
Hi all,
I have a question concerning using several conditions in an ifelse function
used as the function in apply.
I want to create a new value with the function ifelse ? object which can be
coerced to logical mode ?test[n,] >1 & test[n-1,]==0?
With n I mean the row. I don?t know how I could do this without a loop. I
want to avoid the usage of loops and was thinking about apply. This
2012 Feb 13
2
different way for a for loop for several columns?
Hi,
I have a question about repeating something for several columns. I
calculated a lot of values for different objects. The values are normally
calculated step-wise for every day for each object. With this obtained data
frame, I make further calculations. Here I have to calculate some things and
I have to take into account the years because I want a number for each year.
I do these first for one
2009 Jun 26
1
gradient fill of a grid.polygon
Dear list,
Following a recent enquiry, I've been playing with the idea of creating a
colour gradient for a polygon, using the Grid package. The idea is to draw a
number of stripes of different colours, using the grid.clip function. Below
is my current attempt at this,
library(grid)
rotate.polygon <- function(g, angle=0){ # utility function, works fine
matR <- matrix(c(cos(angle),
2010 Dec 06
3
[plyr] Question regarding ddply: use of .(as.name(varname)) and varname in ddply function
Dear R-Helpers:
I am using trying to use *ddply* to extract min and max of a particular
column in a data.frame. I am using two different forms of the function:
## var_name_to_split is a string -- something like "var1" which is the name
of a column in data.frame
ddply( df, .(as.name(var_name_to_split)), function(x) c(min(x[ , 3] , max(x[
, 3]))) ## fails with an error - case 1
ddply(
2010 Apr 07
1
unexpected behaviour with ddply and colwise
Hi,
I am confused by results from:
> ddply(aa, names(aa), colwise(sum))
I thought ddply was just calling colwise(sum)() with each column.
However ddply() returns a 13 x 5 result !!
The general result I expected is similar to that of apply() , or
using colwise(sum)() alone. Shouldn't ddply() produce the same ?
Thanks in advance for your help,
- Stuart Andrews
>
2011 Jun 21
4
ddply to count frequency of combinations
I have a dataframe df with two columns x and y. I want to count the number
of times a unique x, y combination occurs.
For example
x<- c(1,2,3,4,5,1,2,3,4)
y<- c(1,2,3,4,5,1,2,4,1)
df<-as.data.frame(cbind(x, y))
#what is the correct way to use ddply for this example?
ddply(df, c('x','y', summarize, ??)
#desired output -- format and order doesn't matter
# (x, y)
2011 May 11
3
ddply with mean and max...
I'm trying to use ddply to compute summary statistics for many variables
splitting on the variable site. however, it seems to work fine for mean() but
if i use max() or min() things fall apart. whats going on?
test.set<-data.frame(site=1:10,x=.Random.seed[1:100],y=rnorm(100))
means<-ddply(test.set,.(site),mean)
means
site x y
1 1 -97459496 -0.14826303
2
2009 Nov 19
1
ddply function nesting problems
While putting my R code into functions, I've encountered a ddply function nesting issue and need a bit of advice on the proper way to fix it.? I've tried several approahces, but neither worked and I need to have the ability to include the "cut", "range", and "fullseq" methods within ddply.? (For a bit of that explanation refer to
2011 Aug 24
3
ddply from plyr package - any alternatives?
Hello everyone,
I was asked to repost this again, sorry for any inconvenience.
I'm looking replacement for ddply function from plyr package.
Function allows to apply function by category stored in any column/columns.
Regular loops or lapplys slow down greatly because my unique combination
count exceeds 9000. Is there any available solution which allow me to apply
function by category?
2012 Jul 24
1
Function for ddply
Hello, all. I'm new to R and just beginning to learn to write functions. I
know I'm out of my depth posting here, and I'm sure my issue is mundane.
But here goes. I'm analyzing the American National Election Study (nes),
looking at mean values of a numeric dep_var (environ.therm) across values
of a factor (partyid3). I use ddply from plyr and wtd.mean from Hmisc. The
nes requires a
2012 May 29
2
a question about "by" and "ddply"
Hi all,
I have a data set (df, n=10 for the sake of simplicity here) where I have two continuous variables (age and weight) and I also have a grouping variable (group, with two levels). I want to run correlations for each group separately (kind of similar to "split file" in SPSS). I've been experimenting with different functions, and I was able to do this correctly using ddply
2012 May 05
1
Correct use of ddply with own function
Hi,
I am really confused how ddply work, so maybe you can help me.
I created a function that sorts a vector etc.
fn <- function(x){
x1 <- sort(x)
x2 <- seq(length(x))
x3 <- x2/max(x2)
df <- data.frame(x1,x2,x3)
df
}
Probably this is not the best form of the function, but at least it produces what I want (data to plot a cumulative count curve).
This function works on a
2010 Jun 01
1
data frame manipulation ddply
Dear group,
Here is my data frame:
futures <-
structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10",
"CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10",
"LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10",
"SUGAR NO.11 Jul/10", "SUGAR NO.11
2012 Mar 03
3
Using ddply within a function by argument transfer
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2011 Aug 23
3
ddply - how to transform df column "in place"
Dear R-users,
I am trying to get the plyr syntax right, without much success.
Given:
d<- data.frame(cbind(x=1,y=seq(20100801,20100830,1)))
names(d)<-c("first", "daterep")
d2<-d
# I can convert the daterep column in place the classic way:
d$daterep<-as.Date(strptime(d$daterep, format="%Y%m%d"))
# How to do it the plyr way?
ddply(d2,
2012 Sep 06
1
use of ddply() within function
Dear all,
I am encountering problems with the application of ddply within the body of a self-defined function.
The script is the following:
moncostcarmoto <- function(costtype){
costaux_result <- data.frame()
for (purp in PURPcount){for (per in PERcount){
costcarin =
2010 Sep 22
2
speeding up regressions using ddply
Hi,
I have a data set that I'd like to run logistic regressions on, using
ddply to speed up the computation of many models with different
combinations of variables. I would like to run regressions on every
unique two-variable combination in a portion of my data set, but I
can't quite figure out how to do using ddply. The data set looks like
this, with "status" as
2010 Feb 03
1
Calculating subsets "on the fly" with ddply
Hi,
[I sent this to the plyr mailing list (late) last night, but it seems
to be lost in the moderation queue, so here's a shot to the broadeR
community]
Apologies in advance for being more verbose than necessary, but I'm
not even sure how to ask this question in the context of plyr, so ...
here goes.
As meaningless as this might be to do with the `iris` data, the spirit
of it is what
2012 Apr 03
1
help in ddply
Hi
I've records like this
df=
x panel
4 1
93 2
21 3
83 4
75 1
87 2
87 3
78 4
50 1
76 2
86 3
65 4
84 1
40 2
39 3
26 4
i want to create histogram out of it . i want all the mid and count values
for panel wise
my code is
histoutput = ddply(df,.(df[2]),hist)
i'm not able to get the required result.
please help me
using for loop takes a lot of time if there are more records
-----
Thanks
2009 Aug 05
2
using ddply but preserving some of the outside data
I have a bit of a quandy. I'm working with a data set for which I
have sampled sites at a variety of dates. I want to use this data,
and get a running average of the sampled values for the current and
previous date.
I originally thought something like ddply would be ideal for this,
however, I cannot break up my data by date, and then apply a function
that requires information