similar to: Subset a datafram according to time

Hello all! I have a problem to extract values greater that for example 1820. I try this code: x[x[,1]>1820,]->x1 Please help me! Thank you! The data structure is: structure(c(2.576, 1.728, 3.434, 2.187, 1.928, 1.886, 1.2425, 1.23, 1.075, 1.1785, 1.186, 1.165, 1.732, 1.517, 1.4095, 1.074, 1.618, 1.677, 1.845, 1.594, 1.6655, 1.1605, 1.425, 1.099, 1.007, 1.1795, 1.3855, 1.4065, 1.138, 1.514,

Dear all, Does any one knows why should I get the following error message, when trying to do a simple data.frame?? DataF<-data.frame(Subject,BiomR,Spp,Capas,Litter,Herbs,LitterD,MaxCanH,DDifS p,DSSp,Slope, CanDens,NearestSp) Erro em data.frame(Subject, BiomR, Spp, Capas, Litter, Herbs, LitterD, : arguments imply differing number of rows: 202, 0 The data I am using

Dear R experts, I'm new to R. It seems to be a simple question but I just can't find a way to do it. Please help me. I have two data sets x and y as shown in the following. I want to compare the first two columns in x and y, find the matched ones and assign the relative value from column 2 of y to generate the third column of x. Any help wil be appreciated. Thanks. > x [,1]

Hi I have a table read from a mysql database which is of the kind clusterid clockrate I obtained this table in R as clockrates_table <-sqlQuery(channel,"select...."); I have a function within which I wish to extract the clusterid for a given cluster. Although I know that there is just one row per clusterid in the data frame, I am using subset to extract the clockrate. clockrate =

I have a data frame with 1 factor, one date, and 37 numeric values: str(waterchem) 'data.frame': 3525 obs. of 39 variables: site : Factor w/ 64 levels "D-1","D-2","D-3",..: 1 1 1 1 1 ... $ sampdate : Date, format: "2007-12-12" "2008-03-15" ... $ CO3 : num 1 1 6.7 1 1 1 1 1 1 1 ... $ HCO3 : num 231 228 118 246

Hi expeRts, I would like to calculate weighted mean by two factors. My code is as follows: R> tmp <- by(re$meta.sales.lkm[, c("pc", "sales")], re$meta.sales.lkm[, c("size", "yr")], function(x) weighted.mean(x[,1], x[,2])) The result is as follows: R> tmp size: micro yr: 1994 [1] 1.090

I am trying to set up a function which processes my data according to the following rules: 1. if (x[i]==0) NA 2. if (x[i]>0) log(x[i]/(number of consecutive zeros immediately preceding it +1)) The data this will apply to include a variety of whole numbers not limited to 1 & 0, a number of which may appear consecutively and not separated by zeros. Below is an example with a detailed

Hello I am using R 2.2.0 with Windows XP. I've got a five element list object, each element containing two dataframes of equivalent size. > str(mylist) List of 1 $ data1:List of 2 ..$ data1a :`data.frame': 77 obs. of 63 variables: .. ..$ var1 : num [1:77] 0.41375 0.00056 1.43040 1.43528 0.61730 ... .. ..$ var2 : num [1:77] 1.154 1.686 0.673 0.800 0.760 ... ..

Hi all, As you can see from below, the result is strange... I would imagined that the bb result should be much higher and close to 1, any way to improve the fit? Any other classification methods? Thank you! data=data.frame(y=rep(c(0, 1), times=100), x=1:200) aa=glm(y~x, data=data, family=binomial(link="logit")) newdata=data.frame(x=6, y=100) bb=predict(aa, newdata=newdata,

Hola que tal alguien de ustedes me podría auxiliar, lo que pasa es que estoy tratando de hacer un programa en R utilizando la siguiente tabla: x<1 km x>1km Estabilidad a c d f c d f A 213 440.8 1.94 9.27 459.70 2.094 -9.6 B 156 106.6 1.15 3.30 108.20 1.098 2.0 C 104 61.0 0.91 0.00 61.00 0.911 0.0 D 68 33.2 0.73 -1.70 44.50 0.516 -13.0 E 51 22.8 0.68 -1.30 55.40 0.305

Hi I have measured the UV absorbance (abs) of 10 solutions of a substance at known concentrations (conc) and have used a linear model to plot a calibration graph with confidence limits. I now want to predict the concentration of solutions with UV absorbance results given in the new.abs data.frame, however predict.lm only appears to work for new "conc" variables not new "abs"

Hi, Not sure if this anyone else is interested in this but to me it seems to make sense to use different control session multiplexer sockets for bulk and interactive workloads. Index: auth.c =================================================================== RCS file: /cvs/src/usr.bin/ssh/auth.c,v retrieving revision 1.94 diff -u -p -r1.94 auth.c --- auth.c 23 May 2011 03:33:38 -0000 1.94 +++

. wine has the biggest issue with my programs that require a file opened.Ie porgram failed becuase cant open log file or can't find mfc42.dll . do i need to change media permissions ? I was told i could point wine to use xp's api and dlls how would i do that? mc

I am having trouble locating webvmail on my * server. Is this a seprate porgram or does it come with *. I am running version asterick*CLI> show version Asterisk CVS-03/26/04-17:08:20 built by root@localhost.localdomain on a i686 running Linux asterick*CLI> Thanks Kurt __________________________________ Do you Yahoo!? Yahoo! Photos: High-quality 4x6 digital prints for 25¢

Hi: I need help with geom_text(). I would like to count the number of Locations and put the sum of it right above each bar. x <- "Location Lake_dens Fish Pred Lake1 1.132 1 0.115 Lake1 0.627 1 0.148 Lake1 1.324 1 0.104 Lake1 1.265 1 0.107 Lake2 1.074 0 0.096 Lake2 0.851 0 0.108 Lake2 1.098 0 0.095 Lake2 0.418 0 0.135 Lake2 1.256 1 0.088 Lake2 0.554 1 0.126 Lake2 1.247 1 0.088

Hello, I'm trying to figure out the proper way of passing parameters to my program that is being run by WINE. I've been trying different things I've found in Google, but none have seemed to work yet. The parameters work in a Windows environment, so I do believe the program is okay. This is on a SUSE/SLES 9 machine using WINE .917. If I want to pass the parameter

Motivation: during each iteration, my code needs to collect tabular data (and use it only during that iteration), but the rows of data may vary. I thought I would speed it up by preinitializing the matrix that collects the data with zeros to what I know to be the maximum number of rows. I was surprised by what I found... # set up (not the puzzling part) x<-matrix(runif(20),nrow=4);

Hello all! I have a problem with R. I try to merge data like this: structure(c(2.1785, 1.868, 2.1855, 2.5175, 2.025, 2.435, 1.809, 1.628, 1.327, 1.3485, 1.4335, 2.052, 2.2465, 2.151, 1.7945, 1.79, 1.6055, 1.616, 1.633, 1.665, 2.002, 2.152, 1.736, 1.7985, 1.9155, 1.7135, 1.548, 1.568, 1.713, 2.079, 1.875, 2.12, 2.072, 1.906, 1.4645, 1.3025, 1.407, 1.5445, 1.437, 1.463, 1.5235, 1.609, 1.738, 1.478,

Hi All I have a datafram which looks like this : CustomerID DietType 1 a 1 c 1 b 2 f 2 a 3 j 4 c 4 c 4 f And I would like to reshape this so I can

Hi, Has anybody produced diffs for openssh-2.3.0p1 for the rsa keyexchange problem that Core-SDI described ? ( I noticed that fix is already in openbsd tree ). -Jarno -- Jarno Huuskonen - System Administrator | Jarno.Huuskonen at uku.fi University of Kuopio - Computer Center | Work: +358 17 162822 PO BOX 1627, 70211 Kuopio, Finland | Mobile: +358 40 5388169