similar to: 'deparse(substitute'))' then 'assign' in a S4 methods

Dear R community, I have a question on how R manages memory allocation in .Fortran() calls under Windows. In brief, apparently, it is not possible to allocate large matrices inside a Fortran subroutine unless you pass them as arguments. If you do not act in this way RGUI crashes with a stack overflow error and acting on memory through vsize nsize ppsize and memory.limit does not help at all.

Hi the list, I am writing a package in S4 and I do not manage to understand a bug. The "R CMD check" and the "R CMD build" both work. Here is links to the package (not on CRAN yet for the raison that I explain bellow): http://christophe.genolini.free.fr/aTelecharger/kml_0.5.zip http://christophe.genolini.free.fr/aTelecharger/kml_0.5.tar.gz Then I install the package and I

Hello, I discussed the following problem on the great useR conference with several people and wonder if someone of you knows a more elegant (or more common ?) solution than the one below. The problem: ============ I have several sets of interrelated functions which should be compared. The functions themselves have different structure, application-specific names (for readability) and they should

Hi. I am having difficulty following section 1.6.6 of the R-extensions manual. I am trying to update the Brobdingnag package to include a NAMESPACE file (the untb package requires the Brobdingnag package). Without the NAMESPACE file, the package passes R CMD check cleanly. However, if I include a NAMESPACE file, even an empty one, R CMD check gives the following error in 00install.out:

Hi, I'm writing a function that needs the input names (as characterstrings) as part of the output. With deparse(substitute( ) ) that works fine, until I replace all zeros with 0.001 (log is calculated at some time): tf <- function(input) { input[input==0] <- 0.001 ; deparse(substitute(input)) } myguess <- 42 tf(myguess) # not "myguess", but "42" Now when

In R code, "deparse(substitute(arg))" is the usual way to construct a label for an argument. Is there an equivalent to this in C code working on an SEXP, inside a function called by .Internal()? Duncan Murdoch

On 09 Jan 2017, at 10:53 , Spencer Graves <spencer.graves at prodsyse.com> wrote: > # Define an object of class 'dum' > k <- 1 > class(k) <- 'dum' > str(k) # as expected > > # Define print.dum > print.dum <- function(x, ...) > deparse(substitute(x)) > > print(k) # Prints "k" as expected > #####**** THE FOLLOWING PRINTS

On 07/05/2017 3:56 PM, Spencer Graves wrote: > In an implied call to an S3 print method, deparse(substitute(x)) returns > "x", regardless of the name of object in .GlobalEnv, as indicated in the > following: > > > > Xnamed <- 1 > > class(Xnamed) <- 'name.x' > > print.name.x <- function(x, ...){ > + namex <-

Dear list, can someone explain to me why deparse(substitute(x)) does not seem to work when x is of a user-defined S3 class? In my actual problem, my print method is part of a package, and the method is registered in the NAMESPACE, if that should make a difference. > print.testclass <- function(x,...){ xname <- deparse(substitute(x)) cat("Your object name

Dear List, I have the following function: coca <- function(x, ...) { if(is.null(class(x))) class(x) <- data.class(x) UseMethod("coca", x) } and a default method coca.default <- function(x, y, method = c("predictive", "symmetric"), reg.method = c("simpls", "eigen"), weights = NULL,

Dear R helpers: I like to apply deparse(substitute()) on multiple arguments to collect the names of the arguments into a character vector. I used function test.fun as below. it works when there is only one input argument. but it does not work for multiple arguements. can someone kindly help? test.fun <- function(...){deparse(substitute(...))} test.fun(x) #this works test.fun(x,y,z) # I like

Hello everyone, I encountered the following confusing behavior of 'deparse' and 'substitute' while programming with S4 classes (see example below). It seems like the presence of '...' argument in the definition of the generic generates the problem. I have no clue why, can anyone explain that to me? Are there any "workarounds"? Thanks a lot for your time!

Hi, Peter et al.: On 2017-01-09 4:24 AM, peter dalgaard wrote: > On 09 Jan 2017, at 10:53 , Spencer Graves <spencer.graves at prodsyse.com> wrote: > >> # Define an object of class 'dum' >> k <- 1 >> class(k) <- 'dum' >> str(k) # as expected >> >> # Define print.dum >> print.dum <- function(x, ...) >>

Hi, All: I'm having trouble getting deparse(substitute(x)) inside print.generic to consistently I'm having trouble getting a print.something to work consistently. Consider the following toy example: # Define an object of class 'dum' k <- 1 class(k) <- 'dum' str(k) # as expected # Define print.dum print.dum <- function(x, ...)

I would like to define a function at run-time, but I just can't make it work (please don't question why I want to do this, because that would be too much to explain). For example, I want to define the the following function foo <- function(x) { cat("Function", "foo", "was called with argument", x, ".\n") } However, I would like to

In an implied call to an S3 print method, deparse(substitute(x)) returns "x", regardless of the name of object in .GlobalEnv, as indicated in the following: > Xnamed <- 1 > class(Xnamed) <- 'name.x' > print.name.x <- function(x, ...){ + namex <- deparse(substitute(x)) + cat('How can I get the name of x in .GlobalEnv?\n', +

Hi all, I am experiencing the following quite strange (at least in my knowledge) problem in a simple function like the following: fn<-function(y,v=2){ n<-length(y) y<-y[(v+1):(n-v)] plot(y,type="l",lty=3,xlab="Time",ylab=deparse(substitute(y))) } fn(rnorm(50)) #look at the plot!!! The plot appears with numbers on the left side! If I delete the

I see that plot.default uses deparse(substitute(x)) to extract the character name of an argument and put it on the vertical axis. Hence: foo <- 1:10 plot( foo ) will put the label "foo" on the vertical axis. However, for a function that takes a "..." list as an input, I can only extract the first argument name: x <- 1:10 y <- 10:20 foo <- function(...) {

Hi R version 2.4.0 alpha (2006-09-06 r39158) MacOSX 10.4.7 There was a thread some time ago as to whether the structure created by package.skeleton() would pass R CMD check. I have an example where package.skeleton() gives an R file that gives an error when sourced. If I type setClass("brob", representation = representation

Dear list, When calling R from C, what appears like a spurious error can be triggered during the execution of chisq.test(x, y). This is happening when the following conditions are met: - x and y are "anonymous" C-level R vectors (they do not have a symbol), but they are protected from garbage collection - x and y are "not too small" (it was experienced as soon as they are