similar to: how to plot several curves in the same frame

Hello, I created a data.frame which contains two columns: df$P (Power) et df$DateTime (time). I'd like to add a new column df$diffP (difference of Power between T and T-2). I made a loop : for (i in 3:length(df$DateTime)){ df$diffP[i] = df$P[i] - df$P[i-2] } execution time result is unaceptable: 24s !! Is there any way to reduce complexity about O(n) ? for example 2 or 3s (10s maxi)

Hi, I have to debug my program. When I execute my function (in debug mode), I have got an error but I do not know which line is concerned. I do not want to do an infinite "Browse[2]>n with each line in my function... THanks for your help, ikuzar -- View this message in context: http://r.789695.n4.nabble.com/basic-debugging-tp4371113p4371113.html Sent from the R help mailing list

Hi, Does anybody know why get I this kind of strange situation: Browse[2]> hcEnd [1] "2009-03-29 06:30:00" Browse[2]> class(hcEnd) [1] "POSIXlt" "POSIXt" Browse[2]> is.na(hcEnd) [1] TRUE This issue is the source of my all issues in my program, Thanks for your help -- View this message in context:

Hi, I 'd like to know how to retrieve a column name of a data frame. For instance : df = data.frame(c1=c('a','b'),c2=c(1,2)) > df c1 c2 1 a 1 2 b 2 I would like to retrieve the column name which value is 2 (here, the column is c2) thanks for your help -- View this message in context:

Hello, RStudio displays errors in french . I'd like to change it in english Please help, Thanks -- View this message in context: http://r.789695.n4.nabble.com/RStudio-how-to-change-language-from-fr-french-to-eng-english-tp4424972p4424972.html Sent from the R help mailing list archive at Nabble.com.

Hi everybody, I want to use macro in my R code. But defmacro was not in my libraries. So I installed it : > install.packages("gtools") Installing package(s) into ?C:/Program Files/R/R-2.13.2/library? (as ?lib? is unspecified) essai de l'URL 'http://cran.cict.fr/bin/windows/contrib/2.13/gtools_2.6.2.zip' Content type 'application/zip' length 102500 bytes (100 Kb)

Hi, I'd like to know if there is an equivalent for #ifdef (Clangage) in R. I 'd like to do something like: useDebug = defmacro(DEBUG, expr=(DEBUG==1)) if(useDebug(0)){ #Here I do not use debug mode make_addition = function(a, b) { c=a+b plot(c) return(c) } }else{ #here I use debug mode c=a+b } I assume this would work... The problem is : if

Hi, I'd like to debug in a loop (using debug() and browser() etc but not print() ). I'am looking for the first occurence of NA. For instance: tab = c(1:300) tab[250] = NA len = length(tab) for (i in 1:len){ if(i != len){ tab[i] = tab[i]+tab[i+1] } } I do not want to do "Browse[2]> n" for each step ... I'd like to declare a "browser()" in the loop

Hi, I'd like to plot a point: plot(1,2) I use RStudio. I'd like to know how to specify the length of Oy axis. I 'd like to put 20 as length of Oy but , by default, I 've got 2.5. Thanks for your help -- View this message in context: http://r.789695.n4.nabble.com/how-to-specify-the-Oy-axis-length-tp4372937p4372937.html Sent from the R help mailing list archive at Nabble.com.

Hi, I 'd like to know how to extract an interval of "hour:minute" type from a column of POSIXlt POSIXct type. For instance: my_data.csv: 4352;2011-09-02 21:30:00;3242; 4352;2011-09-02 21:31:00;3315; 4352;2011-09-02 21:32:00;4241; 4352;2011-09-02 21:33:00;5394; ... 4352;2011-09-02 01:02:00;67; 4352;2011-09-02 01:03:00;67; 4352;2011-09-02 01:04:00;67; .... I loaded

Hello, I'd like to classify data with kmeans algorithm. In my case, I should get 2 clusters in output. Here is my data colCandInd colCandMed 1 82 2950.5 2 83 1831.5 3 1192 2899.0 4 1193 2103.5 The first cluster is the two first lines the 2nd cluster is the two last lines Here is the code: x = colCandList$colCandInd y = colCandList$colCandMed m = matrix(c(x, y),

Hello, I have got a data frame df like this : > df e1 e2 e3 e4 1 1 11 1 21 2 2 12 2 22 3 3 13 3 23 4 4 14 4 24 5 5 15 5 25 6 6 16 6 26 7 7 17 7 27 8 8 18 8 28 9 9 19 9 29 10 10 20 10 30 where e1 ... e3 are vectors I have to select columns which median is in the interval [5;6] ( Here, for instance, e1 and e3) I would not want to use loop... (for, while) I search

Hello, I 'd like to use some functions in myLib. So I do: library(myLib) Then I get this message: Error: package 'myLib' is not installed for 'arch=i386' > sessionInfo() R version 2.13.2 (2011-09-30) Platform: i386-pc-mingw32/i386 (32-bit) locale: [1] LC_COLLATE=French_France.1252 LC_CTYPE=French_France.1252 LC_MONETARY=French_France.1252 LC_NUMERIC=C

Hi I recall running across a function a while back which would return information about running processes (such as their cpu and memory usage), but I cannot seem to locate it. Wondering if someone would be kind enough to refresh my memory. I vaguely recall it was parsing the output of the 'ps' command. Thanks, Ben

Not sure where to even start on this.... I'm hoping there's some debugging I can do... I have a loop that cycles through several different data sets (same structure, different info), performing randomForest growth and predictions... saving out the predictions for later study... I get about 5 hours in (9%... of the planned iterations.. yikes!) and R just freezes. This happens in

Hi all; I want to print system.time whenever I execute any command. It takes too much time to type "system.time()" function to all command. is there any solution on it? And, apply(matrix,1,cumsum) command is too slow to some large matrix. is there any function like rowCumSums ? thank u! -- View this message in context:

Hi, I'd like to know how to get a vector of min value from many vectors without making a loop. For example : >v1 = c( 1, 2, 3) > v2 = c( 2, 3, 4) > v3 = c(3, 4, 5) > df = data.frame(v1, v2, v3) > df v1 v2 v3 1 1 2 3 2 2 3 4 3 3 4 5 > min_vect = min(df) > min_vect [1] 1 I 'd like to get min_vect = (1, 2, 3), where 1 is the min of v1, 2 is the min of v2

Hi, I 'd like to select the Date where myvalue =1800 appears the* first time*. For instance: df =data.frame(date, myvalue, ...) ... Date myvalue 2012-01-05 2500 2012-01-06 2450 *2012-01-07 1800* 2012-01-08 2200 2012-01-09 1800 I'd like to retrieve the third line. I do

I'm trying to use the rsync algorithm for incremental backups. After a quick look at rsync I saw the batch mode operations, and I thought that maybe I can modify them for incremental backups. What is needed is to add an option to save the checksums of all the files of the level 0 backup and a second option to use the level n checksum to calculate the delta batch files for the level n+1

1) how to modify the the tickment of x-axis or y-axis. boxplot(data[,1:5]) the tickment in x-axis in V1 V2 V3 V4 V5 ,I want to be some name for example name<-c("1day","2day","3day","4day","5day") 2) how to overlap two plot into one figure? plot(data[1:5]) boxplot(newdata[,1:5]) ? -- TANG Jie [[alternative HTML version deleted]]