similar to: conversion of string

I have some time data and which is in seconds time <-c( 126230400 126252000 126273600 126295200 126316800 126338400) now I wanted to convert this time to Y M D H M S format I have tried following codes but it does not give me the out put in Y M D H M S time_t1 <- as.POSIXlt(time, origin="2005-01-01", tz="GMT") & time_f <- as.POSIXct(time,

Hi, Recently I have installed R version 2.14.1, after installation I am trying to install some packages and I get error message. even I tried install.packages("Rcmdr") but still I am unable to fix this problem. I would be very grateful if somebody can help me to fix this problem. install.packages("hdf5") Installing package(s) into

I have 100 data files, which contains very huge data sets of location details ( e.g latitude, longitude, time, temp) Now I would like to save the all data of these 100 files in r object, so I can reload data any time. * Every file has different length of data latitude <- NULL longitude <- NULL time <- NULL temp <- NULL for ( i in 1:100) { data<-

I got two .RData file e.g data.2005.RData & data.2006.RData I would like to combine these two different data set and make single RData file. in both file there are some NULL files are also available and I would like to clear this NULL files also. $ : NULL $ : NULL $ : num [1:43285, 1:8] -21.1 -21.1 -24.9 -24.9 -24.9 ... ..- attr(*, "dimnames")=List of 2 .. ..$ : NULL ..

I would like to plat some spaghetti plots from my data , ma data is as follows ak[1:3,] [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301 0.9088819 0.9326736 [2,] 0.3159234 0.4071270 0.5579212 0.6844584 0.7684690 0.8243702 0.8677043 0.8931288 0.9261926 [3,] 0.3075260 0.3993699

I have two different datasets 1) is in monthly format (obs) 2) yearly format (model) in obs I have 84 files ( 2003:2009)for different months & in model I have 4 different files which has yearly data (2005:2008) So for calculating my requirement I need these both data sets. The sample calculations are as follows file_o<-list.files(path=' ', pattern="0.2.text") #

________________________________ From: Uday Mhatre<mailto:uday_mhatre at hotmail.com> Sent: ?05-?12-?2014 12:58 To: Andrea Venturoli<mailto:ml at netfence.it> Subject: RE: [Samba] samba 2.2.7a tech issue Just wondering if these samba versions are backward compatible with fedora14 and other Linux distributions. Regards, Uday ________________________________ From: Uday

Hi, all. I'm trying to create a plot that has a range of about an hour on the x axis, starting at about 10:15. I have a way I'm currently doing it but it's not working. this is what I want on the x axis: | | | | | | | | | | ---------------------------------------------- 10:15 10:25 10:35 10:45 10:55 11:05 11:15 what's the best way to plot this out like this? currently,

I have some data set which is available from 2005-2010 . I would like plot monthly maps out of it. So how I should write loop that can plot this yearly data to for every month and write title for individual months too. -- View this message in context: http://r.789695.n4.nabble.com/Plotting-monthly-maps-from-yearly-data-tp4391704p4391704.html Sent from the R help mailing list archive at

I would like to calculate vector from existing value e.g v <- 1000 s <- 30 d1 <- v-s d1 <- 970 d2 <- d1 -s d2 <- 940 d 3 <- d2-s d3 <- 910 : : d15 <- ..... so how I should get vector of length 15 d < - 970,940 , 910 , ....... -- View this message in context:

On Mon, 2 Sep 2019 at 16:59, Roman Lebedev <lebedev.ri at gmail.com> wrote: > > It appears you need 'reassoc' on fmul/fadd: > https://godbolt.org/z/nuTzx2 Thanks very much, that was it. Either that or providing -enable-unsafe-fp-math to llc yielded FMAs. I didn't expect this since using FMAs here instead of mul/add appears to be safer (the reverse is unsafe). ~ Uday

I have some data set which has some values -999.000 & I would like to remove whole row of this kind of values. e.g a<-matrix(c(1,2,3,4,4,5,6,6,-999.99,5,9,-999.00),nrow=4) a<- [,1] [,2] [,3] [1,] 1 4 -999.99 [2,] 2 5 5.00 [3,] 3 6 9.00 [4,] 4 6 -999.00 expected answer [,1] [,2] [,3] [1,] 2 5 5.00 [2,] 3 6 9.00 I

I have some data files e.g 100 . and after for loop I would like to save all data in one single data frame file_s <- list.files(path = ".", pattern = "v2.0.2.txt", all.files = FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE) for (i in 1:100){ data = read.table(file_s[i],header=TRUE) lat = data[,7] # latitude lon

Am Fr., 7. Feb. 2020 um 17:03 Uhr schrieb Chris Lattner <clattner at nondot.org >: > > The discussion here is valuable for me, helping me to make my > > presentation about it at EuroLLVM as relevant as possible. My current > > idea is to take a complex loop nest, and compare optimizing it using > > red/green DAGs and traditional pass-based optimizers. > > Cool.

I would like to read data from two different folder and then combine this together the code which I have tried are as follows setwd("/Groups/data_first/") file_was <- list.files(path = ".", pattern = "v2.0.2.was", all.files = FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE) path<-c("/Groups/data_second/") file_wasaux2

Thanks Chris for CCing us. I remember Michael's presentation and suggestion to consider Roslyn's design and experience. I'll be glad to discuss further in April. Michael, we can also talk later this week if you'd like. I'll send you a separate email. Loop transformations in MLIR take many different paths. Polyhedral affine-to-affine, generative/lowering in linalg, and also

HI samba team, could not find any email except yours,hence mailing. A technical problem ,after installing samba package and samba-common 2.2.7a. Net command is not found with this installation. Can you forward this issue to the correct tech support ?I need a solution asap hence putting a mail.Kindly revert regards, Uday -- Sent via EmailTray, my personal email concierge. Get yours at

Am Mo., 27. Jan. 2020 um 22:06 Uhr schrieb Uday Kumar Reddy Bondhugula < uday at polymagelabs.com>: > Hi Michael, > > Although the approach to use a higher order in-memory abstraction like the > loop tree will make it easier than what you have today, if you used MLIR > for this representation, you already get a round trippable textual format > that is *very close* to your

Am Mi., 5. Feb. 2020 um 18:13 Uhr schrieb Chris Lattner <clattner at nondot.org>: > If I understand your claims, you are claiming both that red/green trees are essential for a loop optimizer, and that this essential nature “justifies” the cost of reinventing an entire compiler infrastructure is lower than the benefit of using (e.g.) MLIR to do this. I haven’t seen evidence of either

Hey R folks, i found some strange (to me) behaviour with chron to POSIXct conversion. The two lines of code result in two different results, on ewith the correct time zone, one without: library(chron) as.POSIXct(chron('12/12/2000'), tz = 'UTC') as.POSIXlt(chron('12/12/2000'), tz = 'UTC') Only the code below would give me a POSIXct object with the correct time