similar to: read.table as integer

Hi, I'm trying to copy the first row of one data frame to another. This is the statement I am using : df2[1,]<-df1[1,]; I have printed them out separately: df1[1,] = A C D E F But after copying: df2[1,] = 96 29 88 122 68 Why isn't it copying? They are both data frames, and "as.character" isn't working either. Thanks for your input :) [[alternative HTML version

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Hello, I am trying to achieve something which I *think* is possible using rowsum, but a little help should be useful: Consider the following dataframe DF0: A B C 89 1 140 89 06 20 89 29 137 89 52 13 89 57 10 89 97 23 89 1 37 89 1 12 89 1 3 52 1 11 52 1 31 52 1 16 52 1 6 52 1 10 52 1 13 52 1 10 52 1 25 52 1 2 52 59 38 52 97 75 57 1 14 57 1 13 57 1 14 57 114 12 57 1 23 57 06 26 I need create a

Dear R'sians, Would really appreciate if you could suggest a more efficient way to order the columns of a dataset. The column names of the dataset contain indices separated by a period. Following are examples of my code and the dataset. oC <- function(tg=x2) { lth <- length(grep("T",names(tg))) thix <-

Hi R Helpers, I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this in a single step; so simply go from df0 to df1 while executing

Hi. I have a problem that I can't seem to find an optimal way of solving other than by doing things manually. I'm trying to subset a data frame by the number of observations that occurred at a given row but want to take into account the number of observations of preceding rows. Here's an example. I'm looking at intervals of data [10,20), [10, 30), ....., [10,120) which contain a

?s 22:50 de 17/10/2024, Sparks, John escreveu: > Hi R Helpers, > > I have been looking for an example of how to execute different dplyr mutate statements on the same dataframe in a single step. I show how to do what I want to do by going from df0 to df1 to df2 to df3 by applying a mutate statement to each dataframe in sequence, but I would like to know if there is a way to execute this

Hola: A ver si me podéis ayudar que estoy atascado... Necesito contar los subcasos de la columna 2 de un dataframe respecto a los casos de la columna 1. Es decir, tengo un data.frame a<-c(rep(c('a','b','c','b','c'),3),'b') b<-c(rep(c('x','y','z','w'),4)) c<-c(rep(c(1,1,0,0),4))

Hola: Aplicaré lo que dices de usar data.table. Sobre hacer for, etc. Ya lo he hecho, pero pensaba que usar dplyr haría la tarea más rápida por estar este implementado en C (si no me equivoco). Siempre que puedo utilizo estas funciones, porque codificas menos y van más rápido. En este caso el problema es que no he encontrado la manera de hacer lo que quiero con dplyr o similar. La idea era al

I truncated and simplified my code and the read in data that I'm working with to isolate the issue. Here is the read in data and R script respectively: http://r.789695.n4.nabble.com/file/n4604287/test.csv test.csv http://pastebin.com/rCdaDqPm Here is the terminal/R shell output that I hope the above replicates on your screen: > source("elecLoad.r", echo = TRUE) > #Load

Hola: Como dice Carlos, algo así, por ejemplo: transforma <- function(df) sapply(df, function(x) ifelse(x%in%c("x1","x2","x3"), "prueba1",ifelse(x%in%c("x4","x5","x6"),"prueba2",x))) > transforma(df1)       col1  [1,] "prueba1"  [2,] "prueba1"  [3,] "x11"  [4,]

I want to change the type to factor of all variables in a data frame whose names match a certain pattern. So here I am trying to change the type to factor of all variables whose name begins with?namestub?in the dataframe?df. attach(df)sapply(grep(glob2rx("namestub*"),names(df)),as.factor) But this doesn't work since >levels(df$namestub1)NULL

Dear Help-Rs,   I have data similar to the following:   DF <- structure(list(X = 1:22, RESULT = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("NEG", "POS"), class = "factor"), YR_MO = c(201011L, 201012L, 201101L, 201102L, 201103L, 201104L, 201105L, 201106L, 201107L, 201108L, 201109L, 201011L,

The new strcapture function in R-devel is handy, capturing the matches to the parenthesized subpatterns in a regular expression in the columns of a data.frame, whose column names and classes are given by the 'proto' argument. E.g., > p1 <- data.frame(Name="", Number=0) > str(strcapture("([[:alpha:]]*) +([[:digit:]]*)", c("Three 3", "Twenty

Hello, I would appreciate if someone could help me resolve the following: 1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work 2. Is these message harmful? The following object(s) are masked from 'df1 (position 3)': X1, X2, X3, X4, X5 Thanks, Pradip Muhuri #Reproducible Example set.seed(5) df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))

I have two data frames which has 3 columns each.My first data frame is large like this below "new.col ppm.p. freq.p." "1_3_diaminopropane 3.13859 5.67516" "1_3_diaminopropane 3.137 6.65388" "1_3_diaminopropane 3.13541 8.0142" "1_3_diaminopropane 3.13383 9.64184" "1_3_diaminopropane 3.12075 298.243" "1_3_diaminopropane 3.1152

Hello all, I have data in the form of a table: X Y1 Y2 0.1 3 2 0.2 2 1 And I would like to transform in the form: X Y 0.1 Y1 0.1 Y1 0.1 Y1 0.1 Y2 0.1 Y2 0.2 Y1 0.2 Y1 0.2 Y2 Any ideas how? Thanks in advance, IOanna [[alternative HTML version deleted]]

Hola, me gustar?a hacer algo como en el siguiente ejemplo A un df a?adirle una columna que es la transformaci?n de otra, en plan a todo lo que sea x1, x2, x3 lo llamo prueba 1 todo lo que sea x4,x5,x6 lo llamo prueba 2 el resto de x las dejo como est?n. Ser?a algo as? col1 <- c('x1', 'x2', 'x11', 'x1','x33', 'x1','x4', 'x5',

Hello All, This works, results <- read.table("plink.txt",T) while this doesn't. results <- read.table("plink.txt") Make sure your data frame contains columns CHR, BP, and P What does adding the "T" in read.table do? Which argument does this correspond to? I tried searching for it but didn't find the answer in: read.table(file, header = FALSE,

Here is a drop-in replacement for the R incomplete beta function. src/math/pbeta.c It is a slightly modified version of the cephes library one from Netlib. In the few cases I tried it seems to give at least 14 digit agreement with the one in S-PLUS (its hard to get more). I'm not sure what performance is like. I'd like to know if it helps with some of the problems which have been