similar to: data.frame: temporal complexity

Displaying 20 results from an estimated 500 matches similar to: "data.frame: temporal complexity"

2012 Feb 03
4
how to plot several curves in the same frame
Hello, I'd like to know how to plot several curves in the same frame (1curve = 1line=1day). For instance (csv file): 2012-02-01 01:00:00; 2100 2012-02-01 02:00:00; 2200 ... 2012-02-01 23:00:00; 2500 2012-02-02 01:00:00; 1000 2012-02-02 02:00:00; 1500 ... 2012-02-02 23:00:00; 1700 Here, I have to plot 2 curves in the same frame: 1 for 2012-02-01 (on the first line) and 1 for 2012-02-02 (on
2012 Feb 08
1
basic debugging
Hi, I have to debug my program. When I execute my function (in debug mode), I have got an error but I do not know which line is concerned. I do not want to do an infinite "Browse[2]>n with each line in my function... THanks for your help, ikuzar -- View this message in context: http://r.789695.n4.nabble.com/basic-debugging-tp4371113p4371113.html Sent from the R help mailing list
2012 Feb 24
6
strange behaviour of "POSIXlt" "POSIXt" object
Hi, Does anybody know why get I this kind of strange situation: Browse[2]> hcEnd [1] "2009-03-29 06:30:00" Browse[2]> class(hcEnd) [1] "POSIXlt" "POSIXt" Browse[2]> is.na(hcEnd) [1] TRUE This issue is the source of my all issues in my program, Thanks for your help -- View this message in context:
2012 Feb 02
2
How to retrieve a column name of a data frame
Hi, I 'd like to know how to retrieve a column name of a data frame. For instance : df = data.frame(c1=c('a','b'),c2=c(1,2)) > df c1 c2 1 a 1 2 b 2 I would like to retrieve the column name which value is 2 (here, the column is c2) thanks for your help -- View this message in context:
2012 Feb 27
2
RStudio: how to change language from fr(french) to eng(english)
Hello, RStudio displays errors in french . I'd like to change it in english Please help, Thanks -- View this message in context: http://r.789695.n4.nabble.com/RStudio-how-to-change-language-from-fr-french-to-eng-english-tp4424972p4424972.html Sent from the R help mailing list archive at Nabble.com.
2012 Jan 12
2
defmacro installation issue
Hi everybody, I want to use macro in my R code. But defmacro was not in my libraries. So I installed it : > install.packages("gtools") Installing package(s) into ?C:/Program Files/R/R-2.13.2/library? (as ?lib? is unspecified) essai de l'URL 'http://cran.cict.fr/bin/windows/contrib/2.13/gtools_2.6.2.zip' Content type 'application/zip' length 102500 bytes (100 Kb)
2012 Jan 12
2
is there an equivalent for #ifdef (C langage) in R
Hi, I'd like to know if there is an equivalent for #ifdef (Clangage) in R. I 'd like to do something like: useDebug = defmacro(DEBUG, expr=(DEBUG==1)) if(useDebug(0)){ #Here I do not use debug mode make_addition = function(a, b) { c=a+b plot(c) return(c) } }else{ #here I use debug mode c=a+b } I assume this would work... The problem is : if
2012 Feb 10
1
debug in a loop
Hi, I'd like to debug in a loop (using debug() and browser() etc but not print() ). I'am looking for the first occurence of NA. For instance: tab = c(1:300) tab[250] = NA len = length(tab) for (i in 1:len){ if(i != len){ tab[i] = tab[i]+tab[i+1] } } I do not want to do "Browse[2]> n" for each step ... I'd like to declare a "browser()" in the loop
2012 Feb 09
1
how to specify the Oy axis length
Hi, I'd like to plot a point: plot(1,2) I use RStudio. I'd like to know how to specify the length of Oy axis. I 'd like to put 20 as length of Oy but , by default, I 've got 2.5. Thanks for your help -- View this message in context: http://r.789695.n4.nabble.com/how-to-specify-the-Oy-axis-length-tp4372937p4372937.html Sent from the R help mailing list archive at Nabble.com.
2011 Dec 27
1
How to extract an interval of "hour:minute" type
Hi, I 'd like to know how to extract an interval of "hour:minute" type from a column of POSIXlt POSIXct type. For instance: my_data.csv: 4352;2011-09-02 21:30:00;3242; 4352;2011-09-02 21:31:00;3315; 4352;2011-09-02 21:32:00;4241; 4352;2011-09-02 21:33:00;5394; ... 4352;2011-09-02 01:02:00;67; 4352;2011-09-02 01:03:00;67; 4352;2011-09-02 01:04:00;67; .... I loaded
2012 Feb 27
2
kmeans: how to retrieve clusters
Hello, I'd like to classify data with kmeans algorithm. In my case, I should get 2 clusters in output. Here is my data colCandInd colCandMed 1 82 2950.5 2 83 1831.5 3 1192 2899.0 4 1193 2103.5 The first cluster is the two first lines the 2nd cluster is the two last lines Here is the code: x = colCandList$colCandInd y = colCandList$colCandMed m = matrix(c(x, y),
2012 Jan 12
1
how to select column wich median is in this interval [5;6]
Hello, I have got a data frame df like this : > df e1 e2 e3 e4 1 1 11 1 21 2 2 12 2 22 3 3 13 3 23 4 4 14 4 24 5 5 15 5 25 6 6 16 6 26 7 7 17 7 27 8 8 18 8 28 9 9 19 9 29 10 10 20 10 30 where e1 ... e3 are vectors I have to select columns which median is in the interval [5;6] ( Here, for instance, e1 and e3) I would not want to use loop... (for, while) I search
2012 Jun 01
1
Error: package 'myLib' is not installed for 'arch=i386'
Hello, I 'd like to use some functions in myLib. So I do: library(myLib) Then I get this message: Error: package 'myLib' is not installed for 'arch=i386' > sessionInfo() R version 2.13.2 (2011-09-30) Platform: i386-pc-mingw32/i386 (32-bit) locale: [1] LC_COLLATE=French_France.1252 LC_CTYPE=French_France.1252 LC_MONETARY=French_France.1252 LC_NUMERIC=C
2012 Apr 05
2
how to compute a vector of min values ?
Hi, I'd like to know how to get a vector of min value from many vectors without making a loop. For example : >v1 = c( 1, 2, 3) > v2 = c( 2, 3, 4) > v3 = c(3, 4, 5) > df = data.frame(v1, v2, v3) > df v1 v2 v3 1 1 2 3 2 2 3 4 3 3 4 5 > min_vect = min(df) > min_vect [1] 1 I 'd like to get min_vect = (1, 2, 3), where 1 is the min of v1, 2 is the min of v2
2012 Jan 19
1
dataframe: how to select an element from a row
Hi, I 'd like to select the Date where myvalue =1800 appears the* first time*. For instance: df =data.frame(date, myvalue, ...) ... Date myvalue 2012-01-05 2500 2012-01-06 2450 *2012-01-07 1800* 2012-01-08 2200 2012-01-09 1800 I'd like to retrieve the third line. I do
2010 Jul 24
1
Sound card problem in acoustic echo
>I remember?I had to expose the echo cancelation level implementing a get_echo_level( ) function based on this: >http://lists.xiph.org/pipermail/speex-dev/2008-September/006889.html This is really a good idea to determine the frequency difference between capture and play of the sound card. But it need constant far-end voice and a long time because it must repeat the process of
2010 Jul 22
1
Sound card problem in acoustic echo
Thank you. But it will cost you a long time to get the accurate play and capture frequencies. Does your program test two frequencies of the sound card each time? Because different sound cards have different frequency errors. And the resampling program is also time consuming because the target frequency is so close to the sampling frequency of the input signal, isn't it? I have tested program
2010 Sep 30
1
Sound card problem in acoustic echo
Hi All, In order to deal with acoustic echo cancellation problems of most PCs which sound cards have different capture and play frequencies. I made a trial. At first, a 1000Hz sine wave is played for a long time via a speaker and its acoustic echo is recoreded. Seconds, get the frequency of the echo by a FFT analyser. So the difference between capture and play frequencies is obtained. Thirdly,
2020 Nov 20
0
dnsupdate failed with TKEY is unaceptable
El 20 de noviembre de 2020 2:22:45 GMT-05:00, "L.P.H. van Belle" <belle at bazuin.nl> escribi?: >I suggest you read : >https://wiki.samba.org/index.php/Dns_tkey_negotiategss:_TKEY_is_unacceptable > Hello; I read the URL sugessted. There exist a Kerberos principal; there exist the bind AD account and the files permission in /usr/local/samba/private/dns.keytab are
2013 Oct 10
2
Help with expression()
Hi everyone, I am hoping someone can help with my attempted use of the expression function. I have a long series of text and variable to paste together including a degree symbol. The text is to be placed on my scatter plot using the mtext function. Using expression like this: changetext = expression(paste("Change from ",mini," to ", maxi, ":", diff