similar to: Bug?

I run "net join -U Administrator -w CISL.CO.UK -d10" which fails to join the domain with the error "Unable to find a suitable server" net appears to fail because it cannot load a file that does not exist. [2008/01/13 09:19:52, 3] libads/ldap.c:ads_connect(394) Connected to LDAP server 10.50.20.2 [2008/01/13 09:19:52, 10] intl/lang_tdb.c:lang_tdb_init(138) lang_tdb_init:

R 1.9.1 requires multi-line strings to contain a backslash at the end of each line (except the last line). As noted by Mark Bravington (http://tolstoy.newcastle.edu.au/R/help/02b/5199.html) this requirement appears to be undocumented. In S-Plus 6.2, multi-line strings do not need a backslash for continuation. I recently (http://tolstoy.newcastle.edu.au/R/devel/04b/0256.html) requested

Dear R-Devel subscriber, I encountered the following problem for tex-formatted table with xtable(). Suppose I do want the following matrix as a table in LaTeX: library(xtable) a11 <- "\\color{green}\\textbf{big green}" a21 <- "\\color{red}\\textbf{big red}" a12 <- "\\color{green}green" a22 <- "\\color{red}red" A <- matrix(c(a11, a21, a12,

Hi, I would really like to have a way to split long string literals across multiple lines in R. Currently, if a string literal spans multiple lines, there is no way to inhibit the introduction of newline characters: > "aaa + bbb" [1] "aaa\nbbb" If a line ends with a backslash, it is just ignored: > "aaa\ + bbb" [1] "aaa\nbbb" We could use

Hello! I've just started trying gnome-terminal (instead of xterm) because of its "tabbing" facility. However, I note that with it backslashes appear something like a W with a horizontal line through it. Any known way to get a backslash to appear as a backslash? To see what I mean, use gnome-terminal with echo '\' in bash, ksh, etc. Regards, Chip Campbell

Greeting R Community, I am a windows user so this problem may be specific to windows. I often want to source files from within R such as: C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To source this file I need to go through the path and replace all the backslashes (\) with forward slashes (/). I usually do this in MS Word using the replace option, however, I'd like

Dear R List I have a small problem concerning the output of print(). My version: > R.version _ platform i386-portbld-freebsd5.2 arch i386 os freebsd5.2 system i386, freebsd5.2 status major 1 minor 9.0 year 2004 month 04 day 12 language R Consider this: I want to print a backslash with an exclamation mark. Here is the output. > print( "\!"

I have a path: path = "/nfs/users/nfs_n/ns9/ Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll trained without akapn+tnik.csv" I wish to replace the spaces with "\ " so that it can be read by a system call to unix. Using gsub I try: > gsub(" ","\\ ",path) [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg BinaryAll

Hi, I'm trying to build a vector of latex commands. However, I need the command strings to begin with a backslash "\". I have: test <- c('foo','bar') and I need to rebuild the array, encapsulating the text items with latex stuff, like this: paste("\parbox[b]{3cm}{", test, "}", fill=TRUE) Actually, cat() prints the string fine if one uses

I find that Sys.glob() doesn't like UNC paths where the initial slashes are backslashes. The help page for Sys.glob() doesn't specificly mention UNC paths, but does say: "File paths in Windows are interpreted with separator \ or /." Is the failure to treat a path beginning with a double-backslash as a UNC network drive path the intended behavior? E.g., on a Windows system

I am trying to check for backslashes in data, then remove them when I find them, but am having a difficult time figuring out the best way to do it. I know the backslash is the escape character in R, and I should be able to use 'gsub' to accomplish this, but I all I seem to be getting are errors. For example: If entry is: "Hello\World" I want: "HelloWorld"

Rowland, I remember now, you and I have been here before and I have lost the email. Due to the manner that linux handles backslashes "\" users need to backslash *around* the backslash you need for W10 like so, "\\\\FQDN" to get "\FQDN" on the W10 path? Therefore, the following is what I want: "--profile-path=\\dtmbr04.ad.dtntwk.work\profiles\sttest11

I thought that I can use metacharacters such as \w to match word characters with one backslash. But for some reason, I need to include two backslashes. > grepl(pattern='\w', x="what") Error: '\w' is an unrecognized escape in character string starting "\w" > grepl(pattern='\\w', x="what") [1] TRUE I can't find the reason for this

Dear list, After searching many old posts, I can't find the solution to a simple problem. can someone tell me how to create a character string with multiple backslashes, as in: file_dir <- c("C:\files\data\") I need to create this string and then paste it to many files names for batch processing in another software program. R won't accept the backslash and removes

I noticed this issue in stringr::str_replace, but it also affects sub() in base R. If the pattern in a call to one of these needs to be a regular expression, then backslashes in the replacement text are treated specially. For example, gsub("a|b", "\\", "abcdef") gives "def", not "\\\\def" as I wanted. To get the latter, I need to escape

Hi there, I rejoiced when I realized that you can use Perl regex from within R. However, as the FAQ states "Some functions, particularly those involving regular expression matching, themselves use metacharacters, which may need to be escaped by the backslash mechanism. In those cases you may need a quadruple backslash to represent a single literal one. " I was wondering if that is

Dear helpers, I'm trying to replace a character with a unicode code inside a data frame using gsub(), but unsuccessfully. > data.frame(animals=c("dog","wolf","cat"))->my.data > gsub("o","\u0254",my.data$animals)->my.data$animals > my.data$animals [1] "d??g" "w??lf" "cat" It's not that a data

How can I get a single backslash in a character string? My goal is to escape dots in a string that will be used as a regular expression. I thought I could do it this way: gsub(".", "\\.", x) Unfortunately, "\\" does not represent a literal backslash as I expected, but rather a pair of backslashes: > "\\." [1] "\\." > "\\" [1]

Something about the way R processes backslashes is defeating me. Perhaps this is because I have only just started using R for text processing. I would like to change occurrences of the ampersand & into ampersand preceded by a backslash. > temp <- "R & D" > sub("&", "\&", temp) [1] "R & D" > sub("&",

On Wed, 14 Jun 2017 06:12:09 -0500, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > On 14/06/2017 5:58 AM, Andreas Kersting wrote: > > Hi, > > > > I would really like to have a way to split long string literals across > > multiple lines in R. > > I don't understand why you require the string to be a literal. Why not > construct the long