similar to: Trouble pinging servers DNS name.

I'm trying to config Samba PDC using: The Unofficial Samba HOWTO but error apeared: The following error occurred attempting to join the domain MYDOMAIN: The specified network password is not correct I tried: Use Window's Group Policy Editor (gpedit.msc) to make the following changes in the Local Computer Policy\ Computer Configuration\ Windows Settings\ Security Settings\ Local

I played with the smb.config file long enough to get both the smbd and nmbd daemons to run. Then ran TESTPARM against the correct smb,conf file without issue. Finally I tried the following command: [root@cofr3 /]# smbclient -U illingsk -L MySQL added interface ip=172.17.60.6 bcast=172.17.63.255 nmask=255.255.248.0 wins_srv_died(): WINS server 172.16.0.121 appears to be down. Connection to MySQL

I created a new virtual Linux server running the Red Hat v7.2 distribution. After getting a MySQL/PHP application running, the next step was to add a Win2kPro Workstation to a new Linux PDC. Towards that end I modified the smb.conf file as described below to turn the virtual Linux server into a stand alone PDC. A 'MACHINE.SID' was created in the /usr/local/samba/private directory.

Have just upgraded to samba 1.9.18p3 on a RedHat 5.0 linux system... now... when i type smbstatus... this is what i get.. Couldn't open status file /var/lock/samba/STATUS..LCK so i assume that for some reason... this status file is not created upon startup.. Pat.

Can anyone peruse my attached host.conf file and determine what missing statement this error is referring to? Here is the command that generated this error: [root@cofr3 s390]# /usr/sbin/rndc reload /etc/host.conf: line 11: expected service, found `wins, dns, files' rndc: reload command successful Thank you in advance for your time. -------------- next part -------------- # # /etc/host.conf

Hi R-Helpers, Sorry to bother you, but I have a simple task that I can't figure out how to do. For example, I have some names in two columns NamesWide<-data.frame(Name1=c("Tom","Dick"),Name2=c("Larry","Curly")) and I simply want to get a single column

Hi all, let say I have following matrix: > Dat <- matrix(1:30, 5, 6); colnames(Dat) <- rep(c("Name1", "Names2"), 3) > Dat Name1 Names2 Name1 Names2 Name1 Names2 [1,] 1 6 11 16 21 26 [2,] 2 7 12 17 22 27 [3,] 3 8 13 18 23 28 [4,] 4 9 14 19 24 29 [5,] 5

Just to repeat: you have NamesWide<-data.frame(Name1=c("Tom","Dick"),Name2=c("Larry","Curly")) and you want NamesLong<-data.frame(Names=c("Tom","Dick","Larry","Curly")) There must be something I am missing, because NamesLong <- data.frame(Names = c(NamesWide$Name1, NamesWide$Name2)) appears to

I have a simple script: #!/bin/bash # index=0 total=0 names=() ip=() while read -r LINE do NODENAME=` echo $LINE | cut -f 1 -d ','` IP=` echo $LINE | cut -f 2 -d ','` names[index]="$NODENAME" ip[index]="$IP" index=`expr index+1` total=`expr total+1` done <<< $(cat list.txt) simple file: more list.txt name1,ip1 name2,ip2 name3,ip3 output when

I have some questions about the RODBC package. library(RODBC) # required for those who want to repeat these lines 1st, I noticed that the following sequence does not work: channel <- odbcConnextExcel("test.xls") tables <- sqlTables(channel) name1 <- tables[1, "TABLE_NAME"] # this should be the name plan1 <- sqlFetch(channel, name1) # bang!

Hi, I am trying to write a function to automate multiple graph generation. My data looks like: Table of numeric values with the following headers: timeM1 statusM1 xM1 timeM2 statusM2 xM2 timeM3 statusM3 xM3 1 2 3 4 5 6 Where M1,M2, M3 hve no similarity except they have a max string length of 7. Examples are mcw0045, adl0003, lei0101. Now, what I want to do is Function(M1, M2,

Hi! I suspect there must be an easy way to access components of a data frame by name, i.e. the input should look like "name1 name2 name3 ..." and the output be a data frame of those components with the corresponding names. I ´ve been trying for hours, but only found the long way to do it (which is not feasible, since I have lots of components to select):

Hi, Let us suppose I have a list x = list () x $ name1 = 1 x $ name2 = 'a' in the work environment. Let us suppose that in the body of a function I want to acces to a component of x by using its name as argument of that function. How can this by done? For instance, I was expecting f = function ( name ) x $ name to output 1 ( that is, x $ name1 ) when I command f ( name1 ) or f (

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

I may be missing something but using the plain old c() combine function seems to work fine: df <- data.frame(left = 1:5, right = 6:10) df.combined <- data.frame(comb = c(df$left, df$right)) df left right 1 1 6 2 2 7 3 3 8 4 4 9 5 5 10 df.combined comb 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 -----Original

Hi, all How to format and join strings ? For example, like following short python examples. ********* name1 = 'sample-plot' filename = '%s.png' % name1 inputdir = '/path/to/dir' os.path.join(inputdir, filename) ********** Best, Hyunchul Kim [[alternative HTML version deleted]]

Hi, You were on the right track using stack(), but you just pass the entire data frame as a single object, not the separate columns: > stack(NamesWide) ? values ? ind 1 ? ?Tom Name1 2 ? Dick Name1 3 ?Larry Name2 4 ?Curly Name2 Note that stack also returns the index (second column of 'ind' values), which tells you which column in the source data frame the stacked values originated

Dear All, I need some help arranging data that was imported. The imported data frame looks something like this (the actual file is huge, so this is example data) DF: IDKey X1 Y1 X2 Y2 X3 Y3 X4 Y4 Name1 21 15 25 10 Name2 15 18 35 24 27 45 Name3 17 21 30 22 15 40 32 55 I would like to create a new data frame with the following NewDF: IDKey X Y Name1 21 15 Name1

Hi I have a character vector with thousands of names which looks like this: > V=c("Fred", "Mary", "SAM") > V [1] "Fred" "Mary" "SAM" > class(V) [1] "character" I would like to change it to a list: > L=as.list(V) > L [[1]] [1] "Fred" [[2]] [1] "Mary" [[3]] [1] "SAM" but I need to

Say I have a file called exp.batch which contains 2 cols The first col contains names of R objects the user would like to use. The second col contains the file names which will be read in using read.table i.e. exp.batch may look like this..... name1 complex/filename/path1.txt name2 complex/filename/path2.txt name3 complex/filename/path3.txt name4 complex/filename/path4.txt I want to have a