similar to: How to hide the file name listings, but still see the stats?

I'm seeing the following behavior: - lib/ Excludes any directory named lib - .hidden/ Appears to be ignored; .hidden and all sub-folders are transferred/deleted - .hidden** Excludes any directory named .hidden. From my reading of the "FILTER RULES" section, I would expect the last two options to be equivalent. Note that I'm doing this all with -n; I haven't done the

We have a large (20Gb, 250000 files) tree which needs to replicate across our WAN on a regular basis. We have been using a wrapper script around rsync to do this; the wrapper script runs setuid-root on a Solaris 8 server. However, we have on-going problems with files whose permissions don't replicate correctly. These file permissions are the REAL problem; if the permissions aren't

Dear friends, My dataset have many zeros, so i must use fisher exact test . Unfortunately, the fisher.test(stats) function fail to do it. Anybody knows how to do the fisher exact test with many zeros in the dataset? My dataset is: a<-matrix(c(0,1,0,0,0,0,1,0,1,0,0,0,0,1,0,1,1,0,2,1,5,1,1,6,4,4,1,17,2,8,5,7,1,1,24,3,6,1,1,3,2,16,7,4,0,2,4,0,17,0,1,0,0,0,1,2),nrow=8,byrow=TRUE) data.frame(a)

Dear R users, Thanks in advance. I am Deb, Statistician at NSW Department of Commerce, Sydney. I am using R 2.8.1 on Windows XP. This has reference to the package “DPpackage”. The binary version is available on Mac OS, but I am using Windows XP. May I request you to assist me in the followings: How can I prepare Windows binary of DPpackage from source? 2. Is there any possibility

Hi, > R.version.string [1] "R version 2.0.1, 2004-11-15" I have found two possible bugs in function validObject. Details below. Cheers, Scott ================================== Scott D. Chasalow Principal Statistician Statistical Genetics and Biomarkers Bristol-Myers Squibb Company Email: scott.chasalow <AT> bms.com ================================== ------ BEGIN R

Dear friends we have the following problem. We have Operating system=OpenBsd installed computer and an other one with windows 98 when we change the password via smbpasswd myname ... then we have the following problem. My sambapassword is really changed. Since when I try to communicate samba server through windows 98 installed computer I see there is no problem. (Since we can see the shared

Dear Rusers, I have some data in .csv file like "2004-8-1" and "2004-10-1", and i need to convert them into days from the origin (January 1, 1960). I have tried the function date.mmddyyyy(), but cannot get it. Anybody can show me how to handle the date data? Thanks very much! My dataset like: time 2004-8-1 2004-10-1 2001-9-1 2002-9-1 -- With Kind Regards,

Dear Ruser, I use abline() function to add the reference line successfully, but i can't display the values corresponding to the reference line on the x/y axis, anybody knows how to display it? *My simulated programs:* y<-rnorm(50) plot(x,y) abline(v=0.5) *#my question is how to display x=0.5 in the x axis?* Thanks in advance. -- With Kind Regards, oooO::::::::: (..):::::::::

Hi ! While browsing Linux manpages (man 3 syslog) I noticed that the manual says that the LOG_AUTH facility is deprecated use LOG_AUTHPRIV instead. Is there a good reason why OpenSSH doesn't have an option to use LOG_AUTHPRIV facility ? (Looks like that tcpd/telnet etc. use the AUTHPRIV facility (in RH6.2)). Shouldn't be too hard to add the AUTH_PRIV facility ? Cheers, -Jarno --

Dear friends, The following is an example to explain my question. I want to get a legend which will show the z-values according to different colors in image() function. x<-sort(runif(10)) #x-coordinates y<-sort(runif(10)) #y-coordinates z<-matrix(runif(100),nrow=10) #attributes values image(x,y,z,col=gray((6:3)/6)) # legend(x,y,legend=z,col=gray((6:3)/6)) #error. the colors should

Dear R users, I hope to explain the concepts of skewness and kurtosis by generating series of distributions with same skewness and different kurtosis or with same kurtosis and different skewness, but it seems that i cannot find the right functions. I have searched the mailing list, but no answers were found. Is it possible to do that in R? Which function could be used? Thanks a lot. --

Dear friends, After fitting a generalized linear models ,i hope to get the variance of alpha,variance of beta and their covariance, that is , the variance-covariance matrix/information of alpha and beta , suppose *B* is the object of GLMs, i use attributes(B) to look for the options ,but can't find it, anybody knows how to get it? > attributes(B) $names [1] "coefficients"

Dear friends, My dataset is like the following: x y mcpvalue 0.4603578 0.6247629 1.001 0.4603715 0.6247788 1.001 0.4603852 0.6247948 1.001 0.4110561 0.5664841 0.995 The x and y variables are unsorted. I use the function image(x,y,mcpvalue) to generate a plot, but the error is that "increasing 'x' and

Dear all, Following the help from gam(mgcv) help page, i tried to analyze my dataset with all the default arguments. Unfortunately, it can't be run successfully. I list the errors below. #m.gam<-gam(mark~s(x,y)+s(lstday2004)+s(slope)+s(ndvi2004)+s(elevation)+s(disbinary),family=binomial(logit),data=point)

Dear friends, In S-PLUS, we can use the following argument, but not in R. mode12 <- gam(score1 ~ lo(latitude) + lo(longitude)) I searched the help in S-PLUS, it says lo() Allows the user to specify a Loess fit in a GAM formula, but i didn't find the correponding function in R. Anybody knows how to do the similar task in R? Thanks very much. -- With Kind Regards, oooO:::::::::

Dear R users, We have some programs for the specific task in our research, but they were very commonly used. We want to make some functions for them, anybody can recommend any good tools to facilitate us to create R functions even without going deep into the theories of R functions ? Any suggestions or help are greatly appreciated. -- With Kind Regards, oooO::::::::: (..):::::::::

Dear all, I have two variables, y and x. It seems that the relationship between them is Piecewise Linear Functions. The cutpoint is 20. That is, when x<20, there is a linear relationship between y and x; while x>=20, there is another different linear relationship between them. How can i specify their relationships in R correctly? # glm(y~I(x<20)+I(x>=20),family = binomial, data =

Dear friends, Anybody has ever met the problem to add a legend to a figure generated by image()? I have three variables,x,y and z. x and y are the coordinates, and z is the third values. we can use image(x, y, z,...) to generate a figure according to the z-values, but the problem is the figure legend. How can the legend be added to a figure generated by image()? Note that filled.contour() can

Dear all, Some functions like 'ROC(Epi)' can be used to perform ROC analyssi, but it needs us to specify the fitting model in the argument. Now i have got the predicted p-values (0,1) for the 0/1 response variable using some other approach, see the following example dataset: id mark predict.pvalue 1 1 0.927 2 0 0.928 3 1 0.928 ..................

Buenas tardes a todos. Mi problema es el siguiente: Calculo una muestra de unos índices (s) y a partir de esa muestra elijo aquellos elementos de una tabla de datos que tengo (en este caso XP4) que cumplen la condición de que el índice de XYP sea el de la muestra. Ahora comienza mi problema, la única forma que he encontrado para que me R me tome todos los elementos que necesito es creando un