similar to: [Bug 1812] New: fuzzy not working in 2.6.3-pre{1,2}

https://bugzilla.samba.org/show_bug.cgi?id=1489 Summary: Corrupt transfer with the fuzzy option Product: rsync Version: 2.6.2 Platform: All OS/Version: Linux Status: NEW Severity: normal Priority: P3 Component: core AssignedTo: wayned@samba.org ReportedBy: egmont@uhulinux.hu

https://bugzilla.samba.org/show_bug.cgi?id=1812 wayned@samba.org changed: What |Removed |Added ---------------------------------------------------------------------------- Status|NEW |RESOLVED Resolution| |FIXED ------- Additional Comments From wayned@samba.org 2004-09-23 08:47

https://bugzilla.samba.org/show_bug.cgi?id=1488 Summary: rusty-fuzzy.diff lacks a new file Product: rsync Version: 2.6.2 Platform: All OS/Version: Linux Status: NEW Severity: normal Priority: P3 Component: core AssignedTo: wayned@samba.org ReportedBy: egmont@uhulinux.hu QAContact:

Hi I have within a quite big function foo1, an internal function foo2. Now, in order to have a cleaner code, I wish to have the internal foo2 as "external". This foo2 was using arguments within the foo1 environment that were not declared as inputs of foo2, which works as long as foo2 is within foo1, but not anymore if foo2 is external, as is the case now. Now, I could add all those

This is a recent R-devel. file.copy() is not vectorized if multiple destinations succeed: cat("foo1\n", file = "foo1") cat("foo2\n", file = "foo2") unlink(c("copy1", "copy2"), recursive = TRUE) file.copy(c("foo1", "foo2"), c("copy1", "copy2"), copy.date = TRUE) #> Error in

Hello! Say I have a function foo1, which has argument ... to pass various arguments to foo2 i.e. foo1 <- function(x, ...) { foo2(x, ...) } Say that foo2 accepts argument arg1 and I would like to do the following: - if foo1 is called as foo1(x) then I would like to assign some value to arg1 inside foo1 before calling foo2 arg1 <- "some value" foo2(x, arg1=arg1) - if foo1 is

https://bugzilla.samba.org/show_bug.cgi?id=3392 Summary: fuzzy misbehaving if source is a file Product: rsync Version: 2.6.6 Platform: All OS/Version: Linux Status: NEW Severity: normal Priority: P3 Component: core AssignedTo: wayned@samba.org ReportedBy: egmont@uhulinux.hu

Thank you very much for your useful suggestions. These are exactly what I was looking for. foo <- list(foo1, foo2, foo3) lapply(foo, function(x) matrix(unlist(x), nrow = length(x), byrow = TRUE)) or lapply(foo, function(x) do.call('rbind', x)) Best, Muhammad Subianto On 4/11/06, Muhammad Subianto <msubianto at gmail.com> wrote: > Dear all, > I have a result my experiment

Dear R-devel, I'm trying to validate the results from a C function, against a (trial and tested) older R function. For reasons unknown to me, the C function seems to give different result sometimes at each trial, even with the very same data. These are the relevant outputs from R: > library(QCA) Loading required package: lpSolve > benchmark <- function(x, y) { + index <- 0

Hi to all Authors@R: c(person("fooa","foob", role = c("aut","cre"), email = "fooa.foob@fooc.de"), person("foo1","foo2", role = c("ctb"), email = "foo1.foo2@foo3.de")) Author: fooa foob, with contributions from foo1 foo2 using r CMD check --as-cran .. (R 3.1

Dear all, I have a result my experiment like this below (here my toy example): foo1 <- list() foo1[[1]] <- c(10, 20, 30) foo1[[2]] <- c(11, 21, 31) foo2 <- list() foo2[[1]] <- c(100, 200, 300) foo2[[2]] <- c(110, 210, 310) foo3 <- list() foo3[[1]] <- c(1000, 2000, 3000) foo3[[2]] <- c(1100, 2100, 3100) list(foo1,foo2,foo3) The result: > list(foo1,foo2,foo3) [[1]]

Hi, I'm running postfix as SMTP-server and dovecot as IMAP-server. The server has multiple IPs, and postfix is configured that every domain is using a separate IPv4-address. Examle: foo1.com --> 11.22.33.44 foo2.com --> 22.33.44.55 foo3.com --> 33.44.55.66 bar.org --> 66.77.88.99 The hostname of the server is: mail.bar.org Now I have a request from one of my customers,

Hi, some change during the last 10 days breaks code where slots of an object are changed globally: setClass("mylist", contains = "list") setClass("dummy", representation = representation( a = "mylist")) foo1 = function(i, x) { mydummy@a[[i]] <<- x ### change a slot } foo2 = function() { ### define an object mydummy <<-

Hi, although I've done S3 dispatching for more than a decade now, I think I managed to overlook/avoid the following pitfall when using NextMethod(): If you explicitly pass argument '...' to NextMethod(), you will effectively pass those argument twice to the "next" method! EXAMPLE: foo0 <- function(...) UseMethod("foo0"); foo1 <- function(...)

Dear all, I have define a function and its methods as follows: ######## beginning of code fn <- function(x,...){ UseMethod("fn") } fn.foo1 <- function(x, commonA=1, ...){ print("fn.foo1 is called.") } fn.foo2 <- function(x, uniqueFoo2, common=1, ...){ ## uniqueFoo2 is a unique argument in fn.foo2 x <- uniqueFoo2; class(x) <- "foo1" ## use uniqueFoo2

On Mon, Dec 8, 2014 at 3:32 PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: [...] > Why not declare colorspace as a "Suggests:" kind of dependency? I guess that is a solution. :/ In another example in the 'disposables' package I have: \donttest{ pkg <- make_packages( foo1 = { f <- function() print("hello!") ; d <- 1:10 }, foo2 = { f

Hi the list, I define a method that want to change an object without assignation (foo(x) and not x<-foo(x)) using deparse and assign. But when the argument of the method does not match *exactly* with the definition of the generic function, assign does not work... Anything wrong? Christophe #------ Does not work ------#

Dear List: In short, I am writing a number of functions as building blocks for other functions and have some questions about scoping and passing arguments. Suppose I have functions foo1, foo2, and foo3 such that: foo1<-function(a=1,b=TRUE,c=FALSE){#do stuff}; foo2<-function(x=1,y=FALSE,z=c(1,2,3,4)){#do stuff}; foo3<-function(lambda,...){lambda*foo1()*foo2()}; I want to be able to

http://bugzilla.mindrot.org/show_bug.cgi?id=871 Summary: request for idn (intl domain names) support Product: Portable OpenSSH Version: 3.8.1p1 Platform: All OS/Version: Linux Status: NEW Severity: enhancement Priority: P2 Component: Miscellaneous AssignedTo: openssh-bugs at mindrot.org

Dear Mr. Lattner: You have asked me how my instruction set works. If I code like this: int foo1() { int x1,x2; x1 =1; x2 = foo2(x1); return x2; } int foo2(int k) { if(k == 1) k = 2; return k; } int main () { int j; j = foo1(); } This should be emitted like this: Enter foo1; reg x2, x1 add 1;x1 Call foo2;x1,x2 Exit foo1; x2