similar to: round to specific intervals

On Thu, May 09, 2013 at 12:21:30PM -0400, Jack Howarth wrote: > On Wed, May 08, 2013 at 06:53:05AM -0700, Peter Collingbourne wrote: > > On Wed, May 08, 2013 at 09:25:55AM -0400, Jack Howarth wrote: > > > Duncan, > > > I was wondering if you plan on supporting the build of dragonegg under gcc 4.8.1svn > > > for the llvm 3.3 release? Is the deprecation and

On Wed, May 08, 2013 at 06:53:05AM -0700, Peter Collingbourne wrote: > On Wed, May 08, 2013 at 09:25:55AM -0400, Jack Howarth wrote: > > Duncan, > > I was wondering if you plan on supporting the build of dragonegg under gcc 4.8.1svn > > for the llvm 3.3 release? Is the deprecation and poisoning of IDENT_ASM_OP too problematic > > to work around without some

Hi all, Given the following series of numbers: > t [1] 21.85000 30.90410 43.71000 61.82234 87.43999 123.67296 [7] 174.91997 247.40249 349.91996 494.91815 700.00000 What's the simplest way of formatting them into the nearest "natural looking" (rounded to nearest multiple of 10) numbers? So: t[1] becomes 20 t[2] becomes 30 t[3] becomes 40 t[4] becomes 60 t[5] becomes 90

Dear All, would you please provide your thoughts on the following: let us say I have: a <-c(1,5,8,15,32,69) b <-c(8.5,33) and I would like to extract from "a" the two values that are closest to the values in "b", where the length of this vectors may change but b will allways be shorter than "a". So at the end based on this example I should have the result

Hi, I am sure there is a reason but ...... why larger decimal numbers get rounded to the nearest integer? Example: a <- 3308000.5 a [1] 3308001 I would like my numbers to be decimals .... since they do represent coordinates and i don't want them rounded .... how can i keep them as they are? Thanks, Monica _________________________________________________________________

I couldn't find anything in the chron or timeDate packages, and a good search yielded rounding to the nearest half hour, which I don't want. The data: structure(list(Date = structure(c(1209625080, 1209641460, 1209652500, 1209676800, 1209682860, 1209692100, 1209706980, 1209722580, 1209726300, 1209739620, 1209762780, 1209765720, 1209770520, 1209791040, 1209812580, 1209829920,

It may be my lack of unerstanding, but round() seems to me to give inconsistent results when rounding 5s as in the following examples? > round(1.45, 1) [1] 1.4 # OK > round(2.45, 1) [1] 2.5 # shouldn't this be 2.4? > round(1.05, 1) [1] 1.1 # 1.0 ? and signif(): > signif(2.445, 3) [1] 2.44 # OK > signif(3.445, 3) [1]

i have a table like this of an value and its tolerance length delta-length 12.2232 0.4 123.422 0.034123 1234 12 i want to round the value to the significant digits in this way: my-round(length,delta-length) 12.2 , 0.4 123.42 , 0.03 1234 , 12 how can i do this with R? please CC to email, thanks so far, -- Jonas Stein <news at jonasstein.de>

Hello *, I'm trying to round time stamps, consisting of a date and time part, to 10 minutes intervals The timestamps have the following format: %d.%m.%Y %H:%M *timeStamp <- c("31.03.2011 09:30", "31.03.2011 09:41", "31.03.2011 10:04", "31.03.2011 10:10", "31.03.2011 10:28", "31.03.2011 10:35", "31.03.2011 10:49",

Hi This is (hopefully) a bit more cogent phrasing of a previous post. I'm trying to compute a z-score to rows in a large dataframe based on values in another dataframe. Here's the script (that does not work). 2 questons, 1) Anyone know of a more elegant way to calculate the "rounded" age value than the nested ifelse's I've used? 2) how to reference the lookup table

I'm not mathematically gifted, but shouldn't 957%60 be 15 remainder 57? Google and my desktop calculator certainly think so. So where am I going wrong here? The following code exten => 7,1,Verbose(Context: ${CONTEXT} Exten:${EXTEN}) same => n,Set(myNum=957) same => n,Set(sec=$[REMAINDER(${myNum},60)]) same => n,Set(sec=$[ABS(${sec})]) same =>

Dear List, I need some help in coming up with a function that will take two data sets, determine if a value is missing in one, find a value in the second that was taken at about the same time, and substitute the second value in for where the first should have been. My problem is from a fish tracking study. We put acoustic tags in fish and track them for several days. Location data is supposed

>>>>> Hugh Parsonage >>>>> on Sat, 8 Feb 2020 21:12:43 +1100 writes: > The only observation I can make is that the change to > round() was made in r77727 whereas your R-devel appears to > be r77715 (so would not exhibit the fixed behaviour). My > guess is that there was a perpetual installation failure > after r77715 but that

Good day, The use of "rounding" also doesn't make sense. If The number is halfway between two integers, it is rounded to the nearest even integer. > round(2.5) [1] 2 -------------------------------------- Dario Strbenac University of Sydney Camperdown NSW 2050 Australia

Dear R Community, I hope you might be able to assist with a small problem creating a function. I am working with water-quality data sets that contain the concentration of many different elements in water samples. I need to assign quality-control flags to values that fall into various concentration ranges. Rather than a web of nested if statements, I am employing the findInterval function to

What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1, so there are no inside intervals? R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's when length(vec)==0. Would '0' in all those cases be better? > findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE, rightmost.closed=FALSE, left.open=FALSE) [1] 1 0 0 >

Hi , I have two sorted vectors X and Xi, where the range of Xi lies within the range of X. For an element in Xi, I want to find the neigbouring data in X, e.g. find an index ix so that for element number k, then X[ix[k]] < X[k] < X[ix[k] +1] # also OK with "<=" on either one, but not both This is easy to code by looping over the data in X,Xi, but I suspect there may be a

I have corrected a typo in my previous posting. In what follows the line with the inequality is correct Hi , I have two sorted vectors X and Xi, where the range of Xi lies within the range of X. For an element in Xi, I want to find the neigbouring data in X, e.g. find an index ix so that for element number k, then X[ix[k]] < Xi[k] < X[ix[k] +1] # also OK with "<=" on either

Hello, I have a list of dates in which I am going use for a time series analysis. I want to break these dates up into 2 week intervals and count the number of times a date appears in this interval. For example from Nov. 19, 2000 to Dec 2 ,2000 with the data listed below I want to return Start_date Count2000/11/19 4 Date: 2000/11/20 2000/11/21 2000/11/19 2000/11/29 My first approach was toa

Hi All, So I''ve got a DVB-S PCI Express card ($30 USD Twinhan AD-SE200 off eBay) that''s being passed via VT-d/pciback in Xen 3.2.1 under CentOS 5.2 to a Windows XP SP3 which works! ... except for one small issue... Motherboard is an Intel DQ35JO that much people has had success with and an Intel E8400 CPU. The issue is that when dealing with FTA MPEG-2 transport streams (DVB-S