Displaying 20 results from an estimated 2000 matches similar to: "quick ANOVA question"
2010 Aug 03
1
releveling a numeric by factor interaction
Can anyone help me with the necessary code to relevel a numeric*factor
interaction term in a linear model? I would like to report the estimate,
std. error and t-value for the reference factor.
First, I estimated a linear model with dummy variables and was able to
retrieve model estimates for the reference factor using relevel.
for example:
> summary(update(mod.mod, . ~ . - dummy +
+
2009 Jan 09
2
recursive relevel
Dear list,
I'm having second thoughts after solving a very trivial problem: I
want to extend the relevel() function to reorder an arbitrary number
of levels of a factor in one go. I could not find a trivial way of
using the code obtained by getS3method("relevel","factor"). Instead, I
thought of solving the problem in a recursive manner (possibly after
reading
2006 Dec 15
1
Switching labels on a factor
Hi All,
I'm perplexed by the way the unclass function displays a factor whose
labels have been swapped with the relevel function. I realize it won't
affect any results and that the relevel did nothing useful in this
particular case. I'm just doing it to learn ways to manipulate factors.
The display of unclass leaves me feeling that the relevel had failed.
I've checked three books
2017 Jul 05
2
Svyglm Error
Greetings,
I am revisiting code from several different files I have saved from the past and all used to run flawlessly; now when I run any of the svyglm related functions, I am coming up with an error:
Error in model.frame.default(formula = F3ATTAINB ~ F1PARED, data = data, :
the ... list does not contain 4 elements
The following is a minimal reproducible example:
library(RCurl)
2013 Jan 16
1
equivalent code that doesn't return same results?
I need to automate changing the reference value for factors in analysis, and
it is my understanding that the following two sets of code should produce
identical results, but they do not:
1)dataset$method
2)eval(parse(text=paste("dataset",IVcat[k],sep="$"))) (in this case I
have IVcat[k]=method, which is why they are equal)
I even tested them in R, which says that these
2018 Oct 02
1
Relevel confusing with numeric value
Something that bit me:
The function relevel takes a factor, and a reference level to be promoted to the first place.
If ?ref? is a character this level is promoted, if it?s a numeric the ?ref?-th level is promoted.
Which turns out to be very confusing if you have factor with numeric values (e.g. when reading in a csv with some dirty numeric columns and stringsAsFactors TRUE)
For example:
2017 Jul 05
0
Svyglm Error
hi, i am not hitting an error when i copy and paste your code into a fresh
console. maybe compare your sessionInfo() to mine?
> sessionInfo()
R version 3.4.1 (2017-06-30)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows Server 2008 R2 x64 (build 7601) Service Pack 1
Matrix products: default
locale:
[1] LC_COLLATE=English_United States.1252
2017 Oct 28
2
HELP relevel INTERCEPT-COMPARISONS
Dear colleagues,
How can I do to "relevel" the intercept?
I need that the treatment "Db" be the intercept, and have p-values for the comparisons with the others treatments.
I used the function "relevel" but it did not work out to have what I want.
Thanks for your help,
Xavier
T1 <- read.table(file.choose(), h=T)
> head(T1)
treatment replicate Time
2012 Jan 16
2
Relevel dynamically
Dear list,
I am running R code which produces a data.frame with variable rows. For
plotting purposes I need to relevel
the column called "names" but since the dimension of the data.frame can vary
I do not know how to dynamically
revel the data.frame.
Here is an example data.frame called df to illustrate what I try to achieve:
> df <-
2011 Jan 10
1
debug biglm response error on bigglm model
G'morning
What does the error message "Error in x %*% coef(object) : non-
conformable arguments" indicate when calculating the response values
for
newdata with a model from bigglm (in package biglm), and how can I
debug it? I am attempting to do Monte Carlo simulations, which may
explain the loop in the code that follows. After the code I
have included the output, which shows that
2017 Oct 28
2
Function Relevel DOE NOT FOUND
Dear Forum,
Which functions and packages should be installed to make work the function "relevel"?
treatment<-revel(treatment,ref="Db")
Error: no se pudo encontrar la funci?n "revel"
Thank you very much for your help,
Xavier Chiriboga M.
PhD Candidate
Fundamental and Applied Research in Chemical Ecology Lab.
Institute of Biology
University of Neuchatel
2010 Nov 08
1
R help: reorder columns in an xyplot
Hello. First post, though I have read scores. Mostly i can solve my
problems reading the archives, but I lack the vocabulary to ask this one
right. Any social faux pais, I apologize.
I am sure this is a very basic question and I am embarrassed to ask, but I
spent several hours scouring the archives and trying various suggestions,
but I am too new to get any of them to work.
I am trying to
2010 Mar 25
3
Returning Data Frame from Function for use Outside Function
I have a function (see below) that does some bootstrapping (I am happy to
expand offline why I could use existing functions.) I put my results into
and empty matrix and add a row of results with each iteration. My problem is
i am a new user to R and I don't understand data frames, matrices, elements,
and vectors well. What I would like is to have a data frame I can manipulate
outside of the
2004 Dec 22
0
relevel expansion suggestion
To the R developers,
The discussion below reminded me that I think it might be a good idea
to take the Relevel function from the Lexis package and replace relevel
in stats with it. This is really nothing special for epidemiology.
It is fully compatible with the existing relevel (it actually contains
the
relevel code almost verbatim as a subset), but it has the extra
functionality
of combining
2011 May 08
1
Hosmer-Lemeshow 'goodness of fit'
I'm trying to do a Hosmer-Lemeshow 'goodness of fit' test on my logistic
regression model.
I found some code here:
http://sas-and-r.blogspot.com/2010/09/example-87-hosmer-and-lemeshow-goodness.html
The R code is above is a little complicated for me but I'm having trouble
with my answer:
Hosmer-Lemeshow: p=0.6163585
le Cessie and Houwelingen test (Design library): p=0.2843620
2012 Feb 03
1
ordering of factor levels in regression changes result
I was surprised to find that just changing the base level of a factor variable changed the number of significant coefficients in the solution.
I was surprised at this and want to know how I should choose the order of the factors, if the order affects the result.
Here is the small example. It is taken from 'The R Book', Crawley p. 365.
The data is at
2013 Mar 13
1
multi-comparison of means
Hi all:
I have a question about multi-comparison.
The data is in the attachment.
My purpose:
Compare the predicted means of the 3 methods(a,b,c) pairwisely.
I have 3 ideas:
#idea1
result_aov<-aov(y~ method + x1 + x2)
TukeyHSD(result_aov)
diff lwr upr p adj
b-a 0.845 0.5861098 1.1038902 0.0000001
c-a 0.790 0.5311098 1.0488902 0.0000002
c-b -0.055 -0.3138902
2004 Dec 22
4
ordering levels
Hello!
I would like to know if there is a simple way to reorder levels of a given factor.Let's say that the vector
testf<-factor(c("red","red","red","blue","blue","white"))
levels(testf) : blue red white
should have reordered levels such as
levels(testf) : red blue white
(this is for presentation purposes)
I guess
2012 Jul 04
2
Difference between two-way ANOVA and (two-way) ANCOVA
Hi!
as my subject says I am struggling with the different of a two-way ANOVA and
a (two-way) ANCOVA.
I found the following examples from this webpage:
http://www.statmethods.net/stats/anova.html
# One Way Anova (Completely Randomized Design)
fit <- aov(y ~ A, data=mydataframe)
# Randomized Block Design (B is the blocking factor)
fit <- aov(y ~ A + B, data=mydataframe)
# Two Way
2002 Feb 15
2
Reordering factor levels
I would like to define the order of the levels of a factor.
The relevel function would work but since I have 20 levels I would prefer
to declare the order explicitly. Using a smaller example
levels(oldfactor)
"b1" "b2" "r1" "r2"
nufactor <- order(oldfactor,order=c("b1","r1","b2","r2")) # my fabricated function