Displaying 20 results from an estimated 8000 matches similar to: "High l-avg with centos 4.8 on G2 only"
2005 Aug 16
1
preferences in used Compaq Proliant DL380 G1 vrs DL380 G2 etc
greetings,
for those of you in the know, may i have some assistance in helping to make
better decisions in purchasing more used server toys to install CentOS on
please? :-)
in the Compaq Proliant Rackmount DL380 line, the one that looks like the
older 1850R is called a G1 meaning Generation 1 right?
and then the DL380 G2 is a redesign that is gray and just has 6 drive bays
up front correct?
2006 Feb 02
3
ProLiant DL3n0 EMT64 - x86_64 or i686
Guys,
I'll be building a couple of DL360 G4p & DL380 G4 boxes soon and I've
not dealt extensively (i.e. at all) with any PC stuff that hasn't been
i386. I know the DL line pretty well but it was all G2/3.
So, question is, do I stick CentOS i386 or x86_64 on them? 2 boxes x
2GB RAM and 1 x 4GB, all SMP.
Will.
2005 Jan 03
20
TE410P card in an HP-Compaq DL380 G4 server
Hi,
Has anyone had success using a TE410P card in an HP-Compaq DL380 G4
server?
For me the card is detected fine, but the system just never sees an
interrupt from the card. I've tried everything I can think of. The card
definitely works.
Its Fedora Core, but we also tried a stock 2.6.10 kernel. We tried with
and without Hyperthreading, with "noapic", we disabled all the
2005 Feb 04
4
HP ProLiant server for Asterisk
I'm looking at ordering a server from HP. I checked around on Google
and found in the Wiki that the ProLiant DL380 is supposed to be known
to work with *.
I'm going to get a price quote on the following setup:
HP ProLiant DL380 G4 Server w/ the following options:
Intel Xeon 3.20GHz/1MB
2GB REG PC2-3200 (2 X 1GB)
HP ProLiant Battery Backed Write Cache Enabler for SA6i
RAID 1 drive set
HP
2005 Mar 07
1
[Fwd: RE: Re: TE410P card in an HP-Compaq DL380 G4 server]
Was there any resolution on this I also have a TE410P in an box with an
Intel E7501 chipset?
-Vickers
-------- Original Message --------
Subject: RE: [Asterisk-Users] Re: TE410P card in an HP-Compaq DL380 G4
server
Date: Tue, 8 Feb 2005 11:13:24 +1030
From: Peter Childs <peter.childs@nec.com.au>
Reply-To: Asterisk Users Mailing List - Non-Commercial Discussion
2007 Feb 09
1
HP DL380 G2 does not boot off local disk from PXE boot menu
Hi, all:
I can't make my HP DL380 G2 servers to boot off local disk by using
"default local" line in my PXE boot menu.
For fully automated server setups, I have configured all my DL380
servers to always do PXE boot. By manipulating the default boot option
in boot menu, I can control a server whether to install a new OS via
kickstart or just boot off local disk. This scheme works
2013 Jan 24
1
Pairwise Comparrisons
Dear all,
I''m trying to write a function, that will take as an argument, some aligned genome sequences, and using a sliding window, do pairwise comparisons of sequence similarity. Coding the sliding window I think I can manage but what I''m trying to get to grips with is getting it so as every pairwise comparison is made, no matter how many genomes are added, from 3 to N.
So if
2009 Jul 15
1
Help with averaging
Hi
I am using the following script to average a set of data 0f 62 columns into 31 colums. The data consists of values of ln(0.01) or -4.60517 instead of NA's. These need to be averaged for each row (i.e 2 values being averaged). What I would I need to change for me to meet the conditions:
1. If each run of the sample has a value, the average is
given
2. If only one run of the sample has a
2005 Jul 21
1
SOLVED: TE410P card in an HP-Compaq DL380 G4 server
Hi to all out there using HP DL380 G4 servers,
i found a way to get the Digium TE410P with older firmware running on a
HP-Compaq DL380 G4 Server! Here's the step-by-step description:
1. download the latest BIOS (in my case it was 4.04 from date:
06/02/2005) for
the HP-Compaq DL380 G4 using the
"Systems ROMPaq Firmware Upgrade Diskette for HP ProLiant DL480 G4 (P51)
Servers"
Link:
2005 Mar 29
5
pairewise plots
Dear R users,
I have a data generated as the following,
dat <- data.frame(matrix(sample(24), nrow=4))
dimnames(dat) <-list(rownames=c('g1','g2','g3','g4'), colnames=c("A_CH1","A_CH2","B_CH1","B_CH2","C_CH3","C_CH3"))
» dat
A_CH1 A_CH2 B_CH1 B_CH2 C_CH3 C_CH3
g1 16 24 7 9 14
2024 Jul 25
1
please help generate a square correlation matrix
?s 17:39 de 25/07/2024, Yuan Chun Ding via R-help escreveu:
> Hi R users,
>
> I generated a square correlation matrix for the dat dataframe below;
> dat<-data.frame(g1=c(1,0,0,1,1,1,0,0,0),
> g2=c(0,1,0,1,0,1,1,0,0),
> g3=c(1,1,0,0,0,1,0,0,0),
> g4=c(0,1,0,1,1,1,1,1,0))
> library("Hmisc")
> dat.rcorr =
2024 Jul 25
1
please help generate a square correlation matrix
Hi R users,
I generated a square correlation matrix for the dat dataframe below;
dat<-data.frame(g1=c(1,0,0,1,1,1,0,0,0),
g2=c(0,1,0,1,0,1,1,0,0),
g3=c(1,1,0,0,0,1,0,0,0),
g4=c(0,1,0,1,1,1,1,1,0))
library("Hmisc")
dat.rcorr = rcorr(as.matrix(dat))
dat.r <-round(dat.rcorr$r,2)
however, I want to modify this correlation calculation;
2012 Jan 24
4
Question
We were looking at conducting a pilot program with Dell to virtualize our lab environments. We are specifically looking at Dell/Citrix provisioning servers. The OS in this setup is streamed from the server on every boot. I was curious if the R Project had any licensing stipulations in this type of setup. This is in the beginning phases and we wanted to answer some questions about licensing.
2024 Jul 25
1
please help generate a square correlation matrix
HI Rui,
Thank you for the help!
You did not remove a row if zero values exist in both column pair, right?
Ding
From: Rui Barradas <ruipbarradas at sapo.pt>
Sent: Thursday, July 25, 2024 11:15 AM
To: Yuan Chun Ding <ycding at coh.org>; r-help at r-project.org
Subject: Re: [R] please help generate a square correlation matrix
?s 17:?39 de 25/07/2024, Yuan Chun Ding via R-help
2006 Feb 28
2
Problem with two cards Digium
Hello,
I`ve got a problem which I can`t deal with. I own 2 cards - TDM2400P and
TE410P. I`ve put them into a HP Proliant DL380 G4 server, compiled the
drivers according to the manual. Unfortunetly there are both cards
channels are configured in zaptel.conf file the first module (in this
file) sends an error.
For configuration:
span = 1, 1, 0, ccs, hdb3, crc4
fxsks = 21-24
bchan = 25-39,
2011 Apr 05
3
3.5 kernel panic on boot
Yes, I know 3.5 is old. However in this case it's required for a legacy
app.
a fresh install get's me:
kmod: failed to exec /sbin/modprobe -s -k block-major-104, errno = 2
followed by:
VFS: Cannot open root device "cciss/c0d0p2" or 68:02
The system is an HP DL380 G4. any thought on what could cause this?
the rescue system is able to mount the disk and grub-install
2004 Jul 30
2
pairwise difference operator
There was a BioConductor thread today where the poster wanted to find
pairwise difference between columns of a matrix. I suggested the slow
solution below, hoping that someone might suggest a faster and/or more
elegant solution, but no other response.
I tried unsuccessfully with the apply() family. Searching the mailing
list was not very fruitful either. The closest I got to was a cryptic
chunk
2024 Jul 25
1
please help generate a square correlation matrix
Hi Rui,
You are always very helpful!! Thank you,
I just modified your R codes to remove a row with zero values in both column pair as below for my real data.
Ding
dat<-gene22mut.coded
r <- P <- matrix(NA, nrow = 22L, ncol = 22L,
dimnames = list(names(dat), names(dat)))
for(i in 1:22) {
#i=1
x <- dat[[i]]
for(j in (1:22)) {
#j=2
if(i == j) {
#
2007 Jul 14
1
Kernel panic in ext3:dx_probe, help needed
This may or may not be ext3 related but I am trying to find any pointers
which might help me. I got a number of HP Proliant DL380 g5 with a P400
controller and also two qla2400 cards. The OS is RedHat EL4 U5 x86_64.
Every time during reboot these systems panic after the last umount and I
believe before the cciss driver is getting unloaded. The last messages I
am able to see are:
md: stopping
2017 May 15
2
Datos atómicos
Carlos:
Te agradezco mucho tu rápida respuesta y mucho me apena haber planteado tan
mal el problema. Porque la matriz en realidad es:
g1 g2 g3 g4 g5 g6 g7
g1 0 18 13 16 11 12 15
g2 18 0 25 13 22 16 10
g3 13 25 0 28 23 13 25
g4 16 13 28 0 6 7 3
g5 11 22 23 6 0 18 17
g6 12 16 13 7 18 0 8
g7 15 10 25 3 17 8 0
Entonces cada cantidad debe conservar la pertenencia al grupo