Displaying 20 results from an estimated 10000 matches similar to: "Binned line plot"
2005 Oct 05
1
(no subject)
hi all
why does the following not work???
this was someone elses code and i couldnt explain why it doesn't work.
m=matrix(c(0,0),2,1)
v=matrix(c(1,0,0,1),2,2)
Y=function(X1,X2,mu=m,V=v)
{
X=matrix(c(X1,X2),2,1)
a=(1/((2*pi)*sqrt(det(V))))*exp((-0.5)*(t(X-mu)%*%solve(V)%*%(X-mu)))
a[1]
}
x1=seq(-1,1)
x2=x1
Z=outer(x1,x2,FUN="Y",mu=m,V=v)
persp(x1,x2,Z)
my code:
2011 Aug 11
1
Splitting data
I want to implement the following algorithm in R:
I want to split my data, use a t test to compare both means of the groups to see if they significantly differ from each other. If this is a yes (p < alpha) I want to split again (into 4 groups) and do the same procedure twice, and stop otherwise (here the problem arises). As a final result I would have different groups of data.
I made some
2008 Jul 06
3
Lots of huge matrices, for-loops, speed
Hello,
we have 80 text files with matrices. Each matrix represents a map (rows for
latitude and columns for longitude), the 80 maps represent steps in time. In
addition, we have a vector x of length 80. We would like to compute a
regression between matrices (response through time) and x and create maps
representing coefficients, r2 etc. Problem: the 80 matrices are of the size
4000 x 3500 and we
2011 Nov 07
1
Graph binned data
I have a table that looks like this:
structure(list(speed = c(3,9,14,8,7,6), result = c(0.697, 0.011, 0.015, 0.012, 0.018, 0.019), house = c(1,
1, 1, 1, 1, 1), date = c(719, 1027, 1027, 1027, 1030, 1030),
id = c("1000", "10000",
"10001", "10002", "10003", "10004")), .Names = c("speed",
"result",
2012 Feb 07
5
Table rearranging
I have a table that looks like this:
measurement?? ?date??? door ?? color
0.93529385?? ?513?? ?open?? ?red
0.97419293?? ?420??? open ?? red
0.962053514?? ?513?? ?closed?? ?red
0.963909937?? ?1230?? ?open?? ?blue
0.97652034?? ?1230?? ?open?? ?green
0.989310795?? ?1230?? ?closed?? ?blue
0.9941022?? ?917?? ?closed?? ?yellow
I would like to create a table that has: Open measurement, Closed
2011 Aug 24
3
dput data frame
I have a data frame that is about 40 columns by 10000 rows. I want to get the dput of small portion of that by using dput(results[1:10,3:6]). The dput is very long and includes all the values from the original data frame. Why is that?
Jeffrey
2012 Jan 25
3
Gray levels
The gray (level) function returns different shades of gray, where level is a vector of numbers ranging from 0 to 1.? 0 is white and 1 is black and everything in between is a shade of gray.
Is there a function that will let me choose two different colors?? For example, a 0 might be blue and 1 might be red and in between might be a mix.
Jeffrey
2011 Aug 03
4
Convert matrix to numeric
I have a matrix that looks like this:
structure(c("0.0376673981759913", "0.111066500741386", "1", "1103",
"18", "OPEN", "DEPR", "0.0404073656092023", "0.115186044704599",
"1", "719", "18", "OPEN", "DEPR", "0.0665342096693433",
2011 Jul 30
4
Replacing null values
I would like to reorder a two-column table by column A, then fill column B with the values above it. For example: Original:A B2 545 NA8 784 NULL3 269 NULL First sort by column A:A B2 543 264 NULL5 NA8 789 NULL Then replace null/na values in column B with the value above it:A B2 543 264 265 268 789 78 What is the best
2011 Oct 20
2
Calculating differences
I have a table that looks like this:
structure(list(speed = c(3,9,4,8,7,6), C = c(0.697, 0.011, 0.015, 0.012, 0.018, 0.019), house = c(1,
1, 1, 1, 1, 1), date = c(719, 1027, 1027, 1027, 1030, 1030),
hour = c(18, 8, 8, 8, 11, 11), id = c("1000", "10000",
"10001", "10002", "10003", "10004")), .Names = c("speed",
2011 Aug 05
2
Aggregating data
I aggregated my data: aggresults <-aggregate(results, by=list(results$a, results$b, results$c), FUN=mean, na.rm=TRUE)
results has about 8000 lines of data, and aggresults has about 80 lines. I would like to create a separate variable for each of the 80 aggregates, each containing the 100 lines that were aggregated. I would also like to create plots for each of those 80 datasets.
Is
2010 Feb 16
3
error : unused argument(s) when boxplot
Dear all,
I am a total beginner in R, so sorry if this is the wrong place. I am using R 2.10.1 on a Mac (Mac OS 10.6.2).
I have this small dataset :
growth sugar
75 C
72 C
73 C
61 F
67 F
64 F
62 S
63 S
I have no problem reading the table, or getting the summary, but if I try boxplot(growth~sugar, ylab="growth", xlab="sugar", data=Dataset), I have the following error :
2010 Mar 10
2
ggplot2: "varwidth"-equivalent for geom_boxplot?
Hi,
Is there such a thing? If no: is it easily simulated?
thanks, Joh
2012 Jan 17
2
Display numbers on map
I have a text file with states and numbers. I would like to display each number that corresponds to a state on a map.
I am trying to use the maps package, but it doesn't show Alaska or Hawaii. Do you have suggestions on how to do this?
Jeffrey
[[alternative HTML version deleted]]
2011 Aug 02
1
Calculate mean ignore null
I have the following:
Tout = c(". ", ". ",
+ "-51.0", " -9.6", " -9.6", " -9.6", " -9.6", " -9.6", " -9.6",
+ " -9.6", " -9.5", " -9.5", " -9.6", " -9.5", " -9.6", " -9.6",
+ " -9.5", " -9.4", "
2012 Jan 10
2
Aggregate by minimum
For each date, I would like to keep the line with the lowest speed and discard the rest. The result would have one line for each date. Can I use aggregate for this?
My table is as follows:
structure(list(speed = c(3,9,14,8,7,6), result = c(0.697, 0.011, 0.015, 0.012, 0.018, 0.019), house = c(1,
1, 1, 1, 1, 1), date = c(719, 1027, 1027, 1027, 1030, 1030),
id = c("1000",
2011 Apr 07
1
dotplot as a background for multiple barchart plots (with Lattice)
Hi R users,
I'm kind stuck in my R experience...
I want to have a multiple barchart with n windows, but with the same
background for each window, and I want that background to be a recorded
dotplot.
First, is it possible ?
If so, I guess I have to call a record plot in the panel function but how ?
As there is no panel.plot and I can't use the recorded plot as an
argument for the
2008 May 23
2
Boxplot width
Hi there,
assume that you have data with different sampling like
d1 <- rnorm(100)
d2 <- rnorm(150)
now, I'd like to create two boxplots in one graph but each plot located at the
sampling number at the x-axis. This, I can do with "at"
l <- list(d1,d2)
boxplot(l, at=c(length(d1), length(d2)), xlim=c(0,200) )
but both plots are very thin and I'd like to increase the
2003 Sep 07
4
data manipulation
Hi,
I am new to R, coming from a few years using Stata. I've been twisting my
brain and checking several R and S references over the last few days to
try to solve this data management problem: I have a data set with a unique
patient identifier that is repeated along multiple rows, a variable with
month of patient encounter, and a continous variable for cost of
individual encounters. The data
2006 Oct 18
3
creating bins for a plot
Hi. I'm trying to plot the ratio of used versus unused bird houses
(coded 1 or 0) versus a continuous environmental gradient (proportion of
urban cover [purban2]) that I would like to convert into bins (0 -
0.25, 0.26 - 0.5, 0.51 - 0.75, 0.76 - 1.0) and I'm not having much luck
figuring this out. I ran a logistic regression and purban2 ends up
driving the probability of a box being