similar to: Problems Extension with a Call In on Asterisk 1.6

Hi i use this into my extension : exten => _00339xxxxxxxx,1,Set(foo=${SIP_HEADER(To)}) exten => _00339xxxxxxxx,2,Set(cut1=${CUT(foo,:,2)}) exten => _00339xxxxxxxx,3,Set(CLI=${CUT(cut1,>,1)}) exten => _00339xxxxxxxx,4,Set(toexten=${CUT(CLI,@,1)}) exten => _00339xxxxxxxx,5,Noop(ORIGINAL NUMBER : [ ${toexten} ]) exten =>

Hi all, Could anyone refer to me to a good source to learn how to program a simple control-flow construct* in R, or provide me with a simple example? Control-flow constructs are programmed as primitives, but I would like to be able to do that (if possible) in pure R. The general context is that those functions are a mystery to me. The motivating example is that I would like to create a function

Thanks a lot Jiefei, I had thought of defining a binary operator (inspired by pipes) or simply using an additional condition in the if() calls [e.g. if(foo & fn(bar)) doSomeThing; with fn(bar) returning a logical], but both are workaround that I do not find as elegant as a proper control-flow construct. Thus two questions remain: - is it possible to create a control-flow construct in pure R?

Hi, Currently my Xen server is working like a charm. I use Xen 3.2.1 with a Debian Etch Dom0 and Etch DomU. The VM have access to the network/internet using NAT. Each VM is given a virtual network interface and a private IP 10.0.0.x. What I would like to do know is that a VM can be directly accessible from another public IP. So my physical server is at 91.121.xx.xx. My VM is at 10.0.0.1 (on

Hi, I have a problem with a dom0 which is unable to launch my domU : all my dom0 are Debian Lenny amd64 with Debian kernel 2.6.26-2-xen-amd64 and xen-hypervisor-3.2-1-amd64. Then all domU (PV) are Debian Lenny amd64 too, with vanilla kernel 2.6.29.6. So, this new dom0 can''t launch any domU which are working on an other dom0. Software is same on both dom0, and hardware is near the

Hi Alexandre, I'm not an R expert so this is only my personal thought: I don't think you can achieve what you want exactly. A possible solution would be defining a binary operator %*%, where you can replace the asterisk with any function name you want. The function %*% is special since it has two arguments, left operand and right operand respectively. You then can call the `substitute`