similar to: 3Com 3102 Phones

Has there been any luck getting the 3Com NBX series phones to work with Asterisk? Thanks! -Andrew

How hard is it to integrate * into an existing 3com NBX setup? -Tim -------------- next part -------------- An HTML attachment was scrubbed... URL: http://lists.digium.com/pipermail/asterisk-users/attachments/20041004/bf01e3d9/attachment.htm

Hi, I've looked pretty wide on Google for this so I don't think it's been asked before. Has anyone had experience integrating Asterisk with a 3COM NBX system? The only way that I can see that looks possible is via the 3Com NBX ConneXtions H.323 product and then one of the H.323 Asterisk channels. Has anyone done this? Any pointers as to what to avoid or whether to even attempt it?

Hi All I have been looking around and haven not been able to find a working example I have a fresh/new install of Asterisk 1.6.2.0 with dahdi 2.2.1 and libpri 1.4.10.2 I use a sangoma A200 card so I am using wanpipe 3.4.7 If I use zaptel which I read I need for app_rxfax then asterisk crashes with segfaults on startup asterisk[2624]: segfault at 30353466 ip b7eb538b sp bffda26c error 4 in

Does anybody know if the 3com NBX 100 phones will work with Asterisk? The phones require a boot image to be sent either through layer2 or layer3 before they will function properly after being powered on each time. Thanks.

Hello, everyone, I am currently trying to get the asterisk server to talk with a 3COM NBX with T1 connection. My asterisk server has a T100p, TDM20B, a couple of sip phones. Now the sip phones are calling 3COM NBX phones fine, however, the analog phone has problem when dialing the NBX phones. The connection is established and the NBX auto-attendant picks up the call however the NBX end says that

Hi, I would like to simulate data with a binary outcome and a set of predictors that are correlated. I want to be able to fix the number of event (Y=1) vs. non-event (Y=0). Thus, I fix this and then simulate the predictors. I have 2 questions: 1. When the predictors are continuous, I can use mvrnorm(). However, if I have continuous, ordinal and binary predictors, I'm not sure how to simulate

Greetings, We are looking at installing a VoIP system with Asterisk and are currently looking at the line of 3Com phones. Has anybody had success with using the following phones? We need to buy a lot and we don't want to end up with phones that don't work properly with asterisk. 3Com 3101 (model with speakerphone) 3Com 3102 Business Phone 3Com 3103 Manager Phone 3Com 3105

Hi All I'm trying to get my Ultra UPS connected. It connects using a standard USB cable I have --with-drivers=hidups in the configure command and I have lsusb showing Bus 001 Device 002: ID 0d9f:0001 Powercom Co., Ltd Bus 001 Device 001: ID 0000:0000 I have /dev/usb/hiddev0 now matter what I try I keep getting upsdrvctl start Network UPS Tools - UPS driver controller 2.0.3 Can't

Hi All Curious will this work Std. PSTN line ---x------ X100p | ------ Fax Machine Using a standard "home phone" pstn line with a splitter connecting a fax machine and X100 Asterisk Box Incoming Line: Can I have in the dial Plan [incoming] exten => s,1,Wait(1) exten => s,2,IfFax continue to ring, so that the Fax Machine gets it exten

i am just curious how many * systems are in the real world with more than one user. do you run a certain version? you dont update CVS do you? any admins running a system of over twenty? over fifty? over one-hundred? i deal with 3com and nec systems all day (i am cerified in the 3com nbx advanced network telephony, elite voice mail, CCNA, A+, nec ipk, and soon to be "asterisk school of

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 <<insert bug report here>> Reproduced on Debian and Windows ... On 2.4.x if you execute set.seed(12345) t.1 <- rt(n = 1000, df = 20) set.seed(12345) t.2 <- rt(n = 1000, df = 20, ncp = 0) all.equal(t.1, t.2) ## Not close to true This appears to be due to the fact that in 2.4.x rt is now rt function (n, df, ncp = 0) { if

help(qt) states that: "ncp non-centrality parameter delta; currently except for rt(), only for abs(ncp) <= 37.62" so I would expect that calling qt with non-centrality parameter exceeding 37.62 should fail, instead e.g. calling > mapply(function(x) qt(p = 0.9, df = 55, ncp = x),35:45) gives: [1] 40.21448 41.35293 42.49164 43.68862 44.82945 45.97048 47.11170 48.25310 [9]

Dear my friends... I am still new in CentOS. I use CentOS 5 for my new server with cpanel. I have installed the cpanel. The steps were: 1. cd /tmp 2. wget http://layer1.cpanel.net/latest 3. sh latest The installation show a message that the cpanel installation was completed. But I can not see the cpanel login form on my server, either: "http://WWW.MYWEBSERVER.COM:2082" or:

The function 'pchisq' from the 'stats' library gives a wrong result if the argument equals exactly zero: # Upper tail of central 1-df chi^2 distribution > pchisq(1 , 1, ncp=0, lower.tail = F, log.p = FALSE) [1] 0.3173105 > pchisq(0.5 , 1, ncp=0, lower.tail = F, log.p = FALSE) [1] 0.4795001 > pchisq(0.01 , 1, ncp=0, lower.tail = F, log.p = FALSE) [1]

Bug Description: Problem with the function pf() when the non-centrality parameter is large. Here is a sample command. You should see a smooth line from 0 to about 55, and then the values of pf() go crazy from 55 to 100. ############################ ncp <- seq(0,100,length=200) plot(ncp,pf(5,7,2,ncp=ncp)) ############################ Version: platform = i686-pc-linux-gnu arch = i686 os =

Hello all, Here's my query: Running R 1.6.2 on FreeBSD 5.0, and on WinXP, and I find that the following hangs the process: dchisq(alpha=0.01, df=1, ncp=295) but it does work for ncp < 294.92. Is this general? Best wishes to all, Andrew Andrew Robinson Ph: 208 885 7115 Department of Forest Resources Fa: 208 885 6226 University of Idaho E : andrewr at uidaho.edu PO

Full_Name: Jerry W. Lewis Version: 2.6.1 OS: Windows XP Professional Submission from: (NULL) (24.147.191.250) pchisq(0,0,ncp=lambda) returns 0 instead of exp(-lambda/2) pchisq(x,0,ncp=lambda) returns NaN instead of exp(-lambda/2)*(1 + SUM_{r=0}^infty ((lambda/2)^r / r!) pchisq(x, df + 2r)) qchisq(.7,0,ncp=1) returns 1.712252 instead of 0.701297103 qchisq(exp(-1/2),0,ncp=1) returns 1.238938

Dear all, I want to see the source codes for "dchisq(x, df, ncp=0, log = FALSE)", but cannot find it. I input "dchisq" in the R interface, and then enter, the following message return: > dchisq /*****************************************************/ function (x, df, ncp = 0, log = FALSE) { if (missing(ncp)) .Internal(dchisq(x, df, log)) else

Dear List: The square of the noncentral t-statistic with noncentrality parameter \delta is a noncentral F with noncentrality parameter \lambda=\delta^2. So, t^2_{\nu,\delta} = F_{1,\nu,\lambda=\delta^2}. Consequently, it should follow that t^2_{1-\alpha/2,\nu,\delta} = f_{1-alpha,1,\vu,\lambda=\delta^2}. However, this is not what is happening with the following code. The central