similar to: French SIP or IAX phones

I''v finished the french translation of the QuickStart Guides named "Basic two-interface firewall" As i''v not found the email of Tom Eastep i post this news here. I''m translating now the "Standalone", and after i will do the "Three interface" If there is some french guys here, may be they can read to find some errors ?! :) cya -- VETSEL

Hi all, I am having a lot of trouble to get the default value of text fields when they are generated by a partial from a collection. I have been on this for a whole week and I didnt find a single exemple on the internet of someone using a partial that generate text field with a default value. I cant believe that I am the only one having this problem. Anyone has an exemple they can show me?

Hello, with a data.frame like this : > toto <- data.frame(id=c("id1","id1","id2","id3","id3","id3"),dpt=c("13","13","34","30","30","30")) > toto id dpt 1 id1 13 2 id1 13 3 id2 34 4 id3 30 5 id3 30 6 id3 30 what is the most efficient ways to obtain : id

Hi, how can i write this simple sentence : "Hello world" with "Hello" only in bold ? I try > plot(1:5) > title(main=paste(expression(bold("Hello")),"world",sep=" ")) but the result is wrong. thanks, Bruno Si vous n'etes pas destinataires de ce message, merci d'avertir l'expediteur de l'erreur de distribution et de le

Dear R-users, i have two questions : 1- first of all, i wish to know the way to obtain a serie with a format like "00" : ( "01","02","03","04"....) or like postal code ("01100","02222"). for instance, i do : > format(strptime(as.character(c(1:4)),"%H"),"%H") but it sounds complicate and not really

Hi, i have two data.frame x and y like : > x <- data.frame( num = c(1:10), value = runif(10) ) > y <- data.frame( num = c(6:10), value = runif(5) ) and i want to obtain something like : num.x value.x num.y value.y 1 0.38423828 NA 0.2911089 2 0.17402507 NA 0.8455208 3 0.54443465 NA 0.8782199 4 0.04540406 NA 0.3202252 5 0.46052426

I have been hearing a lot about the new Gnet SIP phones. Is anyone using them? How do they perform? Sean

Hello All, I am looking for a sip phone that is capable of automatic nat. The Cisco ata186 for example works fine for natting with iconnecthere, but as for asterisk, both my 7960 and polycom ip600 require you to set the nat ip on the tftp. Does anyone know a good phone (or ata) that can do this automatically? For example, I want to give a phone to my brother, who is going to europe. His ICH

Guys. What do I need to configure in order to let my Asterisk receive calls from sip phones, etc not registered with my server on my extension? For example, let people use their asterisks or sip phones to call blah111@server.com?

Some days ago there was a subject regarding BLF (SIP Phone-receptionist Setup). We are the developers of a Price Verify Terminal for a French company. We have developed the hardware (small board based on a PPC 823e), working with Linux embedded (based on Wolfgang Denk's work). I think that it can be a good BLF. Probably it is possible to integrate the Nicolas's FOP or a new application.

Hello everybody, i already searched the archieves, but i still don't know what is wrong in my implementation, mybe anybody coud give me some advice ll1<-function(rho,theta,beta1,beta2,beta3,beta4,t,Szenariosw5,Testfaellew5,X1,X2) { n<-length(t) t<-cumsum(t) tn<-t[length(t)] Szenn<-Szenariosw5[length(Szenariosw5)]

Hello. I was just brainstorming for a future project and was hoping to get some creative ideas from the list. If I have multiple * servers at multiple locations all connected together with a nicely partitioned dialplan (2XX for office 1, 3XX for office 2, etc.) it's pretty straightforward to link them all using IAX and allow intra-office transfers. Further, servers at each location are

Recientemente me intalaron la plataforma Platform: i686-pc-linux-gnu (32-bit). He intentado instalar el paquete dplR tanto desde el cran como desde un archivo y me da el siguiente error: ERROR: dependency ?XML? is not available for package ?dplR? Esto se debe a la versión de Linux que tengo instalada? gracias -- Ana Marina Srur Departamento de Dendrocronología e Historia Ambiental

Bueno, creo que no contesté tu pregunta. Con training <- data[-i, ] crea una df llamada training, sin la muestra i, que después utiliza para entrenar el algoritmo. Quoting Javier Marcuzzi <javier.ruben.marcuzzi en gmail.com>: > Estimado Manuel Mendoza > > Con sus datos y a modo de curiosidad, ¿que pasa en training <- data[-i, ]? > > Javier Rubén Marcuzzi >

Gracias Jorge. No entiendo bien; la variable objetivo es ya factor. El árbol me la predice bien, como factor, también. Es al ir construyendo el vector que lo anota con un nº, según de cuál de las 4 categorías se trate. Quoting Jorge I Velez <jorgeivanvelez en gmail.com>: > Estimado Manuel, > > Debes definir ecsta como factor usando, por ejemplo, > > factor(ecsta,

Hola, tengo un script para usar la función POSIXct y lo corro en otras computadoras con otras versiones de R y no tengo problemas ahora cuando lo corro en mi maquina donde tengo la versión 3.1.3 no me da ningun error pero genera una nueva columna con NA puede ser sólo problema de la versión de R? gracias ana -- Ana Marina Srur Departamento de Dendrocronología e Historia Ambiental

Gracias Carlos. No uso caret, pero lo miraré. Quoting Carlos Ortega <cof en qualityexcellence.es>: > Hola, > > Creo que si utilizas "caret" y en la función "trainControl()" defines "oob" > como criterio de randomización, puedes luego recuperar del objeto del > modelo, las predicciones individuales... > > Saludos, > Carlos Ortega >

Hi all, I need all your help on this. I have the next part of code:............e1=x1-mean(x1)e2=x2-mean(x2)n1=length(x1)n2=length(x2N=(n1 + n2)nu2=sum( c( ( x1 -mean(x1) )^2 , ( x2-mean(x2) )^2 ) )/Nss=c(e1,e2) b3= N*sum(ss^4)/ (sum( ss^2)^2)............what do lines 6-8 (mathematical notation)?Also the, what means part?............for(j in 1:B){ ss11=sample(x1, n1, replace=TRUE) ss12=sample(x2,

Gracias Javier, pero creo que si no consigo que me lo haga todo de una vez con un loop, me merece más la pena hacerlo como hasta ahora, una a una. Manuel Quoting Javier Marcuzzi <javier.ruben.marcuzzi en gmail.com>: > Estimado Manuel Mendoza > > No sería lo ideal, pero de pronto podría ir guardando en json, que es una > forma no estructurada, luego toma los datos

Hola de nuevo. Se me olvidaba la principal razón para utilizar gbm.step del paquete dismo. Como sabéis, los boosted si sobreajustan (a diferencia de los random forest o cualquier otro bootstrap) pero gbm.step hace validación cruzada para determinar el nº óptimo de árboles y evitarlo. Es fundamental. La opción que me queda, Carlos, es hacerlo con gbm, pero muchas veces, y usar el