Displaying 20 results from an estimated 500 matches similar to: "Simulation over data repeatedly for four loops"
2004 Sep 20
3
montecarlo simulation
Hy!
I would like to know how run a montecarlo simulation with R.
Thank you!!!!
Francesca Matalucci
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2012 May 18
3
How to fix indeces in a loop
Dear Contributors,
I have an easy question for you which is puzzling me instead.
I am running loops similar to the following:
for (i in c(100,1000,10000)){
print((mean(i)))
#var<-var(rnorm(i,0,1))
}
This is what I obtain:
[1] 100
[1] 1000
[1] 10000
In this case I ask the software to print out the result, but I would
like to store it in an object.
I have tried a second loop, because if I
2012 May 25
2
Collecting results of a test with array
Dear contributors
I have tried this experiment:
x<-c()
for (i in 1:12){
x[i]<-list(cbind(x1[i],x2[i])) #this is a list of 12 couples of time
series I am using to perform a test
} # that compares them 2 by 2
#
#################
#trace statistic
test<-data.frame()
cval<-array( , dim=c(2,3,12))
for (i in 2:12){
for (k in 1:2){
for (j in 1:3){
result[k,j,i]<-
2012 Jan 20
3
Istalling Ruby 1.9.2
I just installed 1.9.2 on my 2nd machine, but after I installed I checked
the version with ruby -v and it sent me 1.8.7
Here''s the terminal output...anyone know what''s wrong (I have RVM
installed):
Francescas-MacBook-Air:~ fkrihely$ rvm install 1.9.2
Fetching yaml-0.1.4.tar.gz to /Users/fkrihely/.rvm/archives
Extracting yaml-0.1.4.tar.gz to /Users/fkrihely/.rvm/src
Configuring
2011 Oct 03
2
Merge two data frames and find common values and non-matching values
Hi,
I am trying to find a function to match two data frames of different lengths
for one field only.
So, for example,
df1 is:
Name Position location
francesca A 75
cristina B 36
And df2 is:
location Country
75 UK
56 Austria
And I would like to match on "Location" and the output to be something like:
Name Position Location Match
francesca A 75 1
cristina B 36 0
I have tried with
2017 Oct 19
2
Select part of character row name in a data frame
Thanks a lot, so simple so efficient!
I will study more the grep command I did not know.
Thanks!
Francesca Pancotto
> Il giorno 19 ott 2017, alle ore 12:12, Enrico Schumann <es at enricoschumann.net> ha scritto:
>
> df[grep("strat", row.names(df)), ]
[[alternative HTML version deleted]]
2011 Jul 27
3
Reorganize(stack data) a dataframe inducing names
Dear Contributors,
thanks for collaboration.
I am trying to reorganize data frame, that looks like this:
n1.Index Date PX_LAST n2.Index Date.1 PX_LAST.1
n3.Index Date.2 PX_LAST.2
1 NA 04/02/07 1.34 NA 04/02/07 1.36
NA 04/02/07 1.33
2 NA 04/09/07 1.34 NA 04/09/07
2010 Jan 18
2
Rotating pca scores
Dear Folks
I need to rotate PCA loadings and scores using R.
I have run a pca using princomp and I have rotated PCA results with
varimax. Using varimax R gives me back just rotated PC loadings without
rotated PC scores.
Does anybody know how I can obtain/calculate rotated PC scores with R?
Your kindly help is appreciated in advance
Francesca
[[alternative HTML version deleted]]
2004 Mar 14
2
Shorewall 2.0.0
http://shorewall.net/pub/shorewall/shorewall-2.0.0
ftp://shorewall.net/pub/shorewall/shorewall-2.0.0
-Tom
--
Tom Eastep \ Nothing is foolproof to a sufficiently talented fool
Shoreline, \ http://shorewall.net
Washington USA \ teastep@shorewall.net
2024 Jun 13
1
Create a numeric series in an efficient way
I apologize, I solved the problem, sorry for that.
f.
Il giorno gio 13 giu 2024 alle ore 16:42 Francesca PANCOTTO <
francesca.pancotto at unimore.it> ha scritto:
> Dear Contributors
> I am trying to create a numeric series with repeated numbers, not
> difficult task, but I do not seem to find an efficient way.
>
> This is my solution
>
> blocB <- c(rep(x = 1,
2017 Oct 19
0
Select part of character row name in a data frame
(Re-)read the discussion of indexing (both `[` and `[[`) and be sure to get clear on the difference between matrices and data frames in the Introduction to R document that comes with R. There are many ways to create numeric vectors, character vectors, and logical vectors that can then be used as indexes, including the straightforward way:
df[ c(
"Unique to strat ",
"Unique
2024 Jun 13
1
Create a numeric series in an efficient way
Maybe this was your solution?
blocC <- c(rep(x=c(1:13), times=84))
blocC <- arrange(.data = data.frame(blocC), blocC)
The second line sorts, but that may not be needed depending on application. The object class is also different in the sorted solution.
Tim
-----Original Message-----
From: R-help <r-help-bounces at r-project.org> On Behalf Of Francesca PANCOTTO via R-help
Sent:
2004 Mar 23
1
help on data.frames/data.entry
Dear R-help,
I have a matrix D of dimensions 200 x 26; rows are my cases and columns are
my variables. I would like to create a data.frame "DF" with row.names=
myrownames (this is a vector of characters of length 200) and column names
"mycolnames" (a vector of characters of length 26). I could find the option
in data.frame for naming rows, but not for naming columns. So I
2013 Jan 27
2
Loops
Dear Contributors,
I am asking help on the way how to solve a problem related to loops for
that I always get confused with.
I would like to perform the following procedure in a compact way.
Consider that p is a matrix composed of 100 rows and three columns. I need
to calculate the sum over some rows of each
column separately, as follows:
fa1<-(colSums(p[1:25,]))
fa2<-(colSums(p[26:50,]))
2017 Oct 19
2
Select part of character row name in a data frame
Dear R contributors,
I have a problem in selecting in an efficient way, rows of a data frame according to a condition,
which is a part of a row name of the table.
The data frame is made of 64 rows and 2 columns, but the row names are very long but I need to select them according to a small part of it and perform calculations on the subsets.
This is the example:
X Y
"Unique to
2012 Apr 14
2
master thesis
Hi,
For my master thesis I have 24 micro-plots on which I did measurements during 3 months.
The measurements were:
- Rainfall and runoff events throughout 3monts (runoff being dependant on the rainfall, a coefficient (%) has been made per rainfall event and per 3 months)
- Soil texture (3 different textures were differentiated)
- Slope (3 classes of slopes)
- Stoniness (one time measurement)
2011 Nov 11
8
Help
Dear Contributors
I would like to perform this operation using a loop, instead of repeating
the same operation many times.
The numbers from 1 to 4 related to different groups that are in the
database and for which I have the same data.
x<-c(1,3,7)
datiP1 <- datiP[datiP$city ==1,x];
datiP2 <- datiP[datiP$city ==2,x];
datiP3 <- datiP[datiP$city ==3,x]
datiP4 <-
2005 May 27
3
Re: Shorewall development web site (Mike Noyes)
Hello,
I leave for a couple days .. (Well months) and look at what has
happened. :-)
I would throw my support in behind Xoops .. to be honest ..
If a portal is what we are trying to achieve here.
I just happen to think that sometimes .. More work goes into web design
etc than goes into actual Code.
But thats because I am a lamer at web design :-)
I am coming in here a bit late .. But tell
2024 Sep 16
2
(no subject)
Dear Contributors,
I hope someone has found a similar issue.
I have this data set,
cp1
cp2
role
groupid
1
10
13
4
5
2
5
10
3
1
3
7
7
4
6
4
10
4
2
7
5
5
8
3
2
6
8
7
4
4
7
8
8
4
7
8
10
15
3
3
9
15
10
2
2
10
5
5
2
4
11
20
20
2
5
12
9
11
3
6
13
10
13
4
3
14
12
6
4
2
15
7
4
4
1
16
10
0
3
7
17
20
15
3
8
18
10
7
3
4
19
8
13
3
5
20
10
9
2
6
I need to to average of groups, using the values of column
2012 Dec 13
2
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University of Oxford, UK
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