similar to: last observation carried forward +1

Dear R users, I'm happy to announce the release of version 0.3 of the udpipe R package on CRAN (https://CRAN.R-project.org/package=udpipe). The udpipe R package is a Natural Language Processing toolkit that provides language-agnostic 'tokenization', 'parts of speech tagging', 'lemmatization', 'morphological feature tagging' and 'dependency parsing' of

Dear R users, I'm happy to announce the release of version 0.3 of the udpipe R package on CRAN (https://CRAN.R-project.org/package=udpipe). The udpipe R package is a Natural Language Processing toolkit that provides language-agnostic 'tokenization', 'parts of speech tagging', 'lemmatization', 'morphological feature tagging' and 'dependency parsing' of

Hi! Is there a possibilty in R to carry out LOCF (Last Observation Carried Forward) analysis or to create a new data frame (array, matrix) with LOCF? Or some helpful functions, packages? Karl --------------------------------- Gesendet von http://mail.yahoo.de Schneller als Mail - der neue Yahoo! Messenger. [[alternative HTML version deleted]]

Hi, I have a series of id's with multiple visits and questionnaire scores. This is a clinical trial that will be analyzed using the last observation carried forward method. In other words, in order to comply with intent to treat analysis when many subjects withdraw, data points for the last visit must be generated and filled in with the last observation. The ultimate goal is to tabulate the

Dear R gurus, I am trying to overload some operators in order to let these work with the ff package by registering the S3 objects from the ff package and overloading the operators as shown below in a reproducible example where the "*" operator is overloaded. require(ff) setOldClass(Classes=c("ff_vector")) setMethod( f="*", signature = signature(e1 =

Hello R users, I'm pleased to announce the release of version 0.2 of the textrank package on CRAN: https://CRAN.R-project.org/package=textrank *The package is a natural language processing package which allows one to summarize text by finding* *- relevant sentences* *- relevant keywords* This is done by constructing a sentence network which finds how sentences are related to one another

Hello R users, I'm pleased to announce the release of version 0.2 of the textrank package on CRAN: https://CRAN.R-project.org/package=textrank *The package is a natural language processing package which allows one to summarize text by finding* *- relevant sentences* *- relevant keywords* This is done by constructing a sentence network which finds how sentences are related to one another

Hi everybody, I have a small question about the function "na.locf" from the package "zoo". I saw in the help that this function is able to fill NA gaps with the last value before the NA gap (or with the next value). But it is possible to fill my NA gaps according to the last AND the next value at the same time? Actually, I want R to fill my gaps with the method of

Dear useRs, I very much like the effect display of the proportional odds model on page 29 (Figure 8) of the following paper by John Fox: http://socserv.mcmaster.ca/jfox/Papers/logit-effect-displays.pdf It really gives a very concise overview of the model. I would like to use it to illustrate the proportional odds mixed models we fit here for a project on Diabetes but I can't seem to reproduce

Dear R-users, Is there a way to get p-values for a one-sided hypothesis test about a poisson mean? Thanks, Jan Wijffels University Center for Statistics W. de Croylaan 54 3001 Heverlee Belgium tel: +32 (0)16 322784 fax: +32 (0)16 322831 <http://www.kuleuven.be/ucs> http://www.kuleuven.be/ucs Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm [[alternative HTML version

Hello, I have a series of intraday (high-frequency) price data in the form of POSIX timestamp followed by the value. I sucesfuly loaded that into "its" package object. I would like to create from it a regularly spaced time series of prices (for example 1min, 5min, etc apart) so i could calcualte returns. There is an interpolation function locf() that for timestamp with value NA uses last

Hi I'm quite new to optimization algorithms and I could use some advice or pointers. I'm using ?optim (method L-BFGS-B) to optimize a function over a 60-dimensional parameter space. The function itself takes about 1 to 6 minutes to compute. It finds an optimum after 6 tot 24 hours, depending on the problem I need to solve. For me, speed is an issue and I would like to reduce this to 1

I have this little data.frame http://dl.dropbox.com/u/102669/nanotna.rdata Two column contains NA, so the best thing to do is use na.locf function (with fromLast = T) But locf function doesn't work because NA in my data.frame are not recognized as real NA. Is there a way to substitute fake NA with real NA? In this case na.locf function should work Thank you

I'm sure I'm being stupid so flame away... R2.2.1 on Windoze (boohoo) latest updates of packages. I'm exploring a dataset (land) with three variables looking at an narrowly unbalanced two group (GROUP) ANCOVA of a randomised controlled trial analysing endpoint score (SFQ.LOCF.ENDPOINT) entering the baseline score (SFQ.BASELINE) as covariate and the following work fine: > res.same

Hi, We recently switched from R2.7.0 to R2.8.1 but having problems tracking down this 'invalid multibyte character' encoding issue. Can someone point us how to solve this? > sessionInfo() R version 2.8.1 (2008-12-22) x86_64-unknown-linux-gnu locale:

Hi all, I have a vector like this: x<- c(0.7, 0.1, 0, 0.2, 0.2, 0, 0, 0 , 0, 0.4, 0, 0.8, 1.8) I would like to replace the zero values with the first previous non zero value. my returning vector should look like this: y<-c( 0.7, 0.1, 0.1,0.2,0.2,0.2,0.2,0.2, 0.4, 0.4, 0.8, 1.8) How can I do this in R without using for loop? Thank you

Hi, dat1<- read.table(text=" id??????????????? t???????????????????? scores 2???????????????? 0??????????????????????? 1.2 2???????????????? 2???????????????????????? 2.3 2???????????????? 3??????????????????????? 3.6 2???????????????? 4??????????????????????? 5.6 2???????????????? 6??????????????????????? 7.8 3???????????????? 0??????????????????????? 1.6 3????????????????

Dear R-users, Does anyone of you have binary files for the packages rpart.permutation, snow and rsprng. I would like to use them in my classification tree. I know they are still at the 0.x development stage, though. Where can I get information on how to compile tar.gz files? I'm using windows XP with R 2.1.0. Thanks, Jan --------------------------------------------------------------------

Hello, I have logging information for multiple machines, which I am trying to summarize and graph. So far, I process each host individually, but I would like to summarize the user count across multiple hosts. I want to answer the question "how many unique users logged in on a certain day across a group of machines"? I'm not quite sure how to scale the data frame and analysis to

Hi R helpers, If I have a dataset looks like: ID record 1 20 . 30 . 25 2 26 . 15 3 21 4..................... And I want it becomes ID record 1 20 1 30 1 25 2 26 2 15 3 21 4..................... That is, I have to duplicate IDs for those with multiple records. I am wondering it is possible to be