similar to: Data

I have an R script with the following applicable lines: xshort <- window(s, start=st, end=ed) . . . xshort <- ts(xshort, frequency=1, start=1) . . . m1 <- m2 <- m3 <- m4 <- m5 <- m6 <- NULL m1 <- tslm(xshort ~ trend) I get an error: Error in get(dataname) : object 'xshort' not found When I do traceback() I get: 3: get(dataname) 2: tslm(xshort ~

At 10:37 PM 5/1/00 -0400, E. S. Venkatraman wrote: >I have the following problem. I have survival data (time, status) along >with several covariates (X1, X2,..., Xn). I want to fit a Cox model for >each of the covariate (univariately) and obtain the fitted probability of >survival at a fixed time point t0 and covariate value Xi0. I tried to do >this in a for loop where the index

I have been using R the past couple of years to run models on data we are collecting. I recently got a new computer and updated to a new version of R (2.60 -> 2.90). Since the update, I cannot get my syntax to run. I have tried copying the file it is looking for into many different directories to try and run it. In the last version, I found that it was easiest if the file was copied into the R

I am writing a function where the arguments are names of objects or variable names in a data frame. To convert the strings to the objects I am using eval(parse(text=name)): f.graph.two.vbs<-function(dataname,v1){ val<-paste(dataname,v1,sep="$") val<-eval(parse(text=val)) val } However running this returns an error:

The generic rule is that R is not a macro language, so looping of names of things gets awkward. It is usually easier to use compound objects like lists and iterate over them. E.g. datanames <- paste0("aa_", 2000:2007) datalist <- lapply(datanames, get) names(datalist) <- datanames col1 <- lapply(datalist, "[[", 1) colnum <- lapply(col1, as.numeric) (The 2nd

Hi R-users! Being new to R, and a fairly advanced Stata-user, I guess part of my problem is that my mindset (and probably my language as well) is wrong. Anyway, I have what I guess is a rather simple problem, that I now without success spent days trying to solve. I have a bunch of datasets imported from Stata that is labelled aa_2000 aa_2001 aa_2002, etc. Each dataset is imported as a matrix, and

Hi! Thanks for the replies! I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The syntax from Peter Dalgaard was really clever, and I learned a lot from it, even though it didn't solve my problem (I guess it wasn't very well explained). My problem was basically that I have a data matrix

Um, if you insist on doing it that way, at least use assign(varname, as.vector(get(varname))) -pd > On 4 Dec 2017, at 22:46 , Love Bohman <love.bohman at sociology.su.se> wrote: > > Hi! > Thanks for the replies! > I understand people more accustomed to R doesn't like looping much, and that thinking about loops is something I do since I worked with Stata a lot. The

Dear R-devel, I've made some potential extensions to writeForeignSAS in 'foreign' that I wanted to pass along if anyone is interested. I've attached the diff -u output against the version found in foreign_0.8-15 and an .R file with my changes. (In this .R file, the function is named writeForeignSAS7 to simplify testing/comparisons.) I've tried to alter the current

I have a dataframe with names in the first column and wait times between decisions in the second column. Since individuals make multiple decisions, I want the average for each individual. For example, the data might look like this name wtime jo 1 jo 2 jo 1 jo 3 tim 3 tim 2 tim 2 ro 1 ro 2 etc. I'm hoping there is something like mean(dataname$wtime[name]) which will just

:-) I don't insist on anything, I'm just struggling to learn a new language and partly a new way of thinking, and I really appreciate the corrections. I hope I someday will be able to handle lists in R as easy as I handle loops in Stata... Thanks again! Love -----Ursprungligt meddelande----- Fr?n: peter dalgaard [mailto:pdalgd at gmail.com] Skickat: den 4 december 2017 23:09 Till:

library(survival) library(boot) data=NULL lambda=NULL result=NULL pat=rep(1:102,each=1) trt=rep(c(1,0),51) status=rep(1,102) site=rep(1:51, each=2) nr.datasets=100 seed=2006 beta=log(1/2) for (i in 1:51) { lambda[i]=1+((3-1)/50)*(i-1)} lambda1=rep(lambda, each=2) dummy=rep(c(exp(beta),1),51) elf=lambda1*dummy r=70 #the number of bootstrap replicates

Loops are not evil, and no-one in this thread said they are. But I believe your failure to provide a reproducible example is creating confusion, since you may be using words that mean one thing to you and something else to the readers here. ################################ # A reproducible example includes a tiny set of sample data # Since we cannot reproducibly refer to filenames (your

Full_Name: John P Cavanaugh Version: .99 OS: linux Submission from: (NULL) (24.116.10.99) dataset$ema12 <- EMA (dataset$Close,12) dataset$ema26 <- EMA (dataset$Close,26) dataset$MACD_fast <- dataset$ema26 - dataset$ema12 dataset$MACD_slow <- EMA(dataset$MACD_fast,9) dataset$MACD_hist <- dataset$MACD_fast - dataset$MACD_slow # This line doesnt work!!! But... if I does work if I

Hello, I'm using library(spatstat) and trying to use ppp on my dataset. I get a segmentation error when I try to run it. Any suggestions? Code below ... Thanks, Suzanne --------------------------------------- dat <- read.delim(file="trees_R2.csv", sep=",", header=1) P16 <- (dat$Plot == "P1") | (dat$Plot == "P2") | (dat$Plot == "P3")

Dear R users I get a weired problem when use sink: since the data set pretty big, I sink intermediate result for further use,following lines are consistently used when write data ########################### sink("dataname.txt") data sink() ########################## at first couples of run, all 10 variables are wrote to a file in following format: V1 V2 ....... V10 1

when i try to validate my logistic regression model: fit<-glm(y~x,binomial,data=dataname,x=TRUE,y=TRUE) validate(fit,method="boot",B=150,...) i get the following error message: Error in UseMethod("validate") : no applicable method for "validate" any insight would be appreciated. many thanks! -- View this message in context:

My question is about the write.foreign() command in the foreign package. I use a command like the following to try and output data and a code file to read my data into SAS. write.foreign(data.frame.object, datafile="filepath", codefile="filepath", package="SAS", dataname="myData") With my data set, it gives the following error: Error in

Hi experts, I have a problem in Write.foreign command (SAS). I have a data frame called d. >d Datetime 2006-12-01 00:00:00 2006-12-01 00:10:00 2006-12-01 00:20:00 2006-12-01 00:30:00 2006-12-01 00:40:00 >class(d$Datetime) [1] "POSIXt" "POSIXct" Then I tried with, write.foreign(d,"Z:\\try_i.sas7bdat"," Z:\\try_i.sas

By the way, R 'vectors' are not the equivalents of mathematical 'vectors'. In R, a vector is something that can have arbitrary length and which has no 'attributes', other than perhaps element names. Vectors can be numeric, character, complex, lists, etc. Functions, names, and NULL are not vectors. In my opinion, the typical data scientist will rarely find the R vector