similar to: doveadm who

Hello Giovanni I made a minor modification to your function, which now allows to compute the within R-sq in Twoways Within models (see below). However I ran into an issue that I have already encountered before: whenever I try to fit Twoways Within models on my unbalanced data, the process is strangely slow and I usually terminate it either after ~15min or when my CPU hits 100C. This is similar to

Previously Dovecot has shown shared INBOX like: * LIST (\HasChildren) "/" "shared/tss2" * LIST (\HasNoChildren) "/" "shared/tss2/INBOX" * LIST (\HasNoChildren) "/" "shared/tss2/foo" The last change in hg makes it return simply (same as with Cyrus): * LIST (\HasChildren) "/" "shared/tss2" * LIST (\HasNoChildren)

Pascal Volk writes: >> EXAMPLE >> Move janes messages - received in September 2011 - from her >> INBOX into her archive. >> >> doveadm move -u jane Archive/2011/09 mailbox >> 2011-10-01 SINCE 01-Sep-2011 >> >> [Is this a typo: "2011-10-01" should be "INBOX"?] >> ? > > Where did you

Pascal Volk writes: >> Cut&pasted off the terminal man page output. Looking into >> man1/doveadm-move.1, I see >> >> .B doveadm move \-u jane Archive/2011/09 mailbox INBOX BEFORE \(rs >> .B 2011-10-01 SINCE 01-Sep-2011 >> >> so it's a problem with my nroff, not dovecot's man pages. (Hmm, it >> happens with groff too -- it appears

Dear Michael, One key is adjustment of nls optimizer tolerance. I notice it has to be higher than usual, but, I recovered your noisy "known" parameter values with an error of K1 (-7%) and k1 (-6%): #### Miller problem with Dalgaard modifications ## Linares 1/22/2004 ## Solution 1 nls(noisy ~ lsoda(xstart, time, one.compartment.model, c(K1=K1, k2=k2))[,2], data=C1.lsoda,

Hi, I have a density that I need to get MLEs from, which includes definite integrals both in the denominator and in the numerator of the density function. It looks like the outcome depends on the initial values given. My program is shown below: library(circular) ######################################## 4 parameters ######################################## z<-rvonmises(100,0,1)

Hi, I'm trying to backup a remote directory. Although the remote directory hasn't been changed after rsync's run, I realize that the supposed synchronization missed some files. Does it have to do with rsync or I miss something ? Thanks very much, Mihai. ______________________________ quad ...lu2/BACKUP/k2/mnt/i1/vbs# rsync -av --stats rsync://mlozo@k2/vobuser/user

Hi.. i have an expression of the form: model1<-nls(y~beta1*(x1+(k1*x2)+(k1*k1*x3)+(k2*x4)+(k2*k1*x5)+(k2*k2*x6)+(k3*x7)+(k3*k4*x8)+(k3*k2*x9)+(k3*k3*x10)+ (k4*x11)+(k4*k1*x12)+(k4*k2*x13)+(k4*k3*x14)+(k4*k4*x15)+(k5*x16)+(k5*k1*x17)+(k5*k2*x18)+(k5*k3*x19)+

Hi I want to sum over one of the dimensions of a n x k1 x k2 array in which each column is the product of the corresponding columns from two matrices with dimensions n x k1 and n x k2. I can see two approaches: a loop on k1 and a loop on k2. But I cannot figure a solution that avoids the loop? Is it possible? (I don't refer to apply or lapply etc either as they are just hidden loops so,

Hello...i want to find the empirical rate for type 1 error using fixed trimmed mean. To make it easy, i'm referring to journal given by this website http://www.academicjournals.org/ajmcsr/PDF/pdf2011/Yusof%20et%20al.pdf. I already run the programme and there is no error in it but i got zero for the empirical rate of type 1 error. The empirical rate for the type 1 error given in the journal

Hello, I also have problems to get to run the following lines. If I run the block instead of every single line, it simply does not wait for the input. Can anybody help me? ------------------------ pos_name <- readline("Please type: ") r <- substr(pos_name, 1,1) c <- substr(pos_name, 2,nchar(pos_name)) ------------------------ Thank you! Antje Peter Dalgaard schrieb: >

Hi, The code below is giving me this error message: Error in while (err > eps) { : missing value where TRUE/FALSE needed In addition: Warning messages: 1: In dnbinom(x, size, prob, log) : NaNs produced 2: In dnbinom(x, size, prob, log) : NaNs produced I know from the help files that for dnbinom "Invalid size or prob will result in return value NaN, with a warning", but I am not able

Error in model.frame When I run the following nls model an error message appears and I dont know how to solve that. Could you help me?? mat = c(1,2,3,4,5,6,7,8,9,12,16,24,36,48,60) for (i in 1:length(j30)) { bliss = nls(c(j[i,1:length(mat)]) ~ b0 + b1*((1-exp(-k1*mat))/(k1*mat)) + b2*(((1-exp(-k2*mat))/(k2*mat))-exp(-k2*mat)), start = list(k1=0.1993, k2=0.1993, b0= 22.0046,

Hello, I haven't found errors in your code. I implemented the test in the paper (the first, fixed symetric mean) and it also gives me zero Type I errors, when alpha = 0.05. Try to see the value of min(pv) or to plot the histogram of 'pv', hist(pv) and you'll see that there are no significant p-values, at that level. Anyway I'll continue to look at it, but my first

Hi, I've seen various posts on this question, but still can't get the code right. If I run the following code one line at a time, it works fine. If I run it together as a block, however, it doesn't wait for the input and gives an error. There must be a way to have are pause/wait for an answer, but I can't seem to find it. Thanks! J Code: choosefunction <-

Hi All, I'm looking for how to enable SIP Markers, or specifically, how to have the TIME reset when a call route changes. I'm debugging an issue, where a sip client we have switching to one-way-audio, when an asterisk server fruther down the call path dials out to the PSTN. Scenario is: SIP Client -> A*k1 -> A*k2 -> PSTN Provider/Gradwell -> O2 -> Mobile

http://dovecot.org/releases/2.0/alpha/dovecot-2.0.alpha2.tar.gz http://dovecot.org/releases/2.0/alpha/dovecot-2.0.alpha2.tar.gz.sig Changes since alpha1: - All debug messages are now logged to debug log (debug_log_path setting, defaults to info_log_path). Patch by Pascal Volk. - Added support for SORT=DISPLAY IMAP extension. - Added doveadm who command for listing currently logged in users.

Hi everyone! I'm matching two samples to create one sample that have pairs of observations equal for the k1 variable. Merge() doesn't work because I dont't want to recycle the values. x <- data.frame(k1=c(1,1,2,3,3,5), k2=c(20,21,22,23,24,25)) x y <- data.frame(k1=c(1,1,2,2,3,4,5,5), k2=c(10,11,12,13,14,15,16,17)) y merge(x,y,by="k1") k1 k2.x k2.y 1 1 20

Jim has been exceedingly patient (and may well continue to be so), but this smells like "failure to launch". At what point will you start showing your (failed) attempts at solving your own problems so we can help you work on your specific weaknesses and become self-sufficient? -- Sent from my phone. Please excuse my brevity. On February 25, 2018 7:55:55 AM PST, Val <valkremk at

comp_keys is duplicating what is done in btrfs_comp_cpu_keys, so just call it. Signed-off-by: Diego Calleja <diegocg@gmail.com> --- fs/btrfs/ctree.c | 14 +------------- 1 file changed, 1 insertion(+), 13 deletions(-) Index: linux/fs/btrfs/ctree.c =================================================================== --- linux.orig/fs/btrfs/ctree.c 2009-07-24 00:47:20.936410297 +0200 +++