similar to: Plotting a gragh or histogram in a certain colour

Dear Sir, How do I change the intervals on the x axis of a histogram plot; let us say for example the intervals were 0,5,10,15,and 20, and I wanted to change the intervals to 0,2,4,6,8,10,12,14,16,18,20. I look forward to receiving your words of wisdom. Ivo [[alternative HTML version deleted]]

Dear Sir, I am doing some work on a population of patients. About half of them are admitted into hospital with albumin levels less than 33. The other half have albumin levels greater than 33, so I stratify them into 2 groups, x and y respectively. I suspect that the average length of stay in hospital for the group of patients (x) with albumin levels less than 33 is greater than those

Hello there, I have a bunch of histogram bars that I'd like the first to be a certain colour, second to be another colour, third to be a third colour, and repeat for all my 39 bars. I thought this was the way to go, but I get the same cyan coloured bars for all the bars. I did a vector of 3 colours, hoping it'd recycle them for the other bars. > levels(forPlot$type) [1]

Hello. I am sorry for posting a (seemingly) simple question, but I have just spent 2 hours trying to find the answer, without success. I want to make a histogram with conditioning on a factor, using Trellis graphics. However, I do not want any colours (only black and white) either in the histograms or in the strip. There must be some simple argument but I can’t find it. Here is my code so

Dear Sir, I am facing the same problem you were discussing here: https://www.redhat.com/archives/libvirt-users/2015-January/msg00070.html I am getting this error: Starting install... ERROR internal error: unable to execute QEMU command 'qom-list': The command qom-list has not been found Domain installation does not appear to have been successful. If it was, you can restart your domain

I am trying to do a histogram lattice plot and I would like the histogram to be filled with a different colour in each panel. Note: I want every bar in each histogram to be the same colour, but that there should be different colours *between* histograms. Can't seem to get this to work. I thought that something like the following would be a goer: set.seed(42) X <- rnorm(200) A <-

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I'd like to be able to colour histograms along the diagonal using the colours stored in colnames(d): > d black blue brown cyan 1 0.96405751 -0.02964390 -0.060147424 -0.06460070 2 -0.03614607 0.95475444 -0.152382053 -0.07767974 3 -0.07095613 -0.05884884 -0.061289399 -0.06445973 4 -0.03708223 -0.05997624

Hi, I am having some trouble trying to plot a histogram in more than one colour. What I want to do is, plot two vectors in the same histogram, but with different colours, for instance: > x <- rnorm(1000,20,4); > y <- rnorm(1000,10,2); Then I'd like to have x and y ploted on the same hist (I can do that already doing w <- c(x,y) then hist(w)) but the bars

On Tue, Jun 23, 2015 at 03:41:45PM +0200, Michal Privoznik wrote: > On 23.06.2015 14:16, Ivo Hora wrote: > > Dear Sir, > > > > I am facing the same problem you were discussing here: > > https://www.redhat.com/archives/libvirt-users/2015-January/msg00070.html > > > > I am getting this error: > > Starting install... > > ERROR internal error:

Dear R developers---I just spent half a day debugging an R program, which had two bugs---I selected the wrongly named variable, which turns out to have been a scalar, which then happily multiplied as if it was a matrix; and another wrongly named variable from a data frame, that triggered no error when used as a[["name"]] or a$name . there should be an option to turn on that throws an

On Fri, 27 Jan 2023 at 20:42, Diogo Ivo <diogo.ivo at tecnico.ulisboa.pt> wrote: > > On Fri, Jan 27, 2023 at 04:00:59PM +1000, Ben Skeggs wrote: > > On Fri, 20 Jan 2023 at 21:37, Diogo Ivo <diogo.ivo at tecnico.ulisboa.pt> wrote: > > > > > > On Wed, Jan 18, 2023 at 11:28:49AM +1000, Ben Skeggs wrote: > > > > On Mon, 16 Jan 2023 at 22:27, Diogo

Given a data frame with a continuous variable and a factor. I would like to generate a histogram of the continuous variable, where each bar is filled with different colors according to the percentage of factor values falling into this region of the continuous variable. I looked into packages like 'lattice' and 'ggplot2'. Searching R-help revealed that 'histogram' is

Dear R wizards: is there a clean way to assign to elements in a list? what I would like to do, in pseudo R+perl notation is f <- function(a,b) list(a+b,a-b) (c,d) <- f(1,2) and have c be assigned 1+2 and d be assigned 1-2. right now, I use the clunky x <- f(1,2) c <- x[[1]] d <- x[[2]] rm(x) which seems awful. is there a nicer syntax? regards, /iaw ---- Ivo Welch

Dear Sirs, I have an old but very well-working UPS MGE Pulsar ESV8+ Rack. I'd like to use it to power FreeBSD 9.0-Rel server. Of fortunately I have problem with recommended driver - mge-utalk, nut 2.6.4 (installed from FreeBSD Ports). I get messages: Could not get multiplier table: using raw readings. and updateinfo: Cannot update system status I saw similar thread on mailing list with no

Dear R experts--- Has anyone written parallel versions of "by" (i.e., mcby) and "ave" (i.e. mcave) ? I did ask a question like this a year ago, and then the answer was no. for those who are googling the group for the answer to this question, in the meantime, the poor man's version of "by" is mclapply( split( ds, factor ), FUN ) I don't know the poor

Please compare samples: http://www.ivo.pl/ivo2/sound/krwawa_org.wav http://www.ivo.pl/ivo2/sound/krwawa_fixed.wav http://www.ivo.pl/ivo2/sound/krwawa_float.wav krwawa_org.wav is original file. Both output files was created using same program by compressing from wav to speex, then decompressing from speex to wav (using speex_encode_int and speex_decode_int). Only difference was used speex

dear R experts---I am struggling with the requirements to prepare my files for my printers. I am printing in 2/2 format, which means cyan and black for me, which they take from my color-separated pdf files. R comes into play, because it produces all the figures that are embedded in my book (pdflatex). now, TeX has no problems producing CMYK files. However, R produces RGB files (for

dear R experts---I am using the coef() function to pick off the coefficients from an lm() object. alas, I also need the standard errors and I need them fast. I know I can do a "summary()" on the object and pick them off this way, but this computes other stuff I do not need. Or, I can compute (X' X)^(-1) s^2 myself. Has someone written a fast se() function? incidentally, I think

The treatment of dates seems to be a little inconsistent in R 2.11.1 (2010-05-31): [1] The choice of origins? > as.integer(as.Date("1970-01-01")) works and assumes as origin 1970-01-01. However, > as.Date(1) does not work. It requires an origin (as.Date(1, origin="1970-01-01")). If we set a default origin in the former, it should probably work when the input

dear R experts---now I have a case where I want to estimate very large regression models with many fixed effects---not just the mean type, but cross-fixed effects---years, months, locations, firms. Many millions of observations, a few thousand variables (most of these variables are interaction fixed effects). could someone please point me to packages, if any, that would help me estimate such