similar to: Model Formulae Evaluation

Hello i have installed dovecot from rpm found on rpm.pbone.net 1.2.17-0_115.el5 Everuthing works as charm Postfix + Dovecot + TLS + MySQL/postfixadmin For Reference: Centos 5.6 postfix 2.3.3-2.2 dovecot 1.2.17-0_115.el5 spamassassin 3.2.5-1.el5 postfixadmin 2.3.3 amavisd-new 2.6.4-4.el5.rf Now i'm trying to install Sieve for Dovecot 1.2 to make it redirect spam in proper folders but getting

Dear R Users: I have a list function as: Flat: y = 0 Linear: y = -(1.65/8)d Logistic: y = 0.015 - 1.73/{1+exp[1.2(4-d)]} Umbrella: y= -(1.65/3)d + (1.65/36)d^2 Emax: y = -1.81d/(0.79+d) Sigmoid Emax: y = -1.70d^5/(4^5+d^5) And want draw the figure as attached (those material are extracted from a paper). Could anyone give me a sample code to do this? Thanks

Hi I can do this: formula = as.factor(outcome) ~ . in glm and other model building functions. I think there is a way to get the product of the determinants (that is d1 * d2, d1 * d3, etc) and also another way to get all the polynomials (that is like poly(d1,2) would produce for a single determinant). Can anyone tell me how you write them? Stephen [[alternative HTML version deleted]]

[ I'm teaching log-linear models at present, and looking at Agresti's book. ] Often when producing analyis of variance or analysis of deviance tables it is important to get effects fitted in a specific order. At present in S / R this is done as follows: anova( glm( terms(formula, keep.order=T), ...) ) Can anyone think of a reason why keep.order should not become an argument to

I'd like to check within a whether an argument is a formulae of the type ~X or similar. What's the right way to do so? I'm using: is.language(obj) but not sure this is right Thanks in advance P.J. Paulo Justiniano Ribeiro Jr Dept Maths & Stats - Fylde College Lancaster University Lancaster LA1 4YF - U.K. e-mail: paulojus at est.ufpr.br http://www.maths.lancs.ac.uk/~ribeiro

Hi, I'm a new user of R and I'm trying to make a linear model from this kind of dataset x [1] 16.87 19.93 25.85 20.94 17.06 19.49 19.93 25.45 27.74 20.15 25.81 21.06 17.17 20.03 25.50 27.79 20.44 16.88 19.93 25.79 z<-x-10 y [1] 0.80 1.27 2.22 1.32 0.90 1.18 1.84 2.41 2.97 1.25 2.07 1.41 1.14 1.66 2.59 3.51 1.53 0.81 1.26 2.30 plot(x,y) I want to be able to force the line of

I have seen, several times, dots (like this: "y ~." ) in formula descriptions, noticeably in R help. I am unable to see what it does correspond to. Any ideas ? -- --~~ Toulouse, Grenoble, Auch, Arcachon, B??ziers, Paris, Saragosse, L??vignac Sur Save, habitats naturel du Valdo. ~~-- < http://www.le-valdo.com>

Hi, Is there a way of annotating a ggplot plot with mathematical formulae? I can do geom_text(aes(label="some text", ... but I can't do geom_text(aes(label=expression(x^{n-1}), ... It gives the error Error: geom_text requires the following missing aesthetics: label Is there a convenient equivalent? Cheers, Paul

Dear R Mailing Subscribers, I just have a question of how R handles interacting variables in model creation using glm for instance. if I write : >> model=glm(solution~descriptor1+descriptor2+descriptor3,family=binomial(link="logit")) I should end up with coefficients for a logistic model that I can introduce easily in the mathematical form of such a model (weighted sum of

Hi, This is a problem about writing R documentation (R-exts 2.6). The command "\deqn" defined in "Rd.sty" is: \newcommand{\deqn}[2]{\[#1\]} which will put mathematical formulae in the "displaymath" environment; that means line breaks are not allowed (or will not be shown) in formulae, but sometimes we do need multiple lines of formulae. One solution is to write

Hello, I would like to implement the feature request described here: https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=13287. I think this is a very worthwhile feature. However, I need just a little push in the right direction. When I added either a new command or change the old one to use eqnarray as proposed, the "\\" newline characters were not properly passed to latex - even

Hello again, It appears that get_all_vars() incorrectly handles model formulae that use a right-hand side (rhs) matrix. For example, consider these two substantively identical models: # model using named variables mpg <- mtcars$mpg wt <- mtcars$wt hp <- mtcars$hp m1 <- lm(mpg ~ wt + hp) # model using matrix y <- mtcars$mpg x <- cbind(mtcars$wt, mtcars$hp) m2 <- lm(y ~ x)

Dear all, I have a very rudimental function which takes a vector of terms and returns a list of all possible models which can be made using the given terms. For example for the set c("1", "x", "y", "x:y") I'd get: ~ 1 ~ x ~ y ~ x:y ~ 1 + x ~ 1 + y ~ 1 + x:y ~ x + y ~ x + x:y ~ y + x:y ~ 1 + x + y ~ 1 + x + x:y ~ 1 + y + x:y ~ x + y + x:y ~ 1 + x + y +

Hi, all Does anybody know if it is possible to include TeX-style formulae in R plots? The aim is to export such plots to LaTeX documents using the postscript() device. Many thanks in advance, Alberto Munoz --------------------------------------------------------------------- Alberto Munoz Phone: +34-91- 624 95 79 Dpto. de Estadistica y Econometria Fax: +34-91- 624

I am attempting to extract the derivative/ gradient from this expression df1p <- deriv(f1, "P") > df1p expression({ .value <- s - c - a * P .grad <- array(0, c(length(.value), 1L), list(NULL, c("P"))) .grad[, "P"] <- -a attr(.value, "gradient") <- .grad .value }) So in this case I want to extract the "-a".

What is a good way to enter a very long model formula. For example: y ~ Input.2 + Input.3 + ... + Input.1000 (assuming the corresponding dataframe has many other columns). Is there a way to convert a character string to a formula? Are there command line expansions in R besides the simple '.'? Thanks. [[alternative HTML version deleted]]

Hi all, I wonder if you could help me with (what is surely) a simple R question? I've written a simple R script (attached) to perform multiple ANOVAs on the columns in a table loaded in from a a file (also attached). I loop through the list of columns for which I want to perform the ANOVAs, storing the column name in a variable. When I try to perform the ANOVA using the variable name as a

Dear List The UKgas data is stored as an object of class 'ts'. I am trying to use "UKgas" in a formula as argument to a function. However, I do not know how to access the 'time series' information in the response (such as start() end() etc.). Here is a boiled down example. ssm <- function(formula, data = list(),subset=NULL) { cl <- match.call() if

Hi, Given that R reports Type I sums of squares, isn't it a bit anachronistic that it re-orders terms in formulae? > d <- expand.grid(y=rnorm(8), + A=factor(c(1,2)), + B=factor(c(1,2)), + C=factor(c(1,2))) > summary(aov(y ~ A+B+A:B+C,data=d)) Df Sum Sq Mean Sq F value Pr(>F) A 1 8.294e-34 8.294e-34 1.027e-33 1

Hi All, I have a formula which has a factor with NAs in it. I wish to keep these in the model matrix, but the NA information is currently lost (the rows are kept but the NA gets converted to 0). Any ideas as to how I can keep NAs in? e.g. junk <-