similar to: Help creating a scatterplot with errorbars using gplot

Hi, Does anyone know how i get rid of the marker point in my error bars? The bars default function (it seems) is to have a dot in the middle of the bar, however i don't want it there. I am using Hmis to draw my errorbars and code is a<-as.vector(tapply(Sporangia,list(Host,Isolate),mean)) b<-as.vector(tapply(Sporangia,list(Host,Isolate),sd)) c<-sqrt(b/36)

Hi everyone, I'm very new to R and I like to learn a lot... actually I have a little problem concerning errorbars with xyplot. My data look like run target hemi x 1 1 Nichts Links 0.0007743240 2 2 Nichts Links -0.0008153365 3 1 Target Links -0.0015825950 4 2 Target Links 0.0088743785 5 1 Nichts Rechts 0.0015898995 6 2 Nichts Rechts -0.0011465190 7 1

Dear all I have six variables of the average metal concentrations Var1 4.77 Var2 23.5 Var3 5.2 Var4 12.3 Var5 42.1 Var6 121.2 I want to plot them as a barplot with error bars. Could you help me? Cheers Maria [[alternative HTML version deleted]]

Hi, i'm using this lines of code: dodge <-position_dodge(width=0.9) ggplot(dfm,aes(x = X,y = value)) + geom_bar(aes(fill = variable), position=dodge, stat="identity") + geom_errorbar(aes(ymin=value-er, ymax=value+er),width=0.25, position=dodge,stat="identity") to plot this data frame X variable value er 1 A X4 58.74 9.44 2 B X4

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

Hello, I'm new to this and am trying to teach myself some R by plotting biological data. The growth curve in question is supposed to be fitted to the Verhulst equation, which may be transcribed as follows: f(x)=a/(1+((a-0.008)/0.008)*exp(-(b*x))) - for a known population density (0.008) at t(0). I am trying to rework the example from "An Introduction to R" (p. 72) for my case and

Hi All, Can anyone show me how to add a error bar to my graphs. I am currently using this code g<-ggplot(means,aes(x=variable,y=value)) > g<-g+geom_bar(stat="identity")+facet_wrap(~Site+Season) > g Thanks, Akaalz [[alternative HTML version deleted]]

Here is my code, which plots three lines with errorbar. How could I add an extra line without errorbar to the plot? Thank you very much. beta.data <- data.frame ( method = rep(c("Wrong", "Correct", "Full Bayes"), each = T_obs), mean.beta = c(mean.beta1, mean.beta2, mean.beta3), t = rep(points, 3), std.beta = c(std.beta1, std.beta2, std.beta3) ) limits =

Hi all, I couldn't install gplots package. > install.packages("gplot") Warning message: package 'gplot' is not available (for R version 3.0.2) i want to use heat maps.2 function. can you please tell me how to install this package or are there any alternatives. Thanks in advance :) [[alternative HTML version deleted]]

Hi there, I have two questions about heatmap.2 in gplot. My input is a simple square matrix with numeric values between 75 and 100 (it is a similarity matrix based on bacterial DNA sequences). 1. I can sort my input matrix into categories with rowsidecolors (in this case, very conveniently by bacterial taxa). I do a clustering and reordering of my matrix by Rowv=TRUE (and

Hi all, i installed the ggplot2 package via install.packages(), but the gplot function was not recognized in R console command. Is there any paths to configure? The error message reports that the function was not found. Thanks Ricardo ____________________________________________________________________________________ Be a better friend, newshound, and

Hi, I am drawing a heat map using gplots of R package. The file (new4) is having values 0 and 1 only. library(gplots) library(marray) x=read.table("new4", header=TRUE) mat=data.matrix(x) heatmap.2(mat, col=colorRampPalette(c("black","red"))(256), #col=greenred(75), Rowv=TRUE, Colv=TRUE, distfun = dist, hclustfun = hclust, dendrogram = c("row"), scale =

I am getting following strange error : library(sn) library(ggplot2) dat1 <- as.matrix(rsn(1000, 0, 1, 0))[,1] ggplot() + geom_histogram(aes(x = dat1, y = ..density.., fill = ..count..)) + xlab("Distribution") + scale_y_continuous("") Error: No data for layer Can anyone please tell me why it is coming? -- View this message in context:

Hi, Would like to use to the hexbin package to plot a 2D hist - because it looks really _cool_. My problem is related to drawing a pdf hexbin graphic in series of other graphics. All other figures have a par(mar=c(3.2,3.2,1,1)). So the gplot.hexbin figure in this series looks a little alienated? Was trying a to specify the _mar_ using par, viewport, hexViewport etc. a little. My question. How

I can save to png, TIFF and jpg but get an error "Error: invalid graphics state" when trying to save as pdf and I have to restart R. This happens when I add mtext lines. There are a few other questions e.g. I want to move the mtext on side 1 to the left, but that is the main issue for now. I'm not using the ylab inside gplot.hexbin because it writes over the numbers on the axis.

Hi Everyone, I would like to add errorbars to a lattice plot. I already have a function that adds error bars to a plot (originally written by George Gilchrist) which takes as arguments the coordinates of the point and then the size of the error bar. I would like to integrate it in my lattice code but I seem to be stumped. I can put the error bar function inside my code as if it were a panel

Dear R-Listers, I am very confused with what seems to be a misuse of the faceting options with gplot function and I hope you might help me on this. z contains various simulation results from simulations with different set of parameters. I melt my data to have the following data.frame structure : > str(z) 'data.frame': 12383 obs. of 5 variables: $ vID : num 1 2 3 4 5 6 7 8

Hi, I have a data set with two continous variables that I want to plot MEANS (I am not intrerested in median values) on a double-y graph. I also have 2 factors. I want the factor combinations plotted in different panes. Dummy dataset: mydata <- data.frame(factor1 = factor(rep(LETTERS[1:3], each = 40)), factor2 = factor(rep(c(1:4), each = 10)), y1 =