similar to: transpose ?

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Dear All, I apologize for this trivial question, I can not find the solution I try to use t.test function per line in the data.frame, But i dont'understand the error message my program is as follows group1<-gl(2,20) fun<-function(x){ m<-data.frame(group1,x) #anova(aov(x ~ group1, m)) t.est(x ~ group1,m) } ttest<- apply(data, 1, fun) Error in t.test.default(x = c(1, 1,

HI, Dear R community, My original file has 1932 lines, but when I read into R, it changed to 1068 lines, how comes? cdu@nuuk:~/operon$ wc -l id_name_gh5.txt 1932 id_name_gh5.txt > gene_name<-read.table("/home/cdu/operon/id_name_gh5.txt", sep="\t", skip=0, header=F, fill=T) > dim(gene_name) [1] 1068 3 -- Sincerely, Changbin -- Changbin Du DOE Joint Genome

Hi, I''m having a dataframe ''Subset1'' with a number of factor variables and 160 numerical variables Now I want to make sums for all rows that have the same values for the different factor variables, except for the factor variables: VAR1,VAR2,VAR3 who may have the same values. With the formula given below this works great, but in a situation with 15000 rows and 13

Dear r-help, Could you help me to find a solution for this error: Il y a eu 50 avis ou plus (utilisez warnings() pour voir les 50 premiers) > warnings() Messages d'avis : 1: In if ((data[pa, k] == df[, j]) & (data[ch, k] == i)) { ... : la condition a une longueur > 1 et seul le premier élément est utilisé 2: In if ((data[pa, k] == df[, j]) & (data[ch, k] == i)) { ... : la

I have a data frame called "pose": DESCRIPTION QUANITY CLOSING.PRICE 1 WHEAT May/10 1 467.75 2 WHEAT May/10 2 467.75 3 WHEAT May/10 1 467.75 4 WHEAT May/10 1 467.75 5 COTTON NO.2 May/10 1 78.13 6 COTTON NO.2 May/10 3 78.13 7 COTTON NO.2 May/10 1 78.13

Howdy, R Grues I have enjoyed R, but I cannot solve one problem easily. Please help my problem. When I tried the R script, I got the following Error. This error results from input data file exported through a Excel spreadsheet software. Error in step(lm(pop.rate ~ as.numeric(year) + as.factor(policy) + as.numeric(nation.grant) + ?: ??number of rows in use has changed: remove missing values?

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Hi all Assume I have a data set xx; Group: 1=group1 ?, 2=group2 IQ: ?1= High, 0 =low fit <- glm(IQ ~group, data = xx, family = binomial()) summary(fit) Results ?????? ????????????Estimate Std. Error z value Pr(>|z|) (Intercept) -2.55456??? 0.210 -12.273? < 5e-16 *** group????????? 0.36180 ?????0.076?? 3.952 ????5.24e-05 *** the odd ratio = exp(0.36180 )= 1.435912 My question

Dear all, Lets say I have a data frame as follows: > Date <- as.Date(c('2006-08-23', '2006-08-30', '2006-09-06', '2006-09-13', '2006-09-20')) > Income <- c(73.79, 72.46, 76.32, 72.43, 72.62) > data.frame(Date, Income) Date Income 1 2006-08-23 73.79 2 2006-08-30 72.46 3 2006-09-06 76.32 4 2006-09-13 72.43 5 2006-09-20 72.62 >

Dear All, I have matrix (50000 X 60) of subjects and their responses to a set of questions. All responses are classified into categories (500). I would like to average all subject's responses for each category. I wrote a code using a for loop but is not working. Could please tell me what's wrong with the code? I guess, there is a elegant R way of doing the same thing. Thanks in advance.

Hi all, I wanted to have a seasonality study like whether a particular month has significant effect as compared to others. Here is my data : 0.10499 0 0 1 0 0 0 0 0 0 0 0 0.00259 0 0 0 1 0 0 0 0 0 0 0 -0.06015 0 0 0 0 1 0 0 0 0 0 0 0.10721 0 0 0 0 0 1 0 0 0 0 0 0.03597 0 0 0 0 0 0 1 0 0 0 0 0.10584 0 0 0 0 0 0 0 1 0 0 0 0.02063 0 0 0 0 0 0 0 0 1 0 0 -0.03509 0 0 0 0 0 0 0 0 0 1 0 -0.03485 0 0 0

Hi, I'm trying to find an easy way to do this. I want to select the top three values of a specific column in a subset of rows in a data.frame. I'll demonstrate. A B C x 2 1 x 4 1 x 3 2 y 1 5 y 2 6 y 3 8 I want the top 3 values of B from the data.frame where A=X and C <2 I could extract all the rows where C<2, then sort by B, then take

Hello, Let's assume that one has a list: my.list <- list(a=c(1,2,3,4),b=4,c=c(1:7)) I want to save my.list as a matrix in .txt file. Because of different length we can put NA or 0. Effect (row.names a, b and c are not necessary) a 1 2 3 4 0 0 0 b 4 0 0 0 0 0 0 c 1 2 3 4 5 6 7 How to do it? Thank you. Robert

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I am sorry if this is documented in apply's dcumentation or completely obvious, I could not find or work it out. Given an matricies Q: 2x3, R:1x3 and S:1x2 apply(Q, 1, '-', R) is 3x2 and apply(Q, 2, '-', S) is 2x3 Why? cheers Worik > Q [,1] [,2] [,3] [1,] 1 2 3 [2,] 10 11 12 > R [1] 1 4 7 > S [1] 1 4 > apply(Q, 1, '-', R) [,1]

hello, everybody, i have several unresolved issues: 1. how to do a matrix transpose? i cant find how to do it in the documentation. 2..suppose i have an object named as lm1 from linear regression, how could i refer to it by paste("lm",1,sep="") ? 3. to save a matrix 100 x 30, how to have a text file with 100 lines and 30 cols, instead of stacking them? thanks. best regards

Hello, I would like to switch this dataframe: > k country 1960 1961 1962 1963 99 ARG 7493 7733 7581 7108 246 AUS 10484 10342 10809 11357 295 AUT 7438 7808 7938 8212 393 BDI 587 502 555 608 442 BEL 8223 8638 9021 9311 in this structure: year ARG AUS AUT BDI BEL 1960 7493 10484 7438 587 8223 1961 7733 10342 7808 502 8638 1962 7581 10809 7938 555

Hi Listers, Is there a way that I can transpose an array... Suppose I have the following array... x<-array(c(1,2,3,4),dim=c(1,2,2)) , , 1 [,1] [,2] [1,] 1 2 , , 2 [,1] [,2] [1,] 3 4 And I would like to get the following result... , , 1 [,1] [1,] 1 [,2] 2 , , 2 [,1] [,2] [1,] 3 [,2] 4 Thanks in advance, Marcio -- View this message in context: