similar to: Remove all whitespaces

Displaying 20 results from an estimated 4000 matches similar to: "Remove all whitespaces"

2010 Dec 08
3
Dont print plot on screen
Hi is there any command or setting that allows you to do the plot command but it dose not print the plot on screen? So when you are saveing an plot in a function you dont want it to display the plot just save it. -- View this message in context: http://r.789695.n4.nabble.com/Dont-print-plot-on-screen-tp3078167p3078167.html Sent from the R help mailing list archive at Nabble.com.
2011 May 04
1
Str info. Thanks for helping
It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others
2010 Dec 08
5
Summing up Non-numeric column
Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive
2011 Apr 20
2
user input
Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the
2010 Dec 13
7
descriptive statistics
Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:
2010 Dec 06
1
Loading .RData from Internet
Dear All, Can you please suggest me a correct way to load the following R data frame from the internet and save it to the hard drive? The following is what I tried: > raceprofiling <- > read.table("http://rss.acs.unt.edu/Rdoc/library/twang/data/raceprofiling.RData") > save(raceprofiling, file = 'raceprofiling.RData') However, when I used dim() to check the dataset,
2010 Dec 07
3
string
Hi, I'm running R 2.11 Does anyone know if it possible to transform one character vector to one character string ? Many thanks Benoit -- Benoit Wastine Laboratoire des Sciences du Climat et de l?Environnement (LSCE/IPSL) CEA-CNRS-UVSQ CE Saclay Orme des merisiers B?t 703 - Pte 13A 91191 Gif sur Yvette Cedex France Tel : 33 (0)1 69 08 21 97 Fax : 33 (0)1 69 08 77 16
2011 Jan 18
2
dataframe: string operations on columns
Dear all, how can I perform a string operation like strsplit(x," ") on a column of a dataframe, and put the first or the second item of the split into a new dataframe column? (so that on each row it is consistent) Thanks Boris
2011 Feb 02
1
combining vectors into list
Hi R users I have these two vectors: Row <- sample(1:25, 10) Col <- sample(1:25, 10) Is there a way to combine them into a list, whose first component is a vector containing the first element of Row and the first element of Col, the second component is a vector containing the second element of Row and the second element of Col, and so on... Thanks you Lorenzo
2011 Feb 28
1
Replacing an element in a vector
Dear R helpers I seem to have one trivial problem but can't find solution to it. Suppose I have following input. A = c(1,  3,  0,  5,  8)                  # 3rd element is 0 B = c(100, 30,  0,  25,  40)          # 3rd element is 0 C = A/B > C [1] 0.01 0.10  NaN 0.20 0.20 Obviously, I can't divide 0/0 and hence NaN. My problem is how to replace this NaN say by 0. So that I can
2011 Mar 09
1
Getting the source file's name where the custom function is written
Dear R experts, I've written some functions in a few source files (such as main.R, control.R ...). After loading them into R, how do I retrieve which functions are loaded from which source file? For example: main.R has functions: myPrint(), myScan() control.R has functions: setPrinter(), setData() After loading the sources (main.R and control.R) into R, I would want to know that
2011 Mar 10
1
How to use conditional statement
Dear R helpers Suppose val1 = c(10, 20, 35, 80, 12) val2 = c(3, 8, 11, 7) I want to select either val1 or val2 depending on value of third quantity val3. val3 assumes either of the values "Monthly" or "Yearly". If val3 = "Monthly", then val = val1 and if val3 = "Yearly", then val = val2. I tried the ifelse statement as ifelse(val3 =
2011 Mar 28
2
deleting the first two characters in each row of a factorized column
Hello, I'd like to ask you something again. I have a database and it has a column which looks like this one here: small_factor <- factor(c("d_variable1","d_variable2","d_variable3")) small_factor Now the thing is that I would like to convert each element of this factorized column. Basically I want to rewrite the words in it without the first two characters:
2011 Apr 19
1
Reducing dimension of a list object
Hi all, I generally use the Reduce() function to reduce the dimension of list object. However in my current session I have few objects which are actually list of list of list..(say n step). If I reduce their dimension then I have call Reduce() function many times. Therefore my question is, is there any 1-step way to reduce the dimension at the lowest level? Take this example: lis1 <-
2011 Mar 04
1
column removing under certain conditions
Dear collegues! Given a matrix, I would like to remove columns, that do not fulfill a certain condition. The condition is, that the median of the column is higher than a certain value. I've seen the help on removing NA columns, but I cannot figure out how to change the function part of the statement, so that the function is only TRUE if the median of the column is higher than x;
2011 Feb 03
2
how to read the "Sum Sq" - column from summary.aov()
Dear R-Users, I have a trivial problem, but extensive googling and ??'ing did not solve it: I want to obtain the sums of squares from a summary.aov() object for later use. Example: > DV <- rnorm(100) > IV1 <- as.factor(rep(c("male", "female"), times = 50)) > IV2 <- as.factor(rep(c("young", "old"), times = 50)) > >
2011 Jan 17
2
Finding NAs in DF
Hi, What is an efficient way to take this DF data.frame(A=c(1,2,NA,NA),B=c(1,NA,NA,4)) and get c(NA,"TWO","BOTH","ONE") as the result, where NA corresponds to a row without "NA"s, TWO indicates NA in the second and ONE in the first column. Thanks for any pointers. Joh
2011 Apr 06
1
syntax to subset for multiple values from a single variable
Hi All, Is it possible to use the subset() function to select data based on multiple values of a single variable from a data frame. My actual data set is much bigger and would like to illustrate with following dataset > df = data.frame(x = c('a','b','c','d','e','f','g','h','a','a','b','b'), y =
2010 Dec 01
1
missing values
Dear all, i have spent a lot of time trying to solve this problem, but I am sure that there must be a simple solution. So, as a last resort, I am coming back to you again. I have a dataset with some (almost random) values in many variables. Lets say that the dataset represents the scores of students to test questions. What I need to do is to sum the scores for each student. However, wherever
2011 Jan 12
3
Outputting csv file from dataframe with columns in a particular order
I have a dataframe with columns "ID",'date","estimate","actual" (but not necessarily in that order - I do a merge somewhere and that somehow messes up the order of the columns). How can I output it to a csv file with the columns in the order that I want? Thanks.