similar to: Reducing dimension of a list object

Dear all, please consider my following workbook: library(zoo) lis1 <- vector('list', length = 2) lis2 <- vector('list', length = 2) lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1) lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency = 12) lis2[[1]] <- matrix(1:40, 20) lis2[[2]] <-

Dear all, I'm a newbie to R and I would really apperciate any help with the following: I have two lists, l1 and l2: l1: $"A*0101" [1] 0.076 0.109 0.155 0.077 0.09 0 0 0.073 [9] 0.33 0.0034 0.0053 $"A*0247" [1] 0 0 0.5 .004 0 0 0 $"A*0248" [1] 0 0 0.3 0 0.06 .... l2: $"A*1101" [1] 0.17 0.24 0.097 0.075 0.067 $"A*0247" numeric(0)

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear All, Can you please suggest me a correct way to load the following R data frame from the internet and save it to the hard drive? The following is what I tried: > raceprofiling <- > read.table("http://rss.acs.unt.edu/Rdoc/library/twang/data/raceprofiling.RData") > save(raceprofiling, file = 'raceprofiling.RData') However, when I used dim() to check the dataset,

Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive

Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

Dear List: I am generating N datasets using the following Sigma<-matrix(c(400,80,80,80,80,400,80,80,80,80,400,80,80,80,80,400),4,4 ) mu<-c(100,150,200,250) N=100 for(i in 1:N) { assign(paste("Data.", i, sep=''), as.data.frame(cbind(seq(1:1000),(mvrnorm(n=1000, mu, Sigma))))) } With these datasets, I need to work on some of the variables and then run each dataset

Hi, I'm running R 2.11 Does anyone know if it possible to transform one character vector to one character string ? Many thanks Benoit -- Benoit Wastine Laboratoire des Sciences du Climat et de l?Environnement (LSCE/IPSL) CEA-CNRS-UVSQ CE Saclay Orme des merisiers B?t 703 - Pte 13A 91191 Gif sur Yvette Cedex France Tel : 33 (0)1 69 08 21 97 Fax : 33 (0)1 69 08 77 16

Dear all, how can I perform a string operation like strsplit(x," ") on a column of a dataframe, and put the first or the second item of the split into a new dataframe column? (so that on each row it is consistent) Thanks Boris

Hi R users I have these two vectors: Row <- sample(1:25, 10) Col <- sample(1:25, 10) Is there a way to combine them into a list, whose first component is a vector containing the first element of Row and the first element of Col, the second component is a vector containing the second element of Row and the second element of Col, and so on... Thanks you Lorenzo

Dear R helpers I seem to have one trivial problem but can't find solution to it. Suppose I have following input. A = c(1,  3,  0,  5,  8)                  # 3rd element is 0 B = c(100, 30,  0,  25,  40)          # 3rd element is 0 C = A/B > C [1] 0.01 0.10  NaN 0.20 0.20 Obviously, I can't divide 0/0 and hence NaN. My problem is how to replace this NaN say by 0. So that I can

Dear R experts, I've written some functions in a few source files (such as main.R, control.R ...). After loading them into R, how do I retrieve which functions are loaded from which source file? For example: main.R has functions: myPrint(), myScan() control.R has functions: setPrinter(), setData() After loading the sources (main.R and control.R) into R, I would want to know that

Dear R helpers Suppose val1 = c(10, 20, 35, 80, 12) val2 = c(3, 8, 11, 7) I want to select either val1 or val2 depending on value of third quantity val3. val3 assumes either of the values "Monthly" or "Yearly". If val3 = "Monthly", then val = val1 and if val3 = "Yearly", then val = val2. I tried the ifelse statement as ifelse(val3 =

Hello, I'd like to ask you something again. I have a database and it has a column which looks like this one here: small_factor <- factor(c("d_variable1","d_variable2","d_variable3")) small_factor Now the thing is that I would like to convert each element of this factorized column. Basically I want to rewrite the words in it without the first two characters:

Hi I got a string that looks something like this 1 2 3 4 5 6 7 8 9 ... and I want it to be 123456789... So I want to remove all spaces (or whitespaces) from my string. Anyone know a good way of doing this? //Joel -- View this message in context: http://r.789695.n4.nabble.com/Remove-all-whitespaces-tp3497867p3497867.html Sent from the R help mailing list archive at Nabble.com.

Dear collegues! Given a matrix, I would like to remove columns, that do not fulfill a certain condition. The condition is, that the median of the column is higher than a certain value. I've seen the help on removing NA columns, but I cannot figure out how to change the function part of the statement, so that the function is only TRUE if the median of the column is higher than x;

Dear R-Users, I have a trivial problem, but extensive googling and ??'ing did not solve it: I want to obtain the sums of squares from a summary.aov() object for later use. Example: > DV <- rnorm(100) > IV1 <- as.factor(rep(c("male", "female"), times = 50)) > IV2 <- as.factor(rep(c("young", "old"), times = 50)) > >

Hi, What is an efficient way to take this DF data.frame(A=c(1,2,NA,NA),B=c(1,NA,NA,4)) and get c(NA,"TWO","BOTH","ONE") as the result, where NA corresponds to a row without "NA"s, TWO indicates NA in the second and ONE in the first column. Thanks for any pointers. Joh

Hi All, Is it possible to use the subset() function to select data based on multiple values of a single variable from a data frame. My actual data set is much bigger and would like to illustrate with following dataset > df = data.frame(x = c('a','b','c','d','e','f','g','h','a','a','b','b'), y =