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This is the first time that I have tried to update packages with a tinkered around with .Rprofile. I start R with R --vanilla and it does not load my .Rprofile, but when I issue the command update.packages() R downloads the packages as expected, but then seems to load .Rprofile before compiling the packages sources. What am I doing wrong? kindest regards, Stephen Sefick see- Session info

All, 1. I will try and make this clear and concise. Please let me know any information that would be helpful in figuring out this problem (I don't know the relevant information to post). I am on linux- see below for session information. 2. Problem: working directory: home an old version of a function is sourced into the R session and doesn't work working directory: Desktop the

I would like to be able to grab x and y columns out of a dataframe and then grab all of the columns that are not equal to x or y. I am sure that I am missing something easy. ftbr_UTM_downstream <- (structure(list(site = c("Jennie_Creek_Main_Stem", "Wolf_Pit_Creek_Main_Stem", "Little_Rockfish_Main_Stem_North", "Big_Muddy_Creek_Main_Stem",

I have a model Q=K*A*(R^r)*(S^s) A, R, and S are data I have and K is a curve fitting parameter. I have linearized as log(Q)=log(K)+log(A)+r*log(R)+s*log(S) I have taken the log of the data that I have and this is the model formula without the K part lm(Q~offset(A)+R+S, data=x) What is the formula that I should use? Thanks for all of your help. I can provide a subset of data if necessary.

s <- 1.00 max(s) returns 1 is there anyway that I can get it to return 1.00. I am using the results of this max statement in a grep statement and it returns the wrong numbers, I will provide more information and code if it would make more sense in context. -- Stephen Sefick ____________________________________ | Auburn University? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?? | | Department of

These data represent stream channel cross-sectional surveys. I would like to be able to find the measurement on the tape (measure) where the Bank Full Depth (bkf_depths) is 0. This will happen twice because the channel has two sides. I thought fitting a loess line to these data and then predicting the measurment number would do it. I was wrong. Below is my failed attempt. My naive thought is

the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,

R 2.12.2 on Scientific Linux 6.4 #works chron(times.="15:00:00", format=c(times="h:m:s")) #doesn't work chron(times.="15:00", format=c(times="h:m")) From chron Manual: The times format can be any permutation of "h", "m", and "s" separated by any one non-special character. The default is "h:m:s". what am I

Is there a way to use a continuous variable to pch in qplot? I believe this worked in previous version. I need to specify certain values of a shape for particular points so that multiple graphs all show the same shapes for the same streams. I have gone to the original data and added a pch column that I would like to use to specify the shapes to pch in qplot. Any help would be greatly

I know this is a double post, but the subject line was really misleading. Sorry again. This is the first time that I have tried to update packages with a tinkered around with .Rprofile. I start R with R --vanilla and it does not load my .Rprofile, but when I issue the command update.packages() R downloads the packages as expected, but then seems to load .Rprofile before compiling the packages

When I use this I am getting following warning at the time of opening R from that shortcut : "-max-mem-size=2048MB:too large and taken as 2047M" Why I am getting this? I have 3GB ram installed and using within Vista. Thanks -- View this message in context: http://r.789695.n4.nabble.com/How-to-allocate-more-memories-to-R-tp2271714p2272436.html Sent from the R help mailing list archive

I have a DF ID VALUE 100 120 101 100 102 100 103 104 105 .... when i calculate the sum of the values, it returned NA. should I populate the blank value as 0? Thanks, -- View this message in context: http://r.789695.n4.nabble.com/MISSING-VALUE-IN-R-tp2299586p2299586.html Sent from the R help mailing list archive at Nabble.com.

POS=sum(x[-1][x[-1]>0],na.rm=TRUE) is this the correct syntax? -- View this message in context: http://r.789695.n4.nabble.com/na-rm-TRUE-tp2299596p2299596.html Sent from the R help mailing list archive at Nabble.com.

Hi user's Does anybody work with wavelets on R? Please I need some help.....!!!! Atte Marize Sim?es -- View this message in context: http://r.789695.n4.nabble.com/Package-wavelets-tp2526023p2526023.html Sent from the R help mailing list archive at Nabble.com.

By any chance is there an R package that may contain functionality similar to the frestimate in Matlab/Simulink. Here is the URL for a description of the frestimate functionality: http://www.mathworks.com/help/toolbox/slcontrol/ug/frestimate.html Thank you again for any feedback.

Dear all, I'm just wondering how to submit a package to cran? I followed the instruction, using anonymous as username and my email address as password, but it didn't connect. Any hints? Yan [[alternative HTML version deleted]]

The dataframe is id salary 100 500 101 600 102 700 103 800 how can i generate a subsets if salary>600? -- View this message in context: http://r.789695.n4.nabble.com/Filtering-in-R-tp2299603p2299603.html Sent from the R help mailing list archive at Nabble.com.

Hi, I have a data frame with columns as follows: tree species (independent variable) and several dependent variables (e.g. carbon, nitrogen, phosphorus). Each row represents one tree sample. Some tree samples are unique species in the data frame while other species were replicated (i.e. rows 1,2,3 may be identical for the "tree species" column but have different values for the

Hi, I have been unable to find how to go about changing the significance level in R for hypothesis testing and regression analysis. R has a default setting to alpha=95% (a significance level of 95%), but I want to be able to decrease or increase this level when necessary. If you could give me instructions on how to change the significance level in R for hypothesis testing and regression analysis

HI All, How to read SAS data directly into R ? Thank you [[alternative HTML version deleted]]