similar to: Regrouping data

I submit the following matrix to both MATLAB and R x= 0.133 0.254 -0.214 0.116 0.254 0.623 -0.674 0.139 -0.214 -0.674 0.910 0.011 0.116 0.139 0.011 0.180 MATLAB's inv(x) provides the following 137.21 -50.68 -4.70 -46.42 -120.71 27.28 -8.94 62.19 -58.15 6.93 -7.89 36.94 8.35 11.17 10.42 -14.82 R's solve(x) provides: 261.94 116.22 150.92 -267.78 116.22 344.30 286.68

Hi @ all, I hope for some help of you. I have a dataframe and I want to regroup it. examp4.csv <http://r.789695.n4.nabble.com/file/n4648927/examp4.csv> I need the arguments of "VAL" as table heads and the "TYPE " only in individual expression. The result should look like in the example pic. exp4.png <http://r.789695.n4.nabble.com/file/n4648927/exp4.png> I

Hi all, I had some trouble in?regrouping factor levels for a variable. After some experiments, I have figured out how I can recode to modify the factor levels. I would now like some help to understand why some methods work and others don't. Here's my code : rm(list=ls()) ###some trials in recoding factor levels char<-letters[1:10] fac<-factor(char) levels(fac) print(fac) ##first

Current dragonegg svn has all of the -fplugin-arg-dragonegg-enable-gcc-optzns bugs for usage with -ffast-math -O3 addressed except for those related to PR2314. Using the -fno-tree-vectorize option, we can evaluate the current state of -fplugin-arg-dragonegg-enable-gcc-optzns with the Polyhedron 2005 benchmarks compared to stock dragonegg and stock gcc 4.5.4. The runtime benchmarks below show that

Duncan, Below are the tabulated compile times and executable sizes. A) gcc 4.5.4svn using -msse3 -ffast-math -O3 -fno-tree-vectorize B) gcc 4.5.4svn/dragonegg using -msse3 -ffast-math -O3 -fno-tree-vectorize -fplugin-arg-dragonegg-enable-gcc-optzns C) gcc 4.5.4svn/dragonegg using -msse3 -ffast-math -O3 -fno-tree-vectorize Compile time (seconds) Benchmark A) stock B) gcc 4.5.4/ C)

I can't figure out why this function wont work. #Custom Function used fallInBand <- function(x){ #Assume the bands fall go up form 0 to 100 in intervals of 5 then from 100 to 1000 in intervals of 100. #returns the location (band number) if (is.na(x) == FALSE) { if(x < 100) {#bands of 5 if((x %% 5) >=0){#falls within the band Result = as.integer(x/5)+1

Hi Jack, thanks for these numbers. Can you also please measure compile times? I'm thinking of enabling gcc optimizations by default, but I don't want to increase compile times, which means choosing a value for the -fplugin-arg-dragonegg-llvm-ir-optimize option that is low enough to get good compile times, yet high enough to get fast code. It would be great if you could play around with

Hi Jack, thanks for doing this. > Below are the tabulated compile times and executable sizes. > > A) gcc 4.5.4svn using -msse3 -ffast-math -O3 -fno-tree-vectorize > B) gcc 4.5.4svn/dragonegg using -msse3 -ffast-math -O3 -fno-tree-vectorize -fplugin-arg-dragonegg-enable-gcc-optzns > C) gcc 4.5.4svn/dragonegg using -msse3 -ffast-math -O3 -fno-tree-vectorize These numbers really

Dear List, i am trying to produce a 3d plot using wireframe using the code: wireframe(Residuals_FD ~ Elevation * Temperature, data = data2, scales = list(arrows = FALSE), drape = TRUE, colorkey = TRUE) As you can see when the code (using the data below) is run the plot area is set-up correctly but the actual surface is missing? Any help would be greatly appreciated. Chris #data Elevation

Hello I have a problem that i ant make a Bar plot like the one i have tried to illustrate below (made in paint); http://www.nabble.com/file/p21437080/LG5%2Bgraf%2Bredigeret.jpg http://www.nabble.com/file/p21437080/LG5%2Bgraf%2Bredigeret.JPG LG5+graf+redigeret.JPG Where each line represents a model; model1 = 0.58*x+12.65 model2 = 1.16*x+12.65 But i only want the bars and with y-values above

library(StreamMetabolism) day <- (structure(c(10.08, 10.08, 10.05, 10.03, 10, 9.98, 9.96, 9.95, 9.95, 9.96, 9.96, 9.98, 10.01, 10.05, 10.06, 10.09, 10.11, 10.11, 10.13, 10.13, 10.15, 10.15, 10.13, 10.14, 10.11, 10.13, 10.14, 10.13, 10.12, 10.13, 10.14, 10.16, 10.18, 10.19, 10.23, 10.27, 10.33, 10.37, 10.45, 10.57, 10.6, 10.66, 10.73, 10.77, 10.84, 10.86, 10.87, 10.94, 10.98, 11.01, 11.05,

I am using the number to currency function because i live in the uk and the company want me to only show values of the pound of course.I have created all my application using ruby script/generate scaffold_resource.... I have come across with a problem... this code is in my applcation: def number_to_currency(number, options = {}) options = options.stringify_keys precision, unit, separator,

Dear R, I'm trying to plot the first principle component of an analysis vs the first variable but am having trouble. I have no trouble doing the initial plot but have difficulty thereafter. First I want to highlight some points of the following data set list(running) [[1]] X100m X200m X400m X800m X1500m X5K X10K Marathon Argentina 10.39 20.81 46.84 1.81

The aggregate function for some reason will now work for me. The error I'm getting is: "Error in sort.list(y) : 'x' must be atomic for 'sort.list' Have you called 'sort' on a list?" agPriceList=aggregate(PriceList$Size, list(PriceList$bandNum),sum) *Price list dataframe:* dput(PriceList) structure(list(Price = c(0, 8.18, 8.27, 10.42, 10.5, 10.6, 11.13,

At the cost of breaking the thread I'm going to change your subject and replace 'Principle' by 'Principal'. I just can't stand it any longer... OK, here is how I would solve your other problems. First put > wh <- c("USA", "New Zealand", "Dominican Republic", "Western Samoa", "Cook Islands") > ind

On Thu, Jun 09, 2011 at 03:44:40PM +0200, Duncan Sands wrote: > Hi Jack, thanks for doing this. > >> Below are the tabulated compile times and executable sizes. >> >> A) gcc 4.5.4svn using -msse3 -ffast-math -O3 -fno-tree-vectorize >> B) gcc 4.5.4svn/dragonegg using -msse3 -ffast-math -O3 -fno-tree-vectorize -fplugin-arg-dragonegg-enable-gcc-optzns >> C)

Hello, I am trying to filter a data set like below so that the peaks in the Phase value are more obvious and can be identified by a peak finding function following the useful advise of Carl Witthoft. I have written the following for(i in length(data$Phase)){ newphase=if(abs(data$Phase[i+1]-data$Phase[i])>6){ data$Phase[i+1] }else{data$Phase[i] } } I get the following error which I have not

Hello, I am running Asterisk 11.17 with DAHDI 2.9.0 and an OpenVox A800P with 8x analog POTS lines coming into my Asterisk server from the phone company. Internally, I have about 180 SIP clients defined in sip.conf. What appears to be happening is that if existing calls are consuming all 8 external lines and a new SIP client attempts to make a call, an existing call gets dropped. The asterisk

Dear R helpers I have a data which gives Month-wise and Rating-wise Rates. So the input file is something like month           rating           rate January        AAA             9.04 February      AAA             9.07 .......................................... .......................................... Decemeber     AAA            8.97  January           BBB           11.15 February        

Hello there, I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is