similar to: combining two columns into one column despite NAs

Hello I simply want to plot two variables against one 'year' variable in qplot. Is any way of doing this without reshaping data in long format and using facet function afterwards? Thank you Denis

Dear all, I have 100 files which are used as input.and I have to input the name of my files again and again.the name of the files are 1.out, 2.out......100.out. I want to know if there is anything like perl so that i can use something like this- for($f = 1; $f <= 100; $f++) { $file = $f.".out"; I have tried this thing in R but it does not work.Can somebody please help me.

i am trying to fit a linear model with both continuous covariates and factors. When fitted with the intercept term the first level of the factor is treated by R as intercept and the estimate of the effects of remaining levels(say i th level) are given as true estimate of i th level - estimate of 1st level.can any please help me? thanks in advance..... -- View this message in context:

This is what I was looking for. Thank you everyone! Sincerely, Milu <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail> Mail priva di virus. www.avast.com <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail>

Some help with how to re-label the vertical axis in a histogram would be appreciated. qplot(off.sc,weight=rel.freq,binwidth=.29,main="test Figure"+ylab("New from inside"))+ylab("New from outside")+ xlab("off.sc\nAggregated frequency plots for 17 equal intervals.") The code

Hi helpeRs, I have inherited a set of data files that use the file system as a sort of poor man's database, i.e., the data files are nested in directories that indicate which city they come from. For example: dir.create("deleteme") for(i in paste("deleteme", c("New York", "Los Angeles"), sep="/")) { dir.create(i) for(j in

On Tue, Feb 20, 2018 at 11:58 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > Ista, et. al: efficiency? > (Note: I needed to correct my previous post: do.call() is required for > pmax() over the data frame) > > > x <- data.frame(matrix(runif(12e6), ncol=12)) > > > system.time(r1 <- do.call(pmax,x)) > user system elapsed > 0.049 0.000

Hi guys, Are there any feasible methods in searching & finding non-ASCII characters in R? For example, from the following object, x <- mia. SzaÌmitaÌó The desired output is, x.out <- mia. SzaImitaIA Your help in resolving this would be greatly appreciated. [[alternative HTML version deleted]]

Hi everyone, Is there a way to make R save the workspace output (just the results, not the objects themselves) as you go? I'm running analysis that takes a long time to run and I want to be able to interrupt it without losing all the output to date. Is there an alternative to putting "save.image()" commands after every couple lines of code? Best, Tatyana

Ista, et. al: efficiency? (Note: I needed to correct my previous post: do.call() is required for pmax() over the data frame) > x <- data.frame(matrix(runif(12e6), ncol=12)) > system.time(r1 <- do.call(pmax,x)) user system elapsed 0.049 0.000 0.049 > identical(r1,r2) [1] FALSE > system.time(r2 <- apply(x,1,max)) user system elapsed 2.162 0.045 2.207 ##

Hello everyone, I am trying to figure out a way of replacing missing observations in one of the variables of a data frame by values of another variable. For example, assume my data is X X <-as.data.frame(matrix(c(9, 6, 1, 3, 9, "NA", "NA","NA","NA","NA", 6, 4, 3,"NA", "NA", "NA", 5, 4, 1, 3),

Hi all, I think I'm cracking up. Please help me understand why I'm getting different results with m.test and m.test2 in the example below. > library(reshape) Loading required package: plyr > > m.test <- data.frame(id = factor(rep(1:10, 2)), variable=rep(c("var1","var2"),10), value=rnorm(20)) > cast(m.test, ...~variable, value="value") ## cast

Hello, Here are three vectors to give context to my question below: *id <- c(1,1,1,1,1,2,2,2,3,3,3)) month <- c(1, 1, 2, 3, 6, 2, 3, 6, 1, 3, 5) value <- c(10, 12, 11, 14, 16, 12, 10, 8, 14, 11, 15)* and I want to plot "value" over "month" separately for each "id". Before I can do that, I need to section both month and value, based on ID. I create a

Dear R helpers, I am trying to understand how to use the independence_test function in the coin package. I think I suffer from a misunderstanding about what the package does. Either that or I do not understand how to use it properly. Specifically, I cannot understand if I can test independence of arbitrary statistics. Take the following example: set.seed(10) d <- data.frame(y = c(rnorm(10,

I am not sure if this question has been asked before - but is there a procedure in R (in lm or glm?) that is equivalent to ENTER and REMOVE regression commands in SPSS? Thanks a lot! -- Dimitri Liakhovitski Ninah.com Dimitri.Liakhovitski at ninah.com

I have the following data: prefix <- c("cheap", "budget") roots <- c("car insurance", "auto insurance") suffix <- c("quote", "quotes") prefix2 <- c("cheap", "budget") roots2 <- c("car insurance", "auto insurance") roots3 <- c("car insurance", "auto

Dear R Users, I would like to know is there any package to create a plot like this? http://dl.dropbox.com/u/5409929/cs1160521f01.gif X axis is categorical. And the positions of the points are corresponding to the frequency. (similar to violinplot) Thank you. Regards, CH -- CH Chan

It looks like OP uses a data.frame, so in order to use matrixStats (I'm the author) one would have to pay the price to coerce to a matrix before using matrixStats::rowMaxs(). However, if it is that the original data could equally well live in a matrix, then matrixStats should be computational efficient for this task. (I've seen cases where an original matrix was turned into a data.frame

Hi, I was trying to overlay/combine two freqpoly plots. The sample code below illustrates the problem. Essentially, I want to do is: 1. Have the same colour for all the lines in 'Plot 1' (and 'Plot 2'). Currently, all the lines in Plot 1 have different colours and all the lines in Plot 2 have different colors. I'd like for all lines in Plot 1 to be 'red' and all the

Can someone please tell me what is up with na.action in aggregate? My (somewhat) reproducible example: (I say somewhat because some lines wouldn't run in a separate session, more below) set.seed(100) dat=data.frame( x1=sample(c(NA,'m','f'), 100, replace=TRUE), x2=sample(c(NA, 1:10), 100, replace=TRUE), x3=sample(c(NA,letters[1:5]), 100, replace=TRUE),