similar to: Subset using grepl

Hi all, I have one factor variable in my df and I want to extract the names from it which contain both "t2" and "pd": 'data.frame': 36919 obs. of 162 variables $TE :int 38,41,11,52,48,75,..... $TR :int 100,210,548,546,..... $Command :factor W/2229 levels

You can use the grepl() function to give you logicals for each criterion, then combine them as needed. For example: # example version of Command Command <- paste0("_localize_", c("PD","t2","t1_seq", "abc", "xyz", "PD_t1")) hasPD <- grepl("PD", Command, fixed=TRUE) hast1 <- grepl("t1", Command,

Thanks Jean, Does anyone know how to set these [hast1] and [hast2] as the colors of a plot? On Friday, April 22, 2016 7:39 AM, "Adams, Jean" <jvadams at usgs.gov> wrote: You can use the grepl() function to give you logicals for each criterion, then combine them as needed. For example: # example version of Command Command <- paste0("_localize_",

Hi, I have a dataset that looks like the one below. data plot plantno. species H 31 ABC D 2 DEF Y 54 GFE E 12 ERF Y 98 FVD H 4 JKU J 7 JFG A 55 EGD . . . . . . .

'grepl' returns a logical vector; you have to use this to get your subset. You can use: df_tq <- subset(df, grepl("t1", Command)) df_t2 <- subset(df, grepl("t2", Command)) # if you want to also get a subset that has both, use df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) Jim Holtman Data Munger Guru What is

now after this: df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) I use factor to apply the subset to df but then the Command level becomes 0 df_both$Command=factor(df_both$Command) str(df_both) $ Protocol : Factor w/ 0 levels: Do you know what is the reason? Thanks for replying On Sunday, April 24, 2016 12:18 PM, jim

Hi, I have 2 dataframes of unequal length, and I would like to match a factor to them so that both dataframes will have the same number of rows. example: # create the 2 dataframes with unequal length data1 <- data.frame(letters, 1:26)[-c(5,10,19:21),] data2 <- data.frame(letters, 1:26)[-c(6,9,15:18),] data2a <- match(data1[,1], data2[,1]) data2b <- data2[data2a,] When I match

Hi I have the following df and I created two subsets but I don't know how to use these subsets as the colors of my plot. data.frame': 36919 obs. of 162 variables $TE :int 38,41,11,52,48,75,..... $TR :int 100,210,548,546,..... $Command :factor W/2229 levels

Hi all, I have a data frame df and I want to do subset based on several conditions of letters of the names in Command.1)if the names contain PD 2)if the names contain t1 3)if the names contain t2 4)if the names contain t1 and PD 5)if the names contain t2 and PD 6)otherwise the names would be unknown. I don't know how to use grep for all these conditions. 'data.frame': 36919

Inspired by this old Stack Overflow question https://stackoverflow.com/questions/19765610/when-does-locale-affect-rs-regular-expressions I was wondering why this is TRUE: Sys.setlocale("LC_ALL", "et_EE") grepl("[A-Z]", "T") TRE's documentation at <https://laurikari.net/tre/documentation/regex-syntax/> says that a range "is shorthand for

I do not follow you Gabriel. Package name must not use digit numbers. Tarbal will use them, taken from the DESCRIPTION file, version field. That's why I consider the weird case name you presented as irrelevant, and not to be considered. Le ven. 9 ao?t 2019 ? 20:41, Gabriel Becker <gabembecker at gmail.com> a ?crit : > > > On Fri, Aug 9, 2019 at 11:05 AM neonira Arinoem

x["V2"] is more efficient than using drop=FALSE, and perfectly normal syntax (data frames are lists of columns). I would ignore the naysayers, or put a comment in if you want to accelerate their uptake. As I understand it, one of the main reasons tibbles exist is because of drop=TRUE. List-slice (single-dimension) indexing works equally well with both standard and tibble types of data

Hi all, I was wondering if there's an equivalent to par(new=T) of the plot function in lattice. I'm plotting an xyplot, and I would like to highlight one point by plotting that one point again using a different symbol. For example, where 6 is highlighted: plot(1:10, xlim=c(0,10), ylim=c(0,10)) par(new=T) plot(6,6, xlim=c(0,10), ylim=c(0,10), pch=16) Is there a way to do this in lattice?

Hi all, I have a numeric vector with 1 decimal place, and I'd like to extract the last 3 characters, including the decimal point. The vector ranges from 0 to 20. x <- round(runif(100)*20, digits=1) Some of numbers have 3 characters, and some have 4. I've read up on the substr() function but that extracts characters based on exact positions. How can I extract just the last 3

On 5/30/23 17:45, Ben Bolker wrote: > Inspired by this old Stack Overflow question > > https://stackoverflow.com/questions/19765610/when-does-locale-affect-rs-regular-expressions > > > I was wondering why this is TRUE: > > Sys.setlocale("LC_ALL", "et_EE") > grepl("[A-Z]", "T") > > TRE's documentation at >

Hi all, I have a matrix with 5 rows and 10 columns, which represent the grids on a rectangular map. I used the code below to plot, but it gives me the map with the 10 columns as y-axis, and the 5 rows as the x-axis, and the (0,0) point is at the usual bottom left hand corner. My map starts with the (0,0) at the top left hand corner. How can I rotate the map 90 degrees clockwise so the (0,0)

Dear All, I am experiencing some problems with a script of mine. It crashes with this message Error in grepl(fut_string, past_string) : invalid regular expression

On 04/10/2016 03:27 PM, Fabien Tarrade wrote: > Hi Duncan, >> Didn't you post the same question yesterday? Perhaps nobody answered >> because your question is unanswerable. > sorry, I got a email that my message was waiting for approval and when I > look at the forum I didn't see my message and this is why I sent it > again and this time I did check that the

Hi fellow R users, I have a dataset that looks something like this. species class abundance K 1 592 K 2 288 G 1 254 G 2 239 C 2 173 D 2 123 E 3 89 F 2 87 B 2 86 H 2 82 I 1 79 J 2 76 B 1 73 D 3 72 A 2 62 L 2 58 I want to plot a stacked barchart. species is the x-axis, abundance is y-axis, and class will appear as the stacks in different colours. I need the species to be displayed in descending

Hi R users, I really need help with subsetting data frames: I have a large database of medical records and I want to be able to match patterns from a list of search terms . I've used this simplified data frame in a previous example: db <- structure(list(ind = c("ind1", "ind2", "ind3", "ind4"), test1 = c(1, 2, 1.3, 3), test2 = c(56L, 27L, 58L,