similar to: Analysing Character Strings for subsequent frequency analysis

Hi, Is anyone able to help Mr Stoner? -Ivo ---------- Forwarded message ---------- From: Ed Stoner <ed@whsd.net> Date: Oct 9, 2007 5:32 PM Subject: [sugar] video encoding To: sugar@lists.laptop.org I would like to provide the functionality of a "video export" from within an activity I am working on. I'm starting with a png for each frame of the video and would like to do

Hello Wine community, I tried to install a programm called Helium Music Manager. The installer tries during the installation to register some files, here the error messages of the installer: Unable to register WMAManagerManaged. Code 2 Unable to register Interop.PortableDeviceApiLib.dll Code 2 Unable to register Interop.PortableDeviceTypesLib.dll Code 2 Unable to register IntermediaMTPLibrary.dll

I'd very much appreciate some help with a rather major problem I'm having. I have a Dell 6450 quad Xeon Processor machine with 8GB of RAM and 1TB of disk (RAIDed with an Adaptec 5400S RAID controller). It is running samba (2.2.8) to server up files to around 2300 Windows 2000 machines. The machine was originally installed and configured around September 2002. It had been running

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

I've also tried adding the pgsql and mysql RPM's and they're not available either. On 20/03/2023 12:58, Gary Stainburn wrote: > Apologies.? This is the correct screen grab. > > The extra errors in the OP were because I had been experimenting, to > try to fix the issue. > > [root at testsvr ~]# ./ldapAuth.php gary.stainburn fake-password > PHP Fatal error:?

Hello, I'm not sure how to state my question in a technically accurate manner, so I'll use a short example to clarify my problem: Say I have a vector, vec<-c(1,2,3,2) I would like to be able to "reference" the vector by using the string containing the name of the vector - that is, I would like to know of some function which is able to convert the string "vec"

Is there a function to efficiently search for a subsequence within a vector? For example, with x <- 1:100 I'd like to search for the sequence c(49,50,51), and be told that it occurs exactly once, starting at location 49. (The items in the vectors might be numeric or character, and there might be repetitions within the search pattern or within the vector I'm searching.) Duncan

> And where do we get this? Saw nothing on the speex website... http://www.openacm.org/ --- >8 ---- List archives: http://www.xiph.org/archives/ Ogg project homepage: http://www.xiph.org/ogg/ To unsubscribe from this list, send a message to 'speex-dev-request@xiph.org' containing only the word 'unsubscribe' in the body. No subject is needed. Unsubscribe messages sent to

I have a very long list of strings. Each string actually contains multiple values separated by a semi-colon. I need to turn each string into a vector of the values delimited by the semi-colons. I know I can do this very laboriously by using loops, nchar, and substr, but it is terribly slow. Is there a basic R function that handles this situation? If not, is there perhaps a faster way to do it than

Hello, The example shows a sequence of songtypes a bird has sang. The entire list contains several thousand songs which the bird has produced consecutively. Is there any convenient way in R to produce a contingency table which shows how often a special song type was sang after a special other songtype? Or within a determined frame of e.g. 10 consecutively produced songs? Example: Nr Songtype 1

Dear R users, I was wondering if someone could suggest a few lines of code for my problem. I want to count the number and the length of strings of NA in a vector. For example: vec <- c(1, 2, 1, NA, NA, 1, 2, NA, NA, NA, 3, 4, NA, NA) has 2 strings of NA's of length 2 and 1 string of NA' of length 3. I can easily count the number of NA's per vector, but I am having a hard time

Hello, What is the fastest way to do this? I has to be done quite a few times. Basically I have sets of 3 numbers (as characters) and sets of 3 dashes and I have to store them in named columns. The order of the sets and the column name they fall under is important. The actual numbers and the pattern/order of the sets should be considered random/unpredictable. Sample data: vec =

Hi I'm writing a function that uses four parameters (scalars) and I need to run it in an iterative process (the parameters vary to find the minimum RSS). I don't want to use loops and so tried the do.call function. However it didn't work. My understanding is that the do.call simple runs the function replacing the arguments (scalars by vectors), instead of runing the function for

Hello, Thanks in advance for any help, I have read a CSV file in which there is a column for an IP addr as in: tmpInFile$V2 [1] "74.125.224.38" "74.125.224.38" "129.46.71.19" "129.46.71.19" [5] "129.46.71.19" "129.46.71.19" "129.46.71.19" "129.46.71.19" [9] "129.46.71.19" "129.46.71.19"

Hi, how can I do the following in R?: vec <- c("a", "b", "c") ....magic..... print(str) "abc" or even better: "(a,b,c)"? Cheers -- View this message in context: http://www.nabble.com/merge-character-strings-tp20790116p20790116.html Sent from the R help mailing list archive at Nabble.com.

Hi Rail, We used a very simple pattern expansion (actually, not a pattern fragment). For example, for AND, ADD (horizontal sum), OR and XOR of 4 elements we use something like the following TableGen structure: class HORIZ_Op4<SDNode opc, RegisterClass regVT, ValueType rt, ValueType vt, string asmstr> : SHAVE_Instr<(outs regVT:$dst), (ins VRF128:$src),

Hi, As a follow up to Patch D23646 <https://reviews.llvm.org/D23646>, I'm trying to figure out if there should be an alignment check and what the correct approach is. Some background: For stores, the pass turns: %i.vec = shuffle <8 x i32> %v0, <8 x i32> %v1, <0, 4, 8, 1, 5, 9, 2, 6, 10, 3, 7, 11> store <12 x i32> %i.vec, <12 x i32>* %ptr

Dear useRs, I want to write a function that generates all the possible combinations of diff(). Example: If my vector has length 5, I need the diff() until lag=4 -> c(diff(my.vec), diff(my.vec, lag=2), diff(my.vec, lag=3), diff(my.vec, lag=4)) If it has length 4, I need until lag=3 -> c(diff(my.vec), diff(my.vec, lag=2), diff(my.vec, lag=3)) So, it must be until lag=(length(my.vec)-1).

I have a list (length 750), each element containing a vector of unique strings (unique gene ids), with length up to ~40 (median 15). I want to compile a matrix of all possible triplets and their frequency within gene elements. Using combn and a lot of looping, I am accomplishing this but it is VERY slow. I've tried to figure out a way to vectorize this, using "match" and

Dear R-Helpers: I am a entry level user of R. Have the following question. Many thanks in advance. # value.vec stores values value.vec <- c('a','b','c') # which.vec stores the locations/indexs of values in value.vec. which.vec <- c(3, 2, 2, 1) # How can I obtain the following vector based on the value.vec and which.vec mentioned above # vector.I.want <-