similar to: Removing rows with earlier dates

Dear All, Debuting in R, I'm facing a problem. I have 2 vectors, say 'a' et 'b', and I'd like to merge them according to the proximity of their variable 'time'. How to do to keep elements which satisfy (for example) 'a$time-b$time<0.5'? For example : > a time x 1 1.0 4 2 2.2 5 3 5.2 6 > b time y 1 0 1 2 1 3 3 2 5 4 4 7 5

Hi, I have a data frame with two columns. I need to remove duplicated rows in first column, but I need to do it conditionally to values of the second column. Example: Point_counts Psi_Sp 1 A 0 2 A 1 3 B 1 4 B 2 5 B 0

Hello: I have a dataframe, where the first column in a month: Month CATCHMENT_ med min max 1 Apr Alknda01 71.68080 11.9406600 196.2753 2 Apr Alknda02 69.44580 12.1065600 196.2753 3 Apr ArialKhan 39.89310 5.8598700 175.4433 4 Apr Arjun01 4.79652 0.0093336 55.7136 5 Apr Arjun02 4.79652 0.0093336 55.7136 6 Apr Arun01 52.42320 0.1571928

List, Consider the following data. gender mygroup id 1 F A 1 2 F B 2 3 F B 2 4 F B 2 5 F C 2 6 F C 2 7 F C 2 8 F D 2 9 F D 2 10 F D 2 11 F D 2 12 F D 2 13 F D 2 14 M A 3 15 M A 3 16 M A 3 17

Hello, I am having trouble by using the write.table function to write a data frame of 4 columns and 7530 rows. I don?t know if I should just use a sep="\n" and change the .xls file into a .csv file. Thanks in advance ----- Anna Lippel new in R so be careful I should be asking a loooooooot of questions!:teeth: -- View this message in context:

Hi all I have a data frame with duplicate columns and i want to remove duplicates by adding rows in each group of duplicates, but have lots of NA's. Data: dfrm <- data.frame(a = 1:4, b= 1:4, cc= 1:4, dd=1:10, ee=1:4) names(dfrm) <- c("a", "a", "b", "b", "b") dfrm[3,2:3]<-NA dfrm a a b b b 1 1 1 1 1 1 2 2 2 2 2 2 3

Hi there, I have a data frame with a column named "Flags", whose contents are strings containing any of the following characters, multiple characters allowed: A,B,C,D,E,F,G. Here is the head: GeocodeID PlaceID CountyCode CBSACode StateProvCode PropertyTypeGroupID Flags 1 0 0 0 0 AK 1 ABC 2

Dear all, let say I have following data frame: > data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6)) x y 1 -1.072152537 a 2 0.382985265 a 3 0.058877377 a 4 -0.006911939 a 5 -2.355269051 a 6 -0.303095553 a 7 0.484038422 b 8 0.733928931 b 9 -1.136014346 b 10 0.503552090 b 11 1.708609658 b 12 -0.294599403 b 13

I have a file like this: id n1 n2 n3 n4 n5 n6 1 3 4 7 8 10 2 2 4 1 2 4 3 10 3 7 0 0 0 0 8 4 10 1 0 0 2 3 5 11 1 0 0 0 5 what I want to do is: only if n2=0 and n3=0 and n4=0 and n5=0 then delete the row. how can I do that? thank you, karena -- View this message

R users: Thanks in advance  How to generate missing at random (MAR)? assaedi76@yahoo.com Thanks [[alternative HTML version deleted]]

I have a data set with 22 fields and several thousand records in which one field (count) indicates the number of times that each specific combination of the other 21 fields occurred in a bigger and largely unavailable data set. So each record is unique in its combination of field values and has a field that identifies how many multiples of this record actually occurred. Without resorting to

Hello, I have a file which contains a column with age, which is represented in the two following patterns 1. "007/A" or ''007/a" or ''7 /a" ..... In this case A or a means year and I would like to extract only the numeric values eg 7 in the above case if this pattern exits in a line of file. 2. "004/M" or "004/m" where M or m means month

I have a data.frame object like: > data.frame(x=c('A','A','B','B'), y=c('Ab','Ac','Ba','Bd')) x y 1 A Ab 2 A Ac 3 B Ba 4 B Bd how could I create a tree structure object like this: |---Ab A---| _| |---Ac | | |---Ba B---| |---Bb Thanks, Zech [[alternative HTML version deleted]]

Dear R-users, Say that I have a sequence of zeroes and ones: x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0) The sequences of ones represent segments and I want to report the starting and endpoints of these segments. For example, in 'x', the first segment starts at location 1 and ends at 3, and the second segment starts at location 8 and ends at location 10. Is there an efficient

Hi everyone, Once again I am stuck with a problem I can't seem to figure out. I suppose this learning curve levels off eventually, lol. I am learning on my own with absolutely no background in programming, so if I seem to request help a lot it's not because I am seeking others to do the work for me. I need to assign one of two arrival times to the 'ARRIVE' variable of my

dear R-tists, i am experiencing a problem with the data editor in the windows version of R 1.6.1 envoked with the command 'fix'. the data editor changes the size of large data frames. a simple example illustrates this: ------------------------------------------------------- > dfrm <- data.frame(no=c(1:100000)) > length(dfrm[,1]) [1] 100000 > fix(dfrm) >

Hi, I need to filter my data: I think its easy but i'm stuck so i'll appreciate some help: I have a data frame with 14 variables and 6 million rows. About half of this rows have a value of "0" in 12 variables (the other two variables always have values). How can I delete the rows in which all 12 variables have the value of "0". example (from my data, variable 14 is

I would like to do some operations inside a function using only one value for the last dimension of a table/matrix: tabfn <- function (dfrm, facvec, YN ="event"){ return( Etbl <- do.call(table, dfrm[ , c(facvec, "event") ]) ) # just want Etbl[,,,"TRUE"] or Etbl[,, "TRUE"] or Etbl[,"TRUE"] }

Dear R-brains, I'm rather new to state-space models and would benefit from the extra confidence in using the excellent package sspir. In a one-factor model, If I am trying to do a simple regression where I assume the intercept is constant and the 'Beta' is changing, how do I do that? How do i Initialize the filter (i.e. what is appropriate to set m0, and C0 for the example below)?

Hello R/Splus users.. I am posting in R discussion group in hope of wider response compared to what I received from Splus user groups.... Was wondering if there is any function available in Splus 8.2 that is equivalent to "reshape" of R? Below is a sample dataset. Size [both rows and columns) of the dataset may vary X1 Y1 Y2 Y3 0.25 40 38 22 0.5 44 41