Displaying 20 results from an estimated 500 matches similar to: "Export Results to a txt file applying a function to a list"
2010 Aug 26
2
Problems when Apply a script to a list
Dear users,
*******I have a function f to simulate data from a model (example below used
only to show my problems)
f<-function(n,mean1){
a<-matrix(rnorm(n, mean1 , sd = 1),ncol=5)
b<-matrix(runif(n),ncol=5)
data<-rbind(a,b)
out<-data
out}
*********I want to simulate 1000 datasets (here only 5) so I use
S<-list()
for (i in 1:5){
S[[i]]<-f(n=10,mean1=0)}
******I have a
2010 Sep 04
2
Function try and Results of a program
Hello, users.
Dear users,
*******I have a function f to simulate data from a model (example below used
only to show my problems)
f<-function(n,mean1){
a<-matrix(rnorm(n, mean1 , sd = 1),ncol=5)
b<-matrix(runif(n),ncol=5)
data<-rbind(a,b)
out<-data
out}
*********I want to simulate 1000 datasets (here only 5) so I use
S<-list()
for (i in 1:5){
S[[i]]<-f(n=10,mean1=0)}
2012 Dec 17
1
seeking a help on if function
Hello r helpers! Below is the whole coding for my programme. Before proceed more further, let me explain for you. First of all, I need to compute trimmed mean. Till that step is ok. Then I need to compute ssdw which is sum of square deviation. If I do equal trimming at both tail of distribution that I chose, I will use the first ssd formulae which is "a". But if I am doing unequal
2009 Mar 03
1
profiler and loops
Hello,
(This is follow up from this thread:
http://www.nabble.com/execution-time-of-.packages-td22304833.html but
with a different focus)
I am often confused by the result of the profiler, when a loop is
involved. Consider these two scripts:
script1:
Rprof( )
x <- numeric( )
for( i in 1:10000){
x <- c( x, rnorm(10) )
}
Rprof( NULL )
print( summaryRprof( ) )
script2:
2011 Nov 10
2
library(qpcR) cbind.na
I want to use function cbind.na at library(qpcR)
I install package qpcR and I can use functions such
m1 <- pcrfit(reps, 1, 2, l5)
> AICc(m1)
[1] -102.5843
but when i try cbind.na(1, 1:7) i take message
Error: could not find function "cbind.na"
Thanks
--
View this message in context: http://r.789695.n4.nabble.com/library-qpcR-cbind-na-tp4023339p4023339.html
Sent from the
2005 Jun 17
2
reading csv-data
Hi!
I have had this problem for a long time. I have tried to study the manuals and
search the mailing lists, but I can not solve this. I think there has to be one
simple solution to this, but I just can not find it.
I have saved the data in excel (csv-format). Then I read the data in R e.g.
>data <- read.csv2("example.csv", header=TRUE)
I look the data and it looks ok. E.g
2008 Sep 22
1
lme problems
Hi,
I'm analysing a dataset in which the same 5 subjects (male.pair) were subjected to two treatments (treatment) and were measured for 12 successive days within each treatment (layingday). Overall 5*2*12=120 observations.
I want to test the effect of treatment, time (layingday) and their interaction. I have done so through the ANOVA below:
>
2011 Aug 22
3
Multiple regression in R - unstandardised coefficients are a different sign to standardised coefficients, is this correct?
Hello,
I have a statistical problem that I am using R for, but I am not making
sense of the results. I am trying to use multiple regression to explore
which variables (weather conditions) have the greater effect on a local
atmospheric variable. The data is taken from a database that has 20391 data
points (Z1).
A simplified version of the data I'm looking at is given below, but I have
a
2010 Nov 23
1
Barplot and plot means with confidence intervals in the same plot
I want to obtain a barplot with error bars and a mean plot with error bars
with other scale on the left in the same plot. I need help to get the same
x axis (centered) when overlay two plots (barplot2 and plotCI (or
lineplot.CI) with errorbars), with diferent y axis. I use par (new=T) but
the X axis names are not centered with the figures.
An example of my data:
1999 Mar 07
1
ANOVA f-test
I have a rather basic question. How can I get R to generate a ANOVA table
and a f-value for a hypothesis test such as:
Data: group1 values: 5.2 4.5 6.0 6.1 6.7 5.8
group2 values: 6.5 8.0 6.1 7.5 5.9 5.6
...
H0: mean1 = mean2 = mean3 = mean4
HA: at least two means different
where I want to evaluate using a f test statistic?
F = MSTr/MSE
I'd like a table similar to one that
2012 Dec 23
2
Select maximum subset
Suppose i have matrix z
id<-c(1,2,3,4,5)
a <- c(4, 3, 2, NA, 1)
b <- c(3, NA, 2, 7, 1)
c <-c(3, NA, NA, 7, NA)
z<- cbind(id,a, b,c)
id a b c
[1,] 1 4 3 3
[2,] 2 3 NA NA
[3,] 3 2 2 NA
[4,] 4 NA 7 7
[5,] 5 1 1 NA
I want to select those columns for which I have the smallest number of NA
In my example, these would be column1 and 2
since they give me
4 3
2 2
2004 Apr 19
1
using subscripts in a plot title with 2 lines
Hi,
I'm making a plot in which the title takes up two lines. The title
contains a subscript but when I look at the plot it does'nt seem tocome
out properly. The code I'm using is:
xtxt = expression(paste('Observed -log( ', IC[50], ' )'))
ytxt = expression(paste('Predicted -log( ', IC[50], ' )'))
mtxt = expression(paste('Plot of Observed
2006 Mar 11
2
Draw level lines on the surface of a bivariate function
Hello,
Is it possible to draw level lines on the surface of a bivariate function?
In the following example, to draw surface and levels lines for a
multivariate normal law,
I use persp, trans3d, contourLines and lines,
but if the lines are correctly drawn, some parts of them are, of
course, visible
even if they are drawn on a non visible "face".
Any suggestion to avoid this problem
2011 Aug 16
4
a question about lm on t-test.
Hi all:
I have a question about lm on t-test.
data(sleep)
I wanna perform t-test to test the difference between the 2 groups:
I can use:
t.test(extra~group)
The t.test result shows that:t = -1.8608; mean1=0.75,mean2=2.33
But I still wanna use:
summary(lm(extra~group))
Intercept=0.75,which is mean1,just the same as t.test.
group2=1.58 means the difference of the 2 groups,so
2011 Dec 14
1
Hi
First PRoblem solved
> read.csv("KT80.csv")
X x
1 1 0.01331361
>
I ommitt "" in calling the file name...
2011/12/14 Trying To learn again <tryingtolearnagain@gmail.com>
> Hi all,
>
> I have 100 csv files always with this information (I Attach two example
> excels)
>
> KT80.csv contains:
> ,"x"
>
2011 Oct 28
2
Faster process for creating a matrix based on matrix element comparison
I have matrix data
data<-matrix(cbind(c(0,0,0),c(NA,0,1),c(1,1,1),c(0,1,1)),ncol=3)
and I want to create a new matrix by checking each element of the data and
put value 0 if i have NA and 1 otherwise.
For this reason i made the function below
pdata<-matrix(NA,ncol=ncol(data),nrow=nrow(data))
pdata<-sapply(1:nrow(data),function(i) sapply (1:ncol(data),function(j)
if (is.na(data[i,j]))
2002 Jan 04
0
R CMD check, file permissions (PR#1239)
SunOS fluke 5.8 Generic_108528-07 sun4u sparc SUNW,Ultra-Enterprise
R-1.4.0
Running from the command line
R CMD check chlib
results in the log file 00check.log:
* using log directory `/home/woodstock/hoffmann/R/Sources/chlib.Rcheck'
* checking for file `chlib/DESCRIPTION' ... OK
* checking package directory ... OK
* checking for sufficient/correct file permissions ... WARNING
*
2006 Mar 10
3
Sweave scientific real display format (e.g. 5e-12)
Dear All,
I couldn't figure and couldn't google out how to make construct a pair of
\Sexpr s or a LaTeX macro that would include
5\cdot 10^{-12}
into the LaTeX output istead of
5e-12 .
Any ideas?
Thank you
G?bor
2009 Jan 27
1
Problem with RMA using limma, oligo and pdInfoBuilder packages
Hi,
I am a Ph.D. student from Québec, Canada. I’m a beginner with R and
Bioconductor. Until now the only experience I have is in analyzing
microarray data using affy and limma packages. Now I am trying to analyze
Rat Gene 10 st arrays and I would like to run RMA analysis and Smyth
moderated t test on those arrays. Since no cdf official package is available
for those arrays, after reading many
2010 Oct 20
1
Generate variable with Bivariate Normal Distribution
Dear All
I want to generate variable with Bivariate Normal Distribution by
use mean1 = a, variance1 = b, mean2 = c, variance2 = d, rho = e.
How I can do this.
Many Thanks.
IRD
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