similar to: Layering multiple persp plots

Hello folks, i'm a R beginner and i want to put in a same plot both contour lines and persp plot. For example, fn<-function(x,y){sin(x)+2*y} #this looks like a corrugated tin roof x<-seq(from=1,to=100,by=1) #generates a list of x values to sample y<-seq(from=1,to=100,by=1) #generates a list of y values to sample z<-outer(x,y,FUN=fn) #applies the funct. across the combos of x

Hello R-sters, I'm trying to add several lines to a response surface that I've plotted using persp(). I've tried lines() using the "trans3d" function but I've been unsuccessful in getting it to work (R v2.0.1). Essentially, I'm trying to highlight one or more of the surface wireframe lines in a bolder (or different) color. Any tips from those of you who have some

Hi, I am using function wireframe from package lattice to draw a 3D surface. I would like to add a few points on the surface. I read in a post from Deepayan Sarkar that "To do this in a wireframe plot you would probably use the panel function panel.3dscatter". Does someone have an example? When calling panel.3dscatter with only x, y and z arguments I get "argument

Hello all, I’m trying to add some data points to a wireframe. X an Y axis are independent variables, Z axis is predicted probability. I’d like to add the original data points on which the predicted probabilities are based to the wireframe. I’ve followed some of the previous post on this but get stuck : ## first part yields the wireframe## setwd("C:/Temp") rnp <-

Dear expeRts, I would like to add two points to a wireframe plot. The points have (x,y,z) coordinates where z is determined to be on the wireframe [same z-value]. Now something strange happens. One point is perfectly plotted, the other isn't shown at all. It only appears if I move it upwards in z-direction by adding a positive number. So somehow it disappears in the wireframe-surface

I would like to add points to a wireframe but with a conditioning variable. I found a solution for this without a conditioning variable here, http://finzi.psych.upenn.edu/R/Rhelp02a/archive/65321.html. Does anyone know how to plot a wireframe conditioned on a variable and add the points conditioned on the same variable, similar to the solution at the link above?

Hi, I draw a surface corresponding to bivariate density of independent variables (rho=0) using persp(). Then I add a contour line (i.e., circle in my case) at a particular density. Below is a minimal example of what I have so far. # Bivariate density dnorm2d <- function(x, y, rho = 0) { xoy = (x^2 - 2 * rho * x * y + y^2)/(2 * (1 - rho^2)) density = exp(-xoy)/(2 * pi * sqrt(1 - rho^2))

Hi, I want to draw a figure similar to http://dsarkar.fhcrc.org/lattice/book/images/Figure_13_07_stdBW.png from http://lmdvr.r-forge.r-project.org/figures/figures.html (figure 13.7) . However instead of using a contour plot as a panel for the wireframe I want to use a levelplot. Can somebody help me with this? Thanks in advance for any help, Kind regards, Anton Bossenbroek

Hi, I'm trying to follow the suggestions given by Deepayan Sarkar in this message: http://tolstoy.newcastle.edu.au/R/help/05/11/16135.html to plot 3-D points on a wireframe plot. The problem is that I keep getting a partly formed plot- with the colored lattice visible but no axis labels or additional points- with the error message "error using packet 1, 'x' and 'units'

How can I eliminate the border drawn by default around a wireframe plot? I've tried using border=NA and box=FALSE to no avail. Scott Waichler Pacific Northwest National Laboratory scott.waichler at pnl.gov

Hello, I would like to plot a wireframe of a function which is defined on the unit square using the lattice library (for trellis-like plots). The plot contains z-values of about 100 (only in the neighborhood of zero) although most of the z-values are in the range of -let's say- 0 to 10. If I evaluate this function on an equidistant grid of 25 points on the unit square the plot quality is not

Hello, hopefully simple question, but I cannot find the answer. I need to change the color from the standard default. Still want the scaled colors, but need different colors for different graphs. Code is: wireframe(z ~ y*x, mat.df, drape = TRUE, zlab = list("Water mass error (%)",rot=92), zlim=c(-50,180), xlab = list("Resistance error

Buenas tardes, Podria por favor alguien ayudarme a descifrar por que no es posible ver la grafica 3D cuando se utiliza lattice? Ya se que algunas veces los duendes hacen de las suyas, pero no estoy seguro de que este sea el caso. He reiniciado R, cambiado a RStudio y utilizado XP, pero no pasa "nada". Mi sessionInfo() es: R version 2.14.0 Patched (2011-11-12 r57642) Platform:

I need grayscale formatting for a wireframe. The only col.regions that I can find are color palettes are all colored: rainbow(n, s = 1, v = 1, start = 0, end = max(1,n - 1)/n, gamma = 1, alpha = 1) heat.colors(n, alpha = 1) terrain.colors(n, alpha = 1) topo.colors(n, alpha = 1) cm.colors(n, alpha = 1) The code follows: X11() library(lattice) par(family="serif", cex=1.2)

Hello List, I have some plots with the wireframe() function, and I'd like to display them in a single jpeg file. I know that par(mfrow=c(x,y)) will divide my display window in x rows and y columns, and although this works with plot(), it looks like it's not working with wireframe. here's my code: library(lattice) library(Cairo) CairoJPEG("wiley-rank.jpeg", width=960,

I am working on plotting a response surface using wireframe(). The default style/orientation is z | | y | \ | \ | \ | \ | \ | \ | \ | \|________________x 0 Now what I want the orientation of axes is: z | | | |

Dear All, I'd like to know if it is possible to create animations with R. To be specific, I attach a code I am using for my research to plot some analytical results in 3D using the lattice package. It is not necessary to go through the code. Simply, it plots some 3D density profiles at two different times selected by the user. I wonder if it is possible to use the data generated for different

Moved the node administration elements to a separate submenu. Created a new network administration menu. * users can define a network * users can create a network * users can destroy a network * users can undefine a network * users can list existing networks, including details Each new command is also available as a separate command line executable as well. Signed-off-by: Darryl L. Pierce

Hello, The following code produces a quadrilateral: q<-matrix(c(1,3,1,2,3,1,2,4,2,1,4,2),nrow=4,byrow=T) qc<-xyz.coords(q) wireframe(z~y*x,qc) I have 2 questions 1) How can i remove the bounding box i.e the cube encompassing the quadrilateral? 2) Is there any function to get the 2D coordinates of the quadrilateral actually used in the final plot ? I could manually

Hi R-helpers I would like to plot some planes which are perpendicular to the x-y plane, such as x=y. Is there a way to do this in wireframe? I realize that I am not plotting a function of x, y since there are infinite number of z's that satisfy the above relation.... Hmm... Somewhat related, I would also like to plot a line in 3 d space... Finally, if you are feeling really brave, I