similar to: looking for setdiff equivalent on dataset

Dear R-devel, Please see the recent thread on R-help, "Odd Behavior Out of setdiff(...) - addition of duplicate entries is not identified" posted by Jason Rupert. I gave an answer, then read David Winsemius' answer, and then did some follow-up investigation. I would like to change my answer. My current version of setdiff() is acting in a way that I do not understand, and a way

Dear R-devel, Please see the recent thread on R-help, "Odd Behavior Out of setdiff(...) - addition of duplicate entries is not identified" posted by Jason Rupert. I gave an answer, then read David Winsemius' answer, and then did some follow-up investigation. I would like to change my answer. My current version of setdiff() is acting in a way that I do not understand, and a way

Thank you for your answers, I have another question: the behaviour of setdiff(indicesFalse, indicesNA) does not seem predictable to me. > indices [1] 1 2 3 4 5 6 > compareVector [1] NA TRUE TRUE TRUE FALSE NA > indicesNA = indices[is.na(compareVector)] > indicesNA [1] 1 6 > indicesFalse = indices[compareVector == FALSE] > indicesFalse [1] NA 5 NA >

Hello, I have been interested in setdiff() for data frames that operates row-wise. I looked in the documentation, mailing lists, etc., and didn't find exactly the right thing. Given data frames A, B with the same columns, the goal is to extract the rows that are in A, but not in B. Of course, one can usually do setdiff(rownames(A), rownames(B)) but that is cheating. :-) I played around a

Dear List, I have a data structure like: > aa [[1]] [1] 1 2 3 [[2]] [1] 4 5 6 > bb [[1]] [1] 3 [[2]] [1] 5 I would like to set differences between "aa" and "bb" and get as result another list of lists like: > res [[1]] [1] 1 2 [[2]] [1] 4 6 I am trying: lapply(aa, setdiff, bb) but I simply get "aa" back as result. Could you please point me in the

Hola Marcos. Yo probaría algo del estilo a esto.... Intersecc<-v1[v1%in%v2] Un saludo, _____________________________ Miguel Ángel Rodríguez Muíños Dirección Xeral de Innovación e Xestión da Saúde Pública Consellería de Sanidade Xunta de Galicia http://dxsp.sergas.es -----Mensaje original----- De: r-help-es-bounces en r-project.org [mailto:r-help-es-bounces en r-project.org] En nombre

I think I am using the improved version of setdiff(...) that handles data.frames, so I think some odd behavior was expected but this one is escaping me. It appears that the the addition of duplicate entries is not caught by the setdiff(...). Is this expected behavior? If so, is there another method or approach that should be used to identify duplicate row entries between two different data

hola, tengo dos vectores de 1134 y 385 elementos que se corresponden con números de accesión de genes. Necesito saber que números son comunes o intersección de vectores. He utilizado intersect(x,y) y me da todo el rato un único valor: V1 V1.1 V1.2 V1.3 V1.4 V1.5 V1.6 V1.7 V1.8 V1.9 V1.10 V1.11 V1.12 1 AJ558305 AJ558305 AJ558305 AJ558305 AJ558305

Hi everybody! I'm looking for a function or option to make a full screen plot.. can you help me? and I would like to know if it's possible to automaticaly close a x11 windows.. because i have more than 100 graph to generate and what i want is: 1 - make a full screen graph 2 - save this plot in emf format 3 - close the plot (goto 1) thanks for your advices [[alternative HTML version

hi, I have 2 files example 1 and example 2 and would like to know what is in example2 and not in example1 (attached) V1 contain data which could be in duplicated which I am using as identifiers I used setdiff(example2$V1,example1$V1) to find the identifiers which are specific to example2: [1] "rs2276598" "rs17253672" I am looking for a way to get an output with all

Hi, Actually, i use the function merge like this: (Data1 <- Data1[1:7,1:3])   Policy.Number AXA.Entity Country 1    1060000077        BNL     BNL 2       4001023         CH     BNL 3    1060000006         UK     BNL 4       4001025         CH     BNL 5      6.00E+13        USA     BNL 6       6100001         UK     BNL 7       4001028        USA     BNL > Data2 <-

trying to switch out addresses that have double directions, such as the following example: a = "S S Main St & Interstate 95" a = gsub(pattern="S S ", replacement="S ", a) … the problem is that I don't want to affect instances where this might be a correct address such as the following: "3421 BIGS St" what I want to say is switch out only if

Hi Is it possible to subset an n-dimensional array by a vector of n dimensions? E.g. assume I have > x <- array(1:24, dim=2:4) > x[1,1,2] [1] 7 > dims <- c(1,1,2) I would like a function that I can supply x and dims as parameters to, and have it return 7. Also, I would like to do something like: > x[1,1,] [1] 1 7 13 19 > dims2<- c(1,1,NA) And have a function of x and

Hi, I was *very* surprised by this little trick for new players: mean() only considers its first argument! > mean(1,1,2) [1] 1 > mean(2,1,1) [1] 2 I found this very different behaviour to max(): > max(1,1,2) [1] 2 > max(2,1,1) [1] 2 Perhaps this is the wrong list to ask, but does anyone else think this a little on the interesting side? Is it not possible to detect a

hi, Excuse me asking three questions in a row for a day, but I had collected those questions as I'm still experimenting with R. This one is how do you compose plots with alot of data in one graph. First what I currently do is after i generated all the data I need to plot.. let say 5-6 arrays I do a plot() and then I created a function to scale the other data to approx fit the initial range so

Hi I have a problem with need for speed or my drivers because when I install the game everything is perfect :) but when i try to to play i can't see the pictures i see only like shadows and like a bigs pixels in the screens, i have ubuntu 10.04 y wine version 1.2 i have the same problem with need for speed carbon and i have 3D aceleration

Hi Consider the following graph: x <- rnorm(1000) x <- x + exp(-x/2) layout(matrix(rep(c(1,1,2), 2), 2, 3, byrow=TRUE)) boxplot(x) rug(jitter(x), side=2) plot(density(x)) What I would really like to do is to have the density plot rotated by 90 degrees so that I can see it line up with the rug plot on the side axis. I cant seem to do this. I have seen references to the grid

Hi all, I would like to have a function like this: split.vec.by.NA <- function(x) That takes a vector like this: x <- c(2,1,2,NA,1,1,2,NA,4,5,2,3) And returns a list of length of 3, each element of the list is the relevant segmented vector, like this: $`1` [1] 2 1 2 $`2` [1] 1 1 2 $`3` [1] 4 5 2 3 I found how to do it with a loop, but wondered if there is some smarter (vectorized) way

Third try... > -----Original Message----- > From: Warnes, Gregory R > Sent: Tuesday, February 05, 2002 4:12 PM > To: 'R-bugs' > Subject: layout and piechart diameter problem > > > I've been using layout to create some graphics pages which include pie > charts. (NB: No piechart arguments please, the main chart on the page is > a proper bar chart

Dear R-users,  I have a problem, I have the following dataframe:   d<-data.frame(  'y1'=c(1,2,1,2,1,NA,NA), 'y2'=c(1,2,1,1,1,2,1), 'y3'=c(1,NA,1,NA,NA,2,1), 'y4'=c(NA,2,NA,1,1,2,NA), 'a'=c(1,1,1,1,1,1,2) ) where the last variable counts the number of missing values in a row. Now, i want to set rows where a>1 to NA and arrive at something like the