similar to: writing function

Dear group, I have a function, let's call it myfun, wich give me a list of result: R1,R2,R3... There is a loop in this function to get my results. Here is the structure of my function: Myfun<-function() { For (i in X ){ -----------instructions--------- Ri { { All Results (R1,R2...) are Data.frame. As a final result (call it "Final"), I need to rbind all these dataframe. One

Dear group, Here is my environment: > ls() [1] "DailyPL100419" "DailyPL100420" "DailyPL100421" "dd" "i" "l" "PLglobal" "Pos100416" "Pos100419" "Pos100420" "Pos100421" "position" [13] "result" "sel"

Dear group, Here is a list of elements : l <- c("100415", "100416", "100419", "100420", "100421", "100422", "100423", "100426", "100427", "100428", "100429", "100430", "100503", "100504", "100505", "100506", "100507",

Dear group, Here is a list : l <- list("100415", "100416", "100419", "100420", "100421", "100422", "100423", "100426", "100427", "100428", "100429", "100430", "100503", "100504", "100505", "100506", "100507",

Dear group, Here is my function: #return the daily PL for day y PLDaily<-function(x,y) { #find elements in my directory with "LSCPos" in the name, keep the numeric part in the name and #create a list l<-gsub("\\D","",dir()[grep("LSCPos",dir())]) #select in the list the desired elements

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Dear users, I would like all the ticks on a boxplot (x and y) to be labeled I have checked all the par() arguments but couldn't find what I'm looking for Here is an example to show it: df <- structure(list(SPECSHOR = structure(c(1L, 1L, 1L, 3L, 3L, 3L, 3L, 3L, 4L, 4L), .Label = c("cotau", "dibic", "eqgre", "gicam"), class =

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

Hello, How can I read a xlsx file using xlsx package? Thanks Albert [[alternative HTML version deleted]]

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the

Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive

It's often difficult to figure out what a problem data set looks like when someone pastes a mess of output from R into an e-mail. The dput command, used judiciously?I would hope no one would send a 1 M data set?can make life much easier. I wonder if it would be useful to add a hint in the instructions at the bottom of the posting page, where the list asks for self-contained reproducible

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

Dear users, I would like to process all the lists from all *.rda files that I have in one folder. Up to now, I can load all the *.rda files without any problem. The problem is when I want to access the list saved within each *.rda file (only one list per rda file). Here is my code: fpath <- "D:/R" listnames <- list.files(path=fpath, pattern=glob2rx("*.rda"),