similar to: Revolution R and the R Community?

PlayStation3 with Ubuntu 9.10. revolution-r: Depends: r-revolution-revobase but it is not installable Hi All, I have a PlayStation3 setup with Ubuntu 9.10. Install R went fine with "sudo apt-get install r-base-core" I then attempted to install Revolution packages with "sudo apt-get install revolution-r" This failed with the following error : *Some packages could not be

some hints for the search engines. I just did install.packages("foreach") install.packages("doMC") library(doMC) registerDoMC() library(foreach) > foreach(i = 1:3) %dopar% sqrt(i) The process has forked and you cannot use this CoreFoundation functionality safely. You MUST exec(). Break on

Dear R wizards: is there a clean way to assign to elements in a list? what I would like to do, in pseudo R+perl notation is f <- function(a,b) list(a+b,a-b) (c,d) <- f(1,2) and have c be assigned 1+2 and d be assigned 1-2. right now, I use the clunky x <- f(1,2) c <- x[[1]] d <- x[[2]] rm(x) which seems awful. is there a nicer syntax? regards, /iaw ---- Ivo Welch

dear R experts---now I have a case where I want to estimate very large regression models with many fixed effects---not just the mean type, but cross-fixed effects---years, months, locations, firms. Many millions of observations, a few thousand variables (most of these variables are interaction fixed effects). could someone please point me to packages, if any, that would help me estimate such

dear R experts---I am using the coef() function to pick off the coefficients from an lm() object. alas, I also need the standard errors and I need them fast. I know I can do a "summary()" on the object and pick them off this way, but this computes other stuff I do not need. Or, I can compute (X' X)^(-1) s^2 myself. Has someone written a fast se() function? incidentally, I think

this is not an important question, but I wonder why lm returns an error, and whether this can be shut off. it would seem to me that returning NA's would make more sense in some cases---after all, the problem is clearly that coefficients cannot be computed. I know that I can trap the lm.fit() error---although I have always found this to be quite inconvenient---and this is easy if I have only

I ran into an interesting oddity of R, if (0) { print(1); } else { print(2); } is a syntax error, while if (0) { print(1); } else { print(2); } or if (0) { print(1); } else { print(2); } is not. I presume it has to do with the duality of the newline functioning as an end of command (;) character, though it still seems a bit odd, and it took me a while to figure out

Dear R wizards: I decided to take the advice in the R data import/export manual and want to learn how to work with SQL for large data sets. I am trying SQLite with the DBI and RSQLite database interfaces. Speed is nice. Alas, I am struggling to find a tutorial that is geared for the kind of standard operations that I would want in R. Simple things: * how to determine the number of rows in a

dear R wizards:? I am wrestling with reshape.? I have a long data set that I want to convert into a wide data set, in which rows are firms and columns are years. > summary(rin) firm fyear sim1 Min. :1004.00 Min. :1964.0 Min. : -1.00000 1st Qu.:1010.00 1st Qu.:1979.0 1st Qu.: -0.14334 Median :1016.00 Median :1986.0 Median : 0.00116 Mean

dear R group: I have the probably fairly common problem that I would like to have one code.R file do different things if it is invoked from a symbolic link, which should be easy to uncover. $ ln -s code.R code-0.R $ ln -s code.R code-1.R $ R CMD BATCH code-1.R what needs to be in code-1.R to put code-1.r into a character vector? help appreciated. regards, /ivo welch PS : I read

dear R wizards: here is the strange question for the day. It seems to me that nrow() is very slow. Let me explain what I mean: ds= data.frame( NA, x=rnorm(10000) ) ## a sample data set > system.time( { for (i in 1:10000) NA } ) ## doing nothing takes virtually no time user system elapsed 0.000 0.000 0.001 ## this is something that should take time; we need to add 10,000

hi: where would I find facilities to draw circles, ovals, and semicircles? (or should I construct them myself using curve?) regards, /ivo

Dear R wizards---I read Brian Ripley's post from 2004 which said that it was not possible to print to STDERR. Alas, I have more modest needs. I was wondering if it was possible to just send a string to STDERR with cat() while in CMD BATCH mode. Is it not possible to open STDERR in R? (Or does R use STDERR for itself and redirect it into the output stream?) This would be on a standard Unix

Has anyone heard whether Revolution Analytics is going to release this capability to the R community? http://www.businesswire.com/news/home/20110201005852/en/Revolution-Analytics-Unlocks-SAS-Data Dan Daniel Nordlund Bothell, WA USA

Dear users, The company where I work is considering getting a license for Revolution Enterprise - Windows 64-bit. I'll appreciate for those familiar with the product if can share your experiences with it? In particular, how does it compare to the "free" version of R 64-bit? Thanks in advance. Regards, Lars. [[alternative HTML version deleted]]

dear readers---I struggled with how to do nice fixed-effects regressions in large economic samples for a while. Eventually, I realized that nlme is not really what I needed (too complex), and all I really wanted is the plm package. so, I thought I would share a quick example. ################ sample code to show fixed-effects models? in R # create a sample panel data set with firms and years

Dear R developers---I just spent half a day debugging an R program, which had two bugs---I selected the wrongly named variable, which turns out to have been a scalar, which then happily multiplied as if it was a matrix; and another wrongly named variable from a data frame, that triggered no error when used as a[["name"]] or a$name . there should be an option to turn on that throws an

I know this is not a revolution support forum, but as anyone noticed the following? I have a foreach loop to generate random samples. If I run the exact code below in normal r (2.14.1) it works as expected, but if I run it from revolution 4.2.0 each loop returns the same numbers. The only way I can get revolution to give different numbers is using 1 instead of 8 in registerDoSNOW(makeCluster(8,

Hola a todos, he encontrado una aplicación que se llama Revolution R, éste es su link: http://www.revolutionanalytics.com/why-revolution-r/benchmarks.php Presume de poder realizar procesamiento en paralelo. Me gustaría saber si eso es cierto, si merece la pena y si el procesamiento en paralelo se realiza de forma transparente al usuario o hay que programarlo. saludos, Fernando

R version 2.5.0, under gentoo linux. This may be just my ignorance about naming conventions inside loops and subsets, but the following appears like a bug to me. y = c( 1963, 1963, 1964, 1964, 1965, 1965 ); r1= rnorm(6); d= data.frame ( y=y, r1=r1 ); ## note: I am not attach()ing anything anywhere ## this should give me two results, which it does ahw.y= subset(d, d$y==1963);