similar to: How to plot line, points, using Dates as X-axis

I am trying to plot a image where the x axis has the units of time. When I issue the image(x,y,z) command with x as a POSIXct object, it fails to put a time stamp on the x axis. Instead I get a warning "Incompatible methods" warning and no dates on my x axis. This example shows my problem: Rmat=t(matrix(data=rnorm(1:500),ncol=10,nrow=50)) tax=seq(ISOdate(2010,4,14,12,0,0),

I'd like to make a plot showing frequency of an event. The data is in a data from that includes Year, Month and Day (of month) fields, so I created a Date with ISOdate(Year, Month, Day, tz=''). I can plot frequencies for the year 2002 with > thisyear <- Date[Year==2002] > hist( thisyear, xaxt='n' ) > axis.POSIXct( 1, at=seq(min(thisyear), max(thisyear),

Hello R-experts! I am using R Version 1.7.1 (2003-06-16) on a Debian Linux box and I have discovered an odd result when plotting data involving dates. Please try this minimal example: a = seq(ISOdate(2000,1,1), ISOdate(2001,1,1), "months") b = 1:13 plot(a,b, col="red") What I get is a plot that looks as expected except the x-axis is mostly red. Can anyone reproduce this

Hello, I gather variants of this question have been asked previously. I have done some reading but only became more confused, as I suspect what I am trying to do is more basic than other applications. The following code readily calculates the difference in days between two dates: newdays <- ISOdate(2005, 5,12) - ISOdate(2006, 12, 22) However, I wanted to be able to deduct the dates in

Hello, x <- ISOdate(2003, 4, 1:30) # POSIXct vector y <-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30) aline <- c(30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1) plot(x, y, xaxt = 'n', main = 'Number of Stuff for the Project, April 2003', xlab = 'Report Time', ylab = 'Number of

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

The interface for dates in R is a little confusing to me. I want to create a vector of Date objects from vectors of years, months, and days. One solution I found is: years <- c(1991, 1992) months <- c(1, 10) days <- c(1, 2) dates <- as.Date(ISOdate(years, months, days)) But, in this solution the ISOdate function converts the vectors into characters, which can cause serious

Hello, I am attempting to create plots using two continuous variables and it seems I should be able to use the simple "plot" command. However, my x-axis values are dates, and I believe this could be the reason I am receiving error messages reading: Error in Summary.factor(c(2L, 4L, 3L, 5L, 6L, 7L, 1L), na.rm = FALSE) : range not meaningful for factors I have attempted to

Dear all, I have found the following (for me) incomprehensible behaviour of ISOdate (POSIXct): > ISOdate(1900,6,16) [1] "1900-06-15 14:00:00 Westeurop?ische Sommerzeit" > ISOdate(1950,6,16) [1] "1950-06-16 14:00:00 Westeurop?ische Sommerzeit" Note that in the first case I get the 15th of June back, not the 16th as I would have expected! This happened under R-1.7.1 on

Hi, I want to display dates on my x-axis of the plot. I was trying to use plot() command for the same and passing the values in following manner: The variable "dat" is a data frame. The first column has numeric values and second column has date. e.g. dat [,1] dat[,2] [1,] 300 20060101 [2,] 257

Thanks for this clarification. I have learned in the meantime that it is necessary to be very careful when using all these POSIX things. As another example, here is something that made me scratch my head just yesterday: When I create a sequence of days that happens to start before and ends in daylight savings time, I seem to lose a day: > seq(from = strptime("20030329",

The most important thing is that Date objects by definition do not include time of day. You want to look at ISOdatetime() and as.POSIXct() instead. And beware daylight savings time issues. -pd On 18 Apr 2016, at 15:09 , Ogbos Okike <giftedlife2014 at gmail.com> wrote: > Dear All, > > I have a data set containing year, month, day and counts as shown below: > data <-

Dear list: working with date/times I have come across a problem that ISOdate and ISOdatetime are too slow on large vectors of data. I was surprised just until I looked at the implementation and the man page: "ISOdatetime and ISOdate are convenience wrappers for strptime". In other terms, they convert data to character representation first in order to create a POSIXlt object that is then

hi, I've troubles with some difftime objects. e.g. ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) - 2 works, telling me "Time difference of 57 days". But when I'd like to add days, such as ISOdate(2001, 4, 26) - ISOdate(2001, 2, 26) + 2 the function gives me an error. Function "as.COMDate.chron" of the Rbloomberg package doesn't work for that reason. I'm

Dear All, Many thanks for bailing me out. Ogbos On Apr 18, 2016 9:07 PM, "David Winsemius" <dwinsemius at comcast.net> wrote: > > > On Apr 18, 2016, at 10:44 AM, Ogbos Okike <giftedlife2014 at gmail.com> > wrote: > > > > Dear ALL, > > Thank you so much for your contributions. > > I have made some progress. Below is a simple script I

Dear R-people! I am using R 1.8.0, under Windows XP. While using ISOdate() and strptime(), I noticed the following behaviour when "wrong" arguments (e.g., months>12) are given to these functions: > ISOdate(year=2003,month=2,day=20) #ok [1] "2003-02-20 13:00:00 Westeurop?ische Normalzeit" > ISOdate(year=2003,month=2,day=30) #wrong day, but returns a value [1]

Dear R list, I want to plot the yield curve in a 3D graph: the x-axis refers to time; the y-axis refers to the maturities and the z-axis are the yields. The following code works fine: persp(y, x, as.matrix(ypper), xlab="Last 50 periods", ylab="Maturities (months)",zlab="Yields", zlim=c(3,6),theta=130, phi=15, col="Seagreen", box=T,

Dear ALL, Thank you so much for your contributions. I have made some progress. Below is a simple script I gleaned from your kind responses: Sys.setenv(TZ="Etc/GMT") dates <- c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92") times <- c("23:0:0", "22:0:0", "01:00:00", "18:0:0",

Although the documentation is somewhat sketchy, I() can be used to create objects of class AsIs: > I("a") [1] "a" attr(,"class") [1] "AsIs" "character" > I(4) [1] 4 attr(,"class") [1] "AsIs" "numeric" > I(4 + 0i) [1] 4+0i attr(,"class") [1] "AsIs" "complex" > This

Hello useRs, I'm using version 2.0.1 on Windows XP. I have a data.frame with 3 factors and a date. The data.frame is sorted by the 3 factors and by date. I would like to create a new factor designating membership in a group. Each group is defined as having the same factor values and dates that are less than some number (e.g. 10) days apart. Does anyone have any suggestions as to how to