similar to: [Beginner] Issue with the barplot function

> On Jun 23, 2017, at 5:53 AM, Jay Zola <jayjay.1988 at hotmail.nl> wrote: > > Dear sir/madame, > > > I am currently writing a meta-analysis on the complication and reoperation rates of 5 different treatment modalities after a distal radius fracture. I was able to pool the rates of the 5 different rates using R. Now I have to compare the pooled rates of the 4 treatment

Dear sir/madame, I am currently writing a meta-analysis on the complication and reoperation rates of 5 different treatment modalities after a distal radius fracture. I was able to pool the rates of the 5 different rates using R. Now I have to compare the pooled rates of the 4 treatment modalities with the golden standard separately. I though the chi squared test would be the best method. How do

Probably the wrong list. R-help is concerned with R programming, not statistics methodology questions, although the intersection can be nonempty. I suggest you post on stats.stackexchange.com instead, which *is* concerned with statistics methodology questions. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into

HI, I am a studient, so don't be surprise if my question seems so simple for you... I have a dataframe with 6 qualitative variables divided in 33 modalities, 2 qualitatives variables and 78 lines. I use a glm to know wich variables have interactions... I would like to know if its normal that one (the first in alphabetical order) of the modalities of each qualitatives variable doesn't

Note though that this has been put on hold on stats.stackexchange.com as off-topic. On 23/06/2017 19:33, Bert Gunter wrote: > Probably the wrong list. R-help is concerned with R programming, not > statistics methodology questions, although the intersection can be > nonempty. > > I suggest you post on stats.stackexchange.com instead, which *is* > concerned with statistics

What is the best way to change my R code to be able to compare the pooled proportions(complication and reoperation rates) with the Chi square method? Verstuurd vanaf mijn iPhone > Op 24 jun. 2017 om 14:18 heeft Michael Dewey <lists at dewey.myzen.co.uk> het volgende geschreven: > > Note though that this has been put on hold on stats.stackexchange.com as off-topic. > >>

Dear advanced statisticians, *******Objectif******** I try to set up linear models with mean as intercept: Answer: y Variable: x, as factor of two modalities: x(1), x(2). I would like to have a model as: y = mean(y)+A(i)+residuals, with i in (1,2) and A(1) coefficient for x(1) and A(2) coefficient for x(2). *******Trials in R******* ## Firstly: I write in R: >Model<-lm(y~x,Data)

Dear List, my problem should be easy to fix, but I couldn't find a solution by myself... In my survey, there is a question with 14 possible answers. None of the respondents choose the 13th answer, so when I table() the results, R says: 1 2 3 4 5 6 7 8 9 10 11 12 14 31 52 7 21 40 7 8 2 28 2 2 1 17 13 is missing... anyone knows how to tell table() that there are 14 modalities in the

Dear R users,I am looking for an easy (i.e., direct) way in obtaining the F and p values from the intercept in anovas with within-subject designs. Data are from a psychophysics expeirment where I am using d' (d-prime) values obtained from 3 modalities of presentation in each subject.I would like to know not only whether there is an effect of modality, but also wether the main effect is

I have exported a CSV file from my EXCEL worksheet and its last column contained decimal values: Subject;Group;Side;Difference;PercentError M3;1;1;; M5;1;1;375;18,75 M8;1;1;250;14,58 M10;1;1;500;12,50 M12;1;1;375;25,00 . . . When I tried to do ANOVA test on it, R complained by givin error: > Anova3LongAuditoryFemaleError.data <- read.csv("C:\\Documents\ and\

Dear R users, I am looking for an easy (i.e., direct) way of obtaining the F and p values from the intercept in anovas with within-subject designs. My data are from a psychophysics experiment where I am using d' (d-prime) values obtained from 3 modalities of presentation in each subject. I would like to know not only whether there is an effect of modality, but also whether the main effect is

Hi users I'm student who is struggling with basic R programming. Would you please help me with this problem. "My english is bad" I hope that my question is clear: I have a matrix in wich there are two colmns( yp, yt) Yp: predicted values from my model. yt: true values ( my dependante variable y is a categorical;3 modalities (0,1,2) I don't know how to procede to calculate the

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Hello, I am writing a meta-analysis on the complication and reoperation rates after 5 treatment modalities of a distal radius fracture. I have a code to compare the complication and reoperation rates. Currently it is using a mixed effects model. Is it possible to change the code so a random effects model is used? Thank you very much, Jay R code library(meta) library(readxl) All <-

R provides a few ways of handling missing values, a.o. in the context of an anova (aov); 2 types of exclusion, and failure. In some situations, I personally like to have missing values replaced by the mean (or the median) for the given combination of factors. A routine that does that is something like the code included below. It works, but is (of course) rather slow. It would be much quicker

Good afternoon, I REALLY try to answer to my question as an autonomous student searching in the huge pile of papers on my desk and on the Internet but I can't find out the solution. Would you mind giving me some help? Please. ######################################### I'm trying to use glm with factors: > Pyr.1.glm<-glm(Pyrale~Trait,DataRav,family=poisson) If I have correctly

Hi, I have two different imaging modalities (for the identification of areas of infarcted myocardium) that I need to compare regarding agreement and consistency. However, I don't think that methods like Cohen's Kappa, PCC, Bland-Altmann or ICC are sufficient here as there is not just a pairwise but also a spatial relationship between measured data points. For example if the results of the

http://dovecot.org/test/ Well, remember when I said: > Here you go, maildir syncing problems finally fixed (I hope). Well, > except there's this "new-dir-only syncing" optimization which I'm not > really sure if it works as it should. Just before I found the expunge bug in index, I was trying to fix the new-dir-only syncing because the code looked wrong. Then I

1. You neglected to cc r-help! 2. Word files are **not** text files. -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Fri, Jun 23, 2017 at 12:23 PM, Jay Zola <jayjay.1988 at hotmail.nl> wrote: > Dear sir, > > >

Hello, I am medical student, writing a meta-analysis on complication and reoperation rates after the five most common treatments of distal radius fractures. I have been busy with the statistics for months by my self, but find it quite hard since our classes were very basic. Now I want to compare the treatment modalities to see if there are significant differences. Using R I was able to