similar to: Reading data

Displaying 20 results from an estimated 6000 matches similar to: "Reading data"

2017 Dec 09
2
Reducing code size of Position Independent Executables (PIE) by shrinking the size of dynamic relocations section
* Rahul Chaudhry via gnu-gabi: > The encoding used is a simple combination of delta-encoding and a > bitmap of offsets. The section consists of 64-bit entries: higher > 8-bits contain delta since last offset, and lower 56-bits contain a > bitmap for which words to apply the relocation to. This is best > described by showing the code for decoding the section: > > typedef
2008 Apr 18
2
Correspondence and detrended correspondence analysis
Hi, I hope someone knows the answer to this or has a real good reference about it (I am using Legendre & Legendre, Numerical Ecology, 1998).... My data is a data.frame with locations as rows and vegetation assemblages / species as columns. I've done a PCA, a correspondance analysis (CA) using ca in ca package and a detrended correspondance analysis (DCA) using decorana from vegan package.
2006 Jun 08
3
Reading in a table with ISO-latin1 encoding in MacOS-X (Intel)
Dear colleages in R, I have earlier been working with R in Linux, where reading in a table containing Scandinavian letters ("?", "?", and "?") in the header as part of variable names has not caused any problem whatsoever. However, when trying to do the same in R running on new MacOS-X (with an Intel processor) with the same original text table does not seem to
2017 Dec 06
2
Remove
Hi Ashta, There are many ways to do it. Here is one: vars <- sapply(split(DM$x, DM$GR), var) DM[DM$GR %in% names(vars[vars > 0]), ] Best Ista On Wed, Dec 6, 2017 at 6:58 PM, Ashta <sewashm at gmail.com> wrote: > Thank you Jeff, > > subset( DM, "B" != x ), this works if I know the group only. > But if I don't know that group in this case "B", how
2017 Dec 09
1
Remove
Hello, Try the following. keep <- list(A = c(15, 30), B = c(40, 50), C = c(60, 75)) sp <- split(DM$x, DM$GR) inx <- unlist(lapply(seq_along(sp), function(i) keep[[i]][1] <= sp[[i]] & sp[[i]] <= keep[[i]][2])) DM[inx, ] # GR x y #1 A 25 125 #2 A 23 135 #5 B 45 321 #6 B 47 512 #9 C 61 521 #10 C 68 235 Hope this helps, Rui Barradas On 12/9/2017 12:48 AM, Ashta
2017 Dec 09
2
Remove
> On Dec 8, 2017, at 4:48 PM, Ashta <sewashm at gmail.com> wrote: > > Hi David, Ista and all, > > I have one related question Within one group I want to keep records > conditionally. > example within > group A I want keep rows that have " x" values ranged between 15 and 30. > group B I want keep rows that have " x" values ranged
2017 Dec 09
0
Remove
Hi David, Ista and all, I have one related question Within one group I want to keep records conditionally. example within group A I want keep rows that have " x" values ranged between 15 and 30. group B I want keep rows that have " x" values ranged between 40 and 50. group C I want keep rows that have " x" values ranged between 60 and 75. DM <-
2017 Dec 07
0
Remove
Thank you Ista! Worked fine. On Wed, Dec 6, 2017 at 5:59 PM, Ista Zahn <istazahn at gmail.com> wrote: > Hi Ashta, > > There are many ways to do it. Here is one: > > vars <- sapply(split(DM$x, DM$GR), var) > DM[DM$GR %in% names(vars[vars > 0]), ] > > Best > Ista > > On Wed, Dec 6, 2017 at 6:58 PM, Ashta <sewashm at gmail.com> wrote: >> Thank
2009 Oct 01
4
Color of graph
I am trying to plot a line graph for 3 or more regression lines abline(m1) abline(m2) abline(m3) Can I change the color of each line? if so how? Thanks in advance Ashta [[alternative HTML version deleted]]
2017 Dec 07
4
Remove
> On Dec 6, 2017, at 4:27 PM, Ashta <sewashm at gmail.com> wrote: > > Thank you Ista! Worked fine. Here's another (possibly more direct in its logic?): DM[ !ave(DM$x, DM$GR, FUN= function(x) {!length(unique(x))==1}), ] GR x y 5 B 25 321 6 B 25 512 7 B 25 123 8 B 25 451 -- David > On Wed, Dec 6, 2017 at 5:59 PM, Ista Zahn <istazahn at gmail.com> wrote:
2017 Dec 09
1
Remove
library(dplyr) DM <- read.table( text='GR x y A 25 125 A 23 135 . . . ) DM %>% filter((GR == "A" & (x >= 15) & (x <= 30)) | (GR == "B" & (x >= 40) & (x <= 50)) | (GR == "C" & (x >= 60) & (x <= 75))) On Fri, Dec 8, 2017 at 4:48 PM, Ashta <sewashm at gmail.com>
2017 Dec 09
0
Remove
> On Dec 8, 2017, at 6:16 PM, David Winsemius <dwinsemius at comcast.net> wrote: > > >> On Dec 8, 2017, at 4:48 PM, Ashta <sewashm at gmail.com> wrote: >> >> Hi David, Ista and all, >> >> I have one related question Within one group I want to keep records >> conditionally. >> example within >> group A I want keep rows that
2017 Dec 09
1
Remove
You could make numeric vectors, named by the group identifier, of the contraints and subscript it by group name: > DM <- read.table( text='GR x y + A 25 125 + A 23 135 + A 14 145 + A 35 230 + B 45 321 + B 47 512 + B 53 123 + B 55 451 + C 61 521 + C 68 235 + C 85 258 + C 80 654',header = TRUE, stringsAsFactors = FALSE) > > GRmin <- c(A=15, B=40, C=60) > GRmax <-
2023 Dec 08
2
regarding CCA plot
Hii rstudio members I am learning rstudio, For my manuscript I am trying to plot CCA using species and environmental data. But I am getting error like Error in cca.default(sptrans, envtrans) : all row sums must be >0 in the community data matrix *My code is like * library(vegan) library(ggplot2) library(dplyr) rassspec<-read.csv("C:/Users/hp/Desktop/R_data/rassspec.csv",
2009 Oct 14
2
Survival and nonparametric
Hi all, Has any body the exprience to iclude a nonparametric component into the survival analysis using R package? *Can someone recommend *me * some ** references? * Thanks a lot Ashta [[alternative HTML version deleted]]
2009 Sep 25
1
Binomial
Dear R-users, Suppose I have the following sample of data, 0 1 2 4 3 1 2 1 3 1 1 3 3 4 1 0 1 2 1 2 1 4 1 4 2 1 2 2 1 1 The first variable is the response variable where 0 is defective and 1 normal. The other four factors( x1,x2,x3,x4) that influence the outcome. I want to fit a binomial model . How do I do that? I am guessing the response variable
2009 Oct 10
1
Creating new variables
Hi all, I have a data set called x with 200 rows and 12 columns. I want create two more columns based on probability. ie if p >0 .4 then v1 =1 else v1=0; if p >0 .6 then v2 =1 else v2=0; Finally x will have 14 variables. Can any one show me how to do that? Thanks Ashta . [[alternative HTML version deleted]]
2010 Mar 25
1
how to deal with vector[0]?
Hi, I have a vector with 4 elements, e.g., tau_i=c(100,200,300,400), but potentially tau_i[0]=0. In a "for" loop, tau_i=c(100,200,300,400) m=4 tau_i[0]=0 # <------- ? P_i=1 for(i in 2:m) { P_i = P_i*(tau_i[i-1]-tau_i[i-2]) } Error in P_i = P_i * (tau_i[k - 1] - tau_i[k - 2]): replacement has length zero Unfortunately, I can add this potential element into
2012 Dec 12
1
data download
I am trying to download the tar files on the website below filename<-" http://rredc.nrel.gov/solar/old_data/nsrdb/1991-2010/SolarAnywhere/x.tar" where x is one those tar files I downloaded x using download.file(). But, the file was corrupt. Can someone help me how to download and untar these files using R. Thanks, Alemu [[alternative HTML version deleted]]
2017 Dec 06
0
Remove
Thank you Jeff, subset( DM, "B" != x ), this works if I know the group only. But if I don't know that group in this case "B", how do I identify group(s) that all elements of x have the same value? On Wed, Dec 6, 2017 at 5:48 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > subset( DM, "B" != x ) > > This is covered in the Introduction to