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Displaying 20 results from an estimated 5000 matches similar to: "Save data in txt"

2010 Oct 07
1
Quantile question
Simple Question I have 100x100 matrix and I want to calculte each row's 30,50% quantile ex) a=matrix(rnorm(10000),100,100) quantile(a[1,],c(0.3,0.5)) quantile(a[2,],c(0.3,0.5)) . . . . I want get results at once. so I try quantile(a[1:100,],c(0.3,0.5)) but I can get what I exactly want. How can I calculte that? -- View this message in context:
2010 Sep 24
1
color of lines while printing through for loop
I am trying to find a convenient way to control line colors when printing from a for loop using the lines command. Right now I have solved this by creating a colors vector that is refered to in the loop with index. However, the colors choosen here are just 1,2,3,4,5... I would like to get colors from the col = rainbow(x) that you can use in plot() and set the to be my number of lines (I think
2009 Feb 18
1
using stepAIC with negative binomial regression - error message help
Dear List, I am having problems running stepAIC with a negative binomial regression model.  I am working with data on manta ray abundance, using 20 predictor variables.  Predictors include variables for location (site), time (year, cos and sin of calendar day, length of day, percent lunar illumination), oceanography (sea surface temp mean and std, sea surface height mean and std), weather (cos
2009 Jan 26
1
glm StepAIC with all interactions and update to remove a term vs. glm specifying all but a few terms and stepAIC
Problem: I am sorting through model selection process for first time and want to make sure that I have used glm, stepAIC, and update correctly. Something is strange because I get a different result between: 1) a glm of 12 predictor variables followed by a stepAIC where all interactions are considered and then an update to remove one specific interaction. vs. 2) entering all the terms
2011 Aug 02
1
Modelo Regresión Lineal
Hola Juan. La regresión lineal es un método muy difundido y estoy seguro que con una breve búsqueda en internet podrás encontrar excelentes manuales en español. Puedes adelantar con saber que la función básica para regresiones lineales es lm() (de linear model) y para las variables que mencionas podrías utilizar: ajuste<-lm(razco_pr~razco_ps+razco_pc, data=tusdatos) summary(ajuste)
2003 Aug 04
1
Error in calling stepAIC() from within a function
Hi, I am experiencing a baffling behaviour of stepAIC(), and I hope to get any advice/help on what went wrong or I'd missed. I greatly appreciate any advice given. I am using stepAIC() to, say, select a model via stepwise selection method. R Version : 1.7.1 Windows ME Many thanks and best regards, Siew-Leng ***Issue : When stepAIC() is placed within a function, it seems
2017 Aug 22
1
boot.stepAIC fails with computed formula
SImplify your call to lm using the "." argument instead of manipulating formulas. > strt <- lm(y1 ~ ., data = dat) and you do not need to explicitly specify the "1+" on the rhs for lm, so > frm2<-as.formula(paste(trg," ~ ", paste(xvars,collapse = "+"))) works fine, too. Anyway, doing this gives (but see end of output)" bst <-
2006 Oct 11
1
Bug in stepAIC?
Hi, First of all, thanks for the great work on R in general, and MASS in particular. It's been a life saver for me many times. However, I think I've discovered a bug. It seems that, when I use weights during an initial least-squares regression fit, and later try to add terms using stepAIC(), it uses the weights when looking to remove terms, but not when looking to add them:
2005 Apr 05
2
cat bailing out in a for loop
Dear All, I am trying to calculate the Hardy-Weinberg Equilibrium p-value for 42 SNPs. I am using the function HWE.exact from the package "genetics". In order not to do a lot of coding "by hand", I have a for loop that goes through each column (each column is one SNP) and gives me the p.value for HWE.exact. Unfortunately some SNP have reached fixation and HWE.exact requires a
2017 Aug 22
1
boot.stepAIC fails with computed formula
Failed? What was the error message? Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Tue, Aug 22, 2017 at 8:17 AM, Stephen O'hagan <SOhagan at manchester.ac.uk> wrote: > I'm trying to use boot.stepAIC for
2003 May 02
2
stepAIC/lme (1.6.2)
Based on the stepAIC help, I have assumed that it only was for lm, aov, and glm models. I gather from the following correspondence that it also works with lme models. Thomas Lumley 07:40 a.m. 28/04/03 -0700 4 Re: [R] stepAIC/lme problem (1.7.0 only) Prof Brian Ripley 04:19 p.m. 28/04/03 +0100 6 Re: [R] stepAIC/lme problem (1.7.0 only) Prof Brian Ripley 06:09 p.m. 29/04/03 +0100 6 Re: [R]
2017 Aug 22
0
boot.stepAIC fails with computed formula
The error is "the model fit failed in 50 bootstrap samples Error: non-character argument" Cheers, SOH. On 22/08/2017 17:52, Bert Gunter wrote: > Failed? What was the error message? > > Cheers, > > Bert > > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along > and sticking things into it." > -- Opus (aka
2007 Oct 19
3
Tc Filter - Port Ranges Calculate Mask Value
Hi, I need to support port ranges in tc filter rules. I know how to formulate the rule but , I am not able to understand how to calculate the mask value for a perticular range so as to segregate the port values that lie within this range . I got the following sample "tc filter add dev eth1 parent 1:1 protocol ip prio 10 u32 match ip sport 0x1ae0 0x1ff0 flowid 1:10 This rule will match all
2009 May 05
2
Stepwise logistic Regression with significance testing - stepAIC
Hello R-Users,   I have one binary dependent variable and a set of independent variables (glm(formula,…,family=”binomial”) ) and I am using the function stepAIC (“MASS”) for choosing an optimal model. However I am not sure if stepAIC considers significance properties like Likelihood ratio test and Wald test (see example below).     > y <- rbinom(30,1,0.4) > x1 <- rnorm(30) > x2
2017 Aug 22
0
boot.stepAIC fails with computed formula
OK, here's the problem. Continuing with your example: strt1 <- lm(y1 ~1, dat) strt2 <- lm(frm1,dat) > strt1 Call: lm(formula = y1 ~ 1, data = dat) Coefficients: (Intercept) 41.73 > strt2 Call: lm(formula = frm1, data = dat) Coefficients: (Intercept) 41.73 Note that the formula objects of the lm object are different: strt2 does not evaluate the formula. So
2006 May 05
1
trouble with step() and stepAIC() selecting the best model
Hello, I have some trouble using step() and stepAIC() functions. I'm predicting recruitment against several factors for different plant species using a negative binomial glm. Sometimes, summary(step(model)) or summary(stepAIC(model) does not select the best model (lowest AIC) but just stops before. For some species, step() works and stepAIC don't and in others, it's the opposite.
2003 Jul 16
1
step.lm() fails to drop {many empty 2-way factor cells} (PR#3491)
Exec. Summary: step() basically ``fails'' whereas MASS' stepAIC() does work This may not be a bug in the strictest sense, but at least something for the wish list. Unfortunately I have no time currently to investigate further myself but want to be sure this won't be forgotten: The example is using a real data set with 216 observations on 9 variables -- where we have
2017 Aug 22
4
boot.stepAIC fails with computed formula
I'm trying to use boot.stepAIC for feature selection; I need to be able to specify the name of the dependent variable programmatically, but this appear to fail: In R-Studio with MS R Open 3.4: library(bootStepAIC) #Fake data n<-200 x1 <- runif(n, -3, 3) x2 <- runif(n, -3, 3) x3 <- runif(n, -3, 3) x4 <- runif(n, -3, 3) x5 <- runif(n, -3, 3) x6 <- runif(n, -3, 3) x7
2006 Apr 07
1
how to run stepAIC starting with NULL model?
Hello, I'm trying to figure out how to run the stepAIC function starting with the NULL model. I can call the null model (e.g., lm(y ~ NULL)), but using this object in stepAIC doesn't seem to work. The objective is to calculate AICc. This can be done if stepAIC can be run starting with the NULL model; the (2p(p-1)/(n-p-1))to get AICc would be added to the final step AIC value. Can
2014 Aug 06
2
concatenación de regresiones lineales
Hola, soy nuevo en R y en esta lista de distribución, pero a ver si alguien me puede echar una mano. Tengo una matriz de datos con 1539 filas, constituida por 171 eventos distintos medidos 9 veces cada uno. Lo que quiero es, para cada evento, hacer una regresión lineal entre la variable dependiente medida 9 veces en cada evento y el tiempo, y obtener el valor de 'r' para cada evento.