similar to: help with plotting

Displaying 20 results from an estimated 600 matches similar to: "help with plotting"

2009 Sep 11
2
help with for loop
example code: P = function(whichday,columns){ y = which(pvalue[,whichday]<Pvaluetest, arr.ind=TRUE) dayarb = raw_urine[y,day1_ind] daystand = raw_urine[y,columns] meandayxx = geometricmeanRow(dayarb) meandayyy = geometricmeanRow(daystand) diff = meandayyy - meandayxx for(i in 1:nrow(diff)){ if(diff[i]>0){ #diffbig = meandayxx<meandayyy x_index[i] = which(diff[i]>0) x[i] =
2001 Oct 26
3
question about anova() output
Hello, I am getting output from anova() and summary(aov()) that depends on the order of the factors in the fitted model object, and this has me baffled. I see this dependency with the data.frame below but not with an example (table 6.4) from Montgomery's DOE book. This is with R 1.3.0 on Debian GNU-Linux. Where have I gone wrong? > centerpts run sample CH50mg 1 day1 dev126 0.56 2
2008 Jul 31
2
S 3 generic method consistency warning please help
I would like to include this in a package. The S3 methods on R CMD check says * checking S3 generic/method consistency ... WARNING window: function(x, ...) window.chron: function(data, day1, hour1, day2, hour2, ...) See section 'Generic functions and methods' of the 'Writing R Extensions' manual. I have looked and can not figure it out. This function is for convience. What
2009 Jan 21
1
finding row and column indices of date in multiple columns of a data frame
Hi, I have a data.frame SAMPLES with columns: Site Site# Season Day1 Day2 Day3 Day1, Day2, Day3 are class "Date", the other columns are numeric or factor. I have a date "mydate" that may or may not be listed in my data.frame and I need to find that out. If "mydate" is there, I want to get the number of the data.frame row where it occurs.
2010 May 21
4
indexing problem
Dear group, Here is my environment : > ls() [1] "l" "PLglobal" "Pos100415" "Pos100416" "Pos100419" "Pos100420" "position" "select" "Trad100415" "Trad100416" "Trad100419" "Trad100420" "trade" "y" With objects : > l [1]
2010 May 26
0
substitution in a function
I have the following function defined as below match.trace <- function(dfobj, distance, day1, day2) { day1 <- substitute(dfobj$day1); day1 day2 <- substitute(dfobj$day2) distance <- substitute(dfobj$distance) xx <- NULL for (i in 0:10) xx[i+1] <- with(dfobj, cor(Lag((day1-day1[1]),i), (day2-day2[1]), use='pair')) i <- match(max(xx), xx) with(dfobj, {
2007 Aug 17
1
finding the row(s) for a date in a data frame
Hi, If I have a data frame A with the following format: Day1 Day2 Day3 Day4 1 1979-11-02 1979-11-03 1979-11-04 <NA> 2 1979-12-06 <NA> <NA> <NA> 3 1979-12-13 1979-12-14 1979-12-15 1979-12-16 4 1979-12-20 <NA> <NA> <NA> And a date "1979-12-14", for
2012 Nov 01
2
Name assignment in for loop
Dear helpeRs- I'm using a for loop to create a series of models. I'm trying to assign a name to each model created, using the loop index. The loop gets stuck at the name of the model, giving the error "target of assignment expands to non-language object". The linear model runs without error; only the name is problematic. Here is the current loop syntax. The use of dat
2002 Nov 01
1
Reshape function
Can someone help me with the proper usage of the reshape function? Let's say I have a dataset with columns like this (wide format): Id Sex Group Test Day1 Day 2 Day 3... And I want to transpose this into something like this (thin): Id Sex Group Test Time Where the new column labeled time contains all the time variables (Day 1, Day 2, Day 3...) that were in the wide
2006 May 07
1
Anyone care for a braindump?
I have this problem with records that have to be alligned on end- and startdate. I came up with the following. but am not convinced that this is the best way to tackle this problem. Anyone care for a braindump? def head_to_tail # Remove days that have startdate >= self.startdate AND enddate <= self.enddate # # before after # # |=====| |=====|
2011 Nov 01
1
Counting entries to create a new table
Hi, I am an R novice and I am trying to do something that it seems should be fairly simple, but I can't quite figure it out and I must not be using the right words when I search for answers. I have a dataset with a number of individuals and observations for each day (7 possible codes plus missing data) So it looks something like this Individual A, B, C, D Day1 1,1,1,1 Day 2 1,3,4,2 Day3
2008 Jul 22
0
loop for multiple regressions
Dear all, I have the following data in excel: day1 y 1 2 3 2 3 x1 0.2 0.3 0.4 0.3 0.2 x2 7 3.4 2 8 6 day2 y 2 4 3 2 2 x1 0.4 0.5 0.3 0.3 0.2 x2 7 8 9.1 6 5 I have the following problems: first of all, when I ask R to read the file (with the package xlsReadWrite and the command read.xls) it has a problem with the fact that the left most corner is labelled the same way, so in order for it
2019 Jul 27
3
[PATCH libnbd] lib: Use symbol versions.
This patch adds support for symbol versions. It is based on what libvirt does. The generated syms file looks like: LIBNBD_1.0 { global: nbd_...; nbd_...; local: *; }; In a future stable 1.2 release, new symbols would go into a new section which would look like this: LIBNBD_1.2 { global: nbd_new_symbol; nbd_another_new_symbol; local: *; } LIBNBD_1.0; In my testing the
2007 Apr 19
4
general question about plotting multiple regression results
Hi all, I have been bumbling around with r for years now and still havent come up with a solution for plotting reliable graphs of relationships from a linear regression. Here is an example illustrating my problem 1.I do a linear regression as follows summary(lm(n.day13~n.day1+ffemale.yell+fmale.yell+fmale.chroma,data=surv)) which gives some nice sig. results Coefficients:
2009 Jun 01
1
Reshaping Data
Hi, i did a mistake with my first post. I have to reshape data from this matrix: id x1 x2 x3 x4 day1 day2 day3 day4 day5 day6 day7 day8 day9 1 0.129 0.797 0.231 0.615 4 4 1 1 1 1 3 3 3 2 0.420 0.376 0.501 0.282 4 4 4 4 5 4 2 5 5 3 0.377 0.486
2006 May 31
0
Ruby on Rails Workshop in Kansas City !
Ruby on Rails Workshop ------------------------------------ Kansas City Ruby User''s Group (http://kcrug.org/) proudly presents the first "Ruby on Rails Workshop" for those eager to get started into Ruby on Rails. This one-and-half-day workshop will offer a quick introduction to Ruby and the Ruby on Rails web application framework. Sponsored by Reevik, Inc., it will
2013 Jan 17
1
plotting from dataframes
thanks to your guys help I am closer to solving my problem but I have some small problem. So let's say I start with >data number day hour 1 17 10 2 17 11 3 17 6 4 18 4 5 18 10 6 19 8 7 19 8 I want to split to odd days, which I am able to do, I call this object frames, which looks like: > frames $`1` c1 day1 hour1 1 1 17 10 2 2 17 11 3 3 17 6 $`2` c1 day1
2012 May 21
1
fda modeling
Dear friends - We have 25 rats, 14 of these subjected to partial removal of kidney tissue, 11 to sham operation, and then followed for 6 weeks. So far we have data on 26 urine metabolites measured by NMR 7 times during the observation. I have smoothed the measurements by b.splines in fda including a roughness penalty, and inspecting the mean curves for nephrectomized and sham animals indicate
2012 Mar 15
1
Bar graph with 2 Y axis
Dear R users,   I need to draw a barplot with 2 Y axis. I have 3 days each of wich having 2 groups (and error bar for each of them). The height of the 3rd day is too tall compared to others. That's why I have to use a second Y axis for that. I am using  "barplot2" function of "gplots" library (to be able to add error bars as well). Data and  codes currently I am using is
2010 Jul 18
4
Question from day2 beginner
Hello, I just started learning R and have a very basic question: When I try ar model and extract residuals it returns Null. Could someone explain what's going on here? Does that mean the model is null? But it seems residual has a length=# observation of the original series according to the model summary. I am learning it by myself and have no one to ask here so please allow me to ask this