Displaying 20 results from an estimated 600 matches similar to: "help with plotting"
2009 Sep 11
2
help with for loop
example code:
P = function(whichday,columns){
y = which(pvalue[,whichday]<Pvaluetest, arr.ind=TRUE)
dayarb = raw_urine[y,day1_ind]
daystand = raw_urine[y,columns]
meandayxx = geometricmeanRow(dayarb)
meandayyy = geometricmeanRow(daystand)
diff = meandayyy - meandayxx
for(i in 1:nrow(diff)){
if(diff[i]>0){
#diffbig = meandayxx<meandayyy
x_index[i] = which(diff[i]>0)
x[i] =
2001 Oct 26
3
question about anova() output
Hello,
I am getting output from anova() and summary(aov()) that depends on the
order of the factors in the fitted model object, and this has me baffled. I
see this dependency with the data.frame below but not with an example (table
6.4) from Montgomery's DOE book. This is with R 1.3.0 on Debian GNU-Linux.
Where have I gone wrong?
> centerpts
run sample CH50mg
1 day1 dev126 0.56
2
2008 Jul 31
2
S 3 generic method consistency warning please help
I would like to include this in a package. The S3 methods on R CMD check
says
* checking S3 generic/method consistency ... WARNING
window:
function(x, ...)
window.chron:
function(data, day1, hour1, day2, hour2, ...)
See section 'Generic functions and methods' of the 'Writing R Extensions'
manual.
I have looked and can not figure it out. This function is for convience.
What
2009 Jan 21
1
finding row and column indices of date in multiple columns of a data frame
Hi,
I have a data.frame SAMPLES with columns:
Site Site# Season Day1 Day2 Day3
Day1, Day2, Day3 are class "Date", the other columns are numeric or
factor.
I have a date "mydate" that may or may not be listed in my data.frame
and I need to find that out.
If "mydate" is there, I want to get the number of the data.frame row
where it occurs.
2010 May 21
4
indexing problem
Dear group,
Here is my environment :
> ls()
[1] "l" "PLglobal" "Pos100415" "Pos100416" "Pos100419"
"Pos100420" "position" "select" "Trad100415" "Trad100416"
"Trad100419" "Trad100420" "trade" "y"
With objects :
> l
[1]
2010 May 26
0
substitution in a function
I have the following function defined as below
match.trace <- function(dfobj, distance, day1, day2) {
day1 <- substitute(dfobj$day1); day1
day2 <- substitute(dfobj$day2)
distance <- substitute(dfobj$distance)
xx <- NULL
for (i in 0:10) xx[i+1] <- with(dfobj,
cor(Lag((day1-day1[1]),i), (day2-day2[1]), use='pair'))
i <- match(max(xx), xx)
with(dfobj, {
2007 Aug 17
1
finding the row(s) for a date in a data frame
Hi,
If I have a data frame A with the following format:
Day1 Day2 Day3 Day4
1 1979-11-02 1979-11-03 1979-11-04 <NA>
2 1979-12-06 <NA> <NA> <NA>
3 1979-12-13 1979-12-14 1979-12-15 1979-12-16
4 1979-12-20 <NA> <NA> <NA>
And a date "1979-12-14", for
2012 Nov 01
2
Name assignment in for loop
Dear helpeRs-
I'm using a for loop to create a series of models.
I'm trying to assign a name to each model created,
using the loop index. The loop gets stuck at the name
of the model, giving the error "target of assignment
expands to non-language object". The linear model runs
without error; only the name is problematic.
Here is the current loop syntax. The use of dat
2002 Nov 01
1
Reshape function
Can someone help me with the proper usage of the
reshape function?
Let's say I have a dataset with columns like this
(wide format):
Id Sex Group Test Day1 Day 2 Day 3...
And I want to transpose this into something like this
(thin):
Id Sex Group Test Time
Where the new column labeled time contains all the
time variables (Day 1, Day 2, Day 3...) that were in
the wide
2006 May 07
1
Anyone care for a braindump?
I have this problem with records that have to be alligned on end- and
startdate. I came up with the following. but am not convinced that this
is the best way to tackle this problem. Anyone care for a braindump?
def head_to_tail
# Remove days that have startdate >= self.startdate AND enddate <=
self.enddate
#
# before after
#
# |=====| |=====|
2011 Nov 01
1
Counting entries to create a new table
Hi,
I am an R novice and I am trying to do something that it seems should be fairly simple, but I can't quite figure it out and I must not be using the right words when I search for answers.
I have a dataset with a number of individuals and observations for each day (7 possible codes plus missing data)
So it looks something like this
Individual A, B, C, D
Day1 1,1,1,1
Day 2 1,3,4,2
Day3
2008 Jul 22
0
loop for multiple regressions
Dear all,
I have the following data in excel:
day1 y 1 2 3 2 3 x1 0.2 0.3 0.4 0.3 0.2 x2 7 3.4 2 8 6 day2 y 2 4 3
2 2 x1 0.4 0.5 0.3 0.3 0.2 x2 7 8 9.1 6 5
I have the following problems:
first of all, when I ask R to read the file (with the package xlsReadWrite
and the command read.xls) it has a problem with the fact that the left most
corner is labelled the same way, so in order for it
2019 Jul 27
3
[PATCH libnbd] lib: Use symbol versions.
This patch adds support for symbol versions. It is based on what
libvirt does.
The generated syms file looks like:
LIBNBD_1.0 {
global:
nbd_...;
nbd_...;
local: *;
};
In a future stable 1.2 release, new symbols would go into a new
section which would look like this:
LIBNBD_1.2 {
global:
nbd_new_symbol;
nbd_another_new_symbol;
local: *;
} LIBNBD_1.0;
In my testing the
2007 Apr 19
4
general question about plotting multiple regression results
Hi all,
I have been bumbling around with r for years now and still havent come up
with a solution for plotting reliable graphs of relationships from a
linear regression.
Here is an example illustrating my problem
1.I do a linear regression as follows
summary(lm(n.day13~n.day1+ffemale.yell+fmale.yell+fmale.chroma,data=surv))
which gives some nice sig. results
Coefficients:
2009 Jun 01
1
Reshaping Data
Hi,
i did a mistake with my first post.
I have to reshape data from this matrix:
id x1 x2 x3 x4 day1 day2 day3 day4 day5 day6 day7 day8 day9
1 0.129 0.797 0.231 0.615 4 4 1 1 1 1 3 3 3
2 0.420 0.376 0.501 0.282 4 4 4 4 5 4 2 5 5
3 0.377 0.486
2006 May 31
0
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Sponsored by Reevik, Inc., it will
2013 Jan 17
1
plotting from dataframes
thanks to your guys help I am closer to solving my problem but I have some
small problem. So let's say I start with
>data
number day hour
1 17 10
2 17 11
3 17 6
4 18 4
5 18 10
6 19 8
7 19 8
I want to split to odd days, which I am able to do, I call this object
frames, which looks like:
> frames
$`1`
c1 day1 hour1
1 1 17 10
2 2 17 11
3 3 17 6
$`2`
c1 day1
2012 May 21
1
fda modeling
Dear friends - We have 25 rats, 14 of these subjected to partial removal
of kidney tissue, 11 to sham operation, and then followed for 6 weeks.
So far we have data on 26 urine metabolites measured by NMR 7 times
during the observation. I have smoothed the measurements by b.splines in
fda including a roughness penalty, and inspecting the mean curves for
nephrectomized and sham animals indicate
2012 Mar 15
1
Bar graph with 2 Y axis
Dear R users,
I need to draw a barplot with 2 Y axis. I have 3 days each of wich having 2 groups (and error bar for each of them). The height of the 3rd day is too tall compared to others. That's why I have to use a second Y axis for that. I am using "barplot2" function of "gplots" library (to be able to add error bars as well). Data and codes currently I am using is
2010 Jul 18
4
Question from day2 beginner
Hello, I just started learning R and have a very basic question:
When I try ar model and extract residuals it returns Null. Could someone
explain what's going on here? Does that mean the model is null? But it
seems residual has a length=# observation of the original series according
to the model summary. I am learning it by myself and have no one to ask
here so please allow me to ask this