similar to: find numbers in a line with letters

Hello, Newbie question: how do you capture groups in a regexp in R? Let's say I have txt="blah blah start=20080101 end=20090224". I'd like to get the two dates start and end. In Perl, one would say: my ($start,$end) = ($txt =~ /start=(\d{8}).*end=(\d{8})/); I've tried: txt <- "blah blah start=20080101 end=20090224" m <-

> grep("f[0-9]+=", "f1=5,f22=3,", value = T) [1] "f1=5,f22=3," How do I make the line output c("f1", "f22") instead? (Actually, c(1,22) would be even better). Thank you. -- View this message in context: http://r.789695.n4.nabble.com/Quick-GREP-challenge-tp2339486p2339486.html Sent from the R help mailing list archive at Nabble.com.

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20100208/52a6d080/attachment.pl>

Dear R guru: If I got a variable aaa<- "up.6.11(16)" how can I extract 16 out of the bracket? I could use substr, e.g. substr(aaa, start=1, stop=2) [1] "up" But it needs start and stop, what if my start or stop is not fixed, I just want the number inside the bracket, how can I achieve this? Many thanks yan

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

Hi, I am getting stuck over an apparently simple problem in the use of regular expressions : To collect together the first letters of the words from the Perl motto, ?There is more than one way to do it? in the following form ? TIMTOWTDI. I tried the following code : ? ##### A regex problem with the Perl motto astr<-"There is more than one way to do it" b1<-grep("\\<",

Gregexpr - extract results with lapply Hello, I need to extract sequences of three upper case letters in a string. In other words, in this string: str <-c("ABC", "this WOUld be gOOD") The result I'm looking for is ABC WOU OOD. With gregexpr, I can get the position and length of the sequences gregexpr('[A-Z]{3}',str,perl=TRUE) [[1]] [1] 1

Please consider following string: MyString <- "ABCFR34564IJVEOJC3434" Here you see that, there are 4 groups in above string. 1st and 3rd groups are for english letters and 2nd and 4th for numeric. Given a string, how can I separate out those 4 groups? Thanks for your time [[alternative HTML version deleted]]

Greetings, I have a vector of values that are a word followed by a number, e.g., x = c("Apple12","HP42","Dell91"). The goal is to split this vector into two vectors such that the first vector contains just the words and the second contains just the numbers. I cannot use strsplit (or at least I do not know how) as there is no obvious separator. I can use sub to

I need to capture matching words in a string, any ideas ? I tried using gregexpr, but it was no help. In this example, I need to capture ID23423424 and ID324234325 > s <- "sID23423424 apple pID324234325 orange"> gregexpr("ID[0-9]+", s)[[1]][1] 2 20attr(,"match.length")[1] 10 11 _________________________________________________________________

I have a vector with a long list of sentences that contain integers. I would like to extract the integers in a manner such that they are separate and manipulatable. for example: x[i] <- "sally has 20 dollars in her pocket and 3 marbles" x[i+1] <- "30 days ago john had a 400k house" all sentences are different and contain a mixture of both integers and characters. i

Hi, I am trying to do some calculations turning DMS data to decimal degrees using the formula (D+(M/60)+(S/3600)), some of the D's involve -ve numbers, the easiest way to do the calculation is to use absolute numbers then use the 'sign' function in R to change the answer back to the correct -ve or +ve, for example, if; D<--69 M<-8 S<-10 then decimal<-D+(M/60)+(S/3600)

Hello, I have a dataframe (tab separated file) which looks like the example below - two values separated by a comma, and tab separation between each of these. [,1] [,2] [,3] [ ,4] [1,] 0,1 1,3 40,10 0,0 [2,] 20,5 4,2 10,40 10,0 [3,] 0,11 1,2 120,10 0,0 I would like to calculate the percentage of the smallest number separated by the comma by: 1) summing the values e.g. for

Dear all, I would like to ask you if R has a library that can work with different GPS formats For example  I have a string of this format N50° 47.513 E006° 03.985 and I would like to convert to GPS decimal format. that means for example converting the part N50° 47.513 to 50 + 47/60 + 513/3600. Is it possible to do that with R? What is the name of such a library? I would like to thank you in

Hi All, I have a character vector with naems of cities in the us. I need to extract the number that appear after the word "New York", for example, x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20") I want the results to be 722, 20 cab I use the grep function, if so how? I appreciate your help, thanks, -- View this message in context:

Hi, I am working with a dataset for sometime and I need some help in parsing some data. There is a column called "Duration" which has data like following: 2 minutes => 120 2 min => 120 10 seconds =>10 2 hrs =>7200 2-3 minutes => 150 or 120 5 minutes (when i arrived => 300 Flyby approx 20 sec. => 20 felt like 10 mins but tim => 600 I need to convert them to

I'm new to R and very excited about its possibilities. But I'm struggling with some very simple things, probably because I haven't found the correct documentation. Here's a simple example which illustrates several of my problems. Suppose I want to have a regexp match against a string, and return all the matching substrings in a vector of strings. regexp <-

Hi there I have a string like this i want to extract 9831019 from this string i used a regular expresion \d+ by which i can only make it to see 7 and returns. This type of number(9831019) appears in any part of the string and is definitely more than 5 digits all the time and i want to give that as a condition UV7C11-F9-E1 MCS#9831019 MCS Lot #9512516" how do i go abt it Ramya -- View

I'm having a Thursday morning mental block, any suggestions on the following would be most appreciated... I have (as an example) surgery = c("d48", "d67", "dnc37", "a75", "d10", "a78", "d31", "d55", "d1") before each number part the possibilities are c("a", "d",