similar to: interesting statistics article in NYT

Hi all: Can someone advice me on how to hold the residuals Mean sq value on a string so it can be used in other calculations. I was trying something like this: Msquare<-dfr$Mean sq but fails..Thanks dfr <- read.table(textConnection("percentQ Efficiency 1.565 0.0125 1.94 0.0213 0.876 0.003736 1.027 0.006 1.536 0.0148 1.536 0.0162 2.607 0.02 1.456 0.0157 2.16 0.0103

On Wed, Jan 7, 2009 at 11:05 AM, ajay ohri <ajayohri at yahoo.com> wrote: > > FYI..not a R -Help Topic, buy I dont know which list to post discussions like this. > Regards, > Ajay > > ---------- Forwarded message ---------- > From: ajay ohri <ajayohri at yahoo.com> > Date: Wed, Jan 7, 2009 at 10:46 AM > Subject: Re: R "Threatens" SAS, According to

Is there a less cryptic way to compare three or more values? allTheSame<-c("red","red","red","red") notAllTheSame<-c(132,132,132,999) all.identical <- function(vectorToTest){ cIdentical=sum(vectorToTest %in% vectorToTest[1]) return(cIdentical==length(vectorToTest)) } all.identical(allTheSame) all.identical(notAllTheSame) Thanks in

Hi, Is there a way to efficiently replace specified indices in a string with another character? For example, if I had a vector of strings such as [1] "hellohowareyoudoing" [2] "imgoodhowareyou" [3] "goodandyou" [4] "yesimgoodijusttoldyou" [5] "ohyesthatsright" and had a list of positions that I want to replace with the character "-"

Hello--I'm doing a simple crosstab using dcast: rawfreq <- dcast(nh11brfs, race3~CHCCOPD, length) with the results race3 Yes No NA 1 White non-Hispanic 446 5473 21 2 Other non-Hispanic 29 211 0 3 Hispanic 6 81 1 4 <NA> 10 83 1 How would I modify this call to exclude all missing values; that is, to obtain race3

>>>>> Evan Cortens <ecortens at mtroyal.ca> >>>>> on Thu, 17 Nov 2016 15:51:03 -0700 writes: > I wonder if this could be related to the issue that I > submitted to bugzilla about two months ago? ( > https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=17159) > That is to say, could it be that it's treating the first >

The packages "readxl" and "haven" (and possibly others) no longer access files on shared network drives. The problem appears to be in the normalizePath() function. The file can be read from a local drive or by functions that don't call normalizePath(). The error thrown is Error: path[1]="\\Hzndhhsvf2/data/OCPH/EPI/BHSDM/Group/17.xls": The system cannot find the

I found this as well. At our institution, our home directories are on network shares that are mapped to local drives. The default, it appears, is to set the location for libraries (etc) to the network share name (//computer//share/director/a/b/user) rather than the local drive mapping (H:/). Given the issue with dir.create(), this means it's impossible to install packages (since it tries to

Hi Thomas, Glad to hear the suggestion helped, and that switching to a `data.table` approach reduced the processing time and memory overhead?15 minutes for one of the smaller datasets is certainly better! Sounds like the adjustments you devised, especially keeping the multicore approach for `make_clean_names()` and ensuring that `ID_Key` values remain intact, were the missing components you

My data frame consists of character variables, factors, and proportions, something like c1 <- c("A", "B", "C", "C") c2 <- factor(c(1, 1, 2, 2), labels = c("Y","N")) x <- c(0.5234, 0.6919, 0.2307, 0.1160) y <- c(0.9251, 0.7616, 0.3624, 0.4462) df <- data.frame(c1, c2, x, y) pct <- function(x) round(100*x, 1) I want to

Help ! I am running rsync as a service on w2k successfully using the patch from http://v.iki.fi/~vherva/cygwin-rsync/ I would like to connect to the windows machine from Linux, to automatically backup the windows machine without user intervention. I understand that there are network problems using the native rsync transport under windows. How do I setup ssh with a w2k server? I have the ssh

How is the server configured to handle memory distribution for individual users. I see it has over 700GB of total system memory, but how much can be assigned it each individual user? AAgain - just curious, and wondering how much memory was assigned to your instance when you were running R. regards, Gregg On Wednesday, December 11th, 2024 at 9:49 AM, Deramus, Thomas Patrick <tderamus at

Hi Gregg. Just wanted to follow up on the solution you proposed. I had to make some adjustments to get exactly what I wanted, but it works, and takes about 15 minutes on our server configuration: temp <- ??????open_dataset( ????????????sources = input_files, ????????????format = 'csv', ????????????unify_schema = TRUE, ????????????col_types = schema( ????????????"ID_Key"

I worked on some ad data before and I found NYT article very biaised and not far from a fraud... Anyone knows if they got money from a - company - to play 'R'? Check out the title: R U Ready for R? Seems to me this title was stolen from XLSolutions www.xlsolutions-corp.com and they never mentioned XLSolutions in the article! They mentioned commercial R....never mentioned

It's Redhat Enterprise Linux 9 Specifically: OS Information: NAME="Red Hat Enterprise Linux" VERSION="9.3 (Plow)" ID="rhel" ID_LIKE="fedora" VERSION_ID="9.3" PLATFORM_ID="platform:el9" PRETTY_NAME="Red Hat Enterprise Linux 9.3 (Plow)" ANSI_COLOR="0;31" LOGO="fedora-logo-icon"

Readers of this list might be interested in the following article in the New York Times and might find amusing the notion that "Some people familiar with R describe it as a supercharged version of Microsoft's Excel spreadsheet software...". http://www.nytimes.com/2009/01/07/technology/business-computing/07progra m.html?_r=1&ref=technology Art

Dear R community I am using the gee package to run logistics regression on paired cases from a panel sample. We are getting request from a reviewer to use sample weights to account for different level of attrition. After searching the documentation I am unable to find a way to incorporate sample weights into the gee formula. I found a way to incorporate precision weight but I understand that I

Hello, I have a large matrix (data), in which there is a column offerid. The values are numbers (lets say 1:5) There is another vector (idnew), which contains some of the offerids and many more (3:10). I want a subset of the matrix wiith only those rows, which match the criteria of the vector. How can I make it work? Thanks! -- View this message in context:

I am trying to install R-1.9.1 on an alpha (Tru64 unix) platform. I had no problem previously installing R-1.4.0, but cannot get the new installation to work. First I ran "configure" specifying an alternate installation directory: ./configure --prefix=/appl/R-1.9.1 then ran "make" (note that this is NOT gmake, which may make the difference). The error message I

I am trying to install R-1.9.1 on an alpha (Tru64 unix) platform. I had no problem previously installing R-1.4.0, but cannot get the new installation to work. First I ran "configure" specifying an alternate installation directory: ./configure --prefix=/appl/R-1.9.1 then ran "make" (note that this is NOT gmake, which may make the difference). The error message I